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Noly Frun Tulow . tho plurtuso "Iitst oclaut" Hen rzion ot Amaa Wl Kroitet (htn "I F Fubku Ca {els MleWil Jefav teA Alnki iutegeal the Kiven !"...

Question

Noly Frun Tulow . tho plurtuso "Iitst oclaut" Hen rzion ot Amaa Wl Kroitet (htn "I F Fubku Ca {els MleWil Jefav teA Alnki iutegeal the Kiven !"xiotMa #cIThe %xion tlwe Iirst uctant btwrvn tmw splcter ccutcrel the origin: Que o Talius abdOl' Laclius

Noly Frun Tulow . tho plurtuso "Iitst oclaut" Hen rzion ot Amaa Wl Kroitet (htn "I F Fubku Ca {els MleWil Jefav teA Alnki iutegeal the Kiven !"xiot Ma #cI The %xion tlwe Iirst uctant btwrvn tmw splcter ccutcrel the origin: Que o Talius abdOl' Laclius



Answers

$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COO} \underset{\text { red } \mathrm{P}}{\stackrel{\mathrm{Cl}_{2}}{\longrightarrow}} \mathrm{A} \stackrel{\mathrm{alc} \mathrm{KOH}}{\longrightarrow} \mathrm{B}$ What is $\mathrm{B} ?$ (a) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHO}$ (b) $\mathrm{ClCH}_{2} \mathrm{CH}_{2} \mathrm{COOH}$ (c) $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCl}$ (d) $\mathrm{CH}_{2}=\mathrm{CHCOOH}$

In this problem, in one side, I'm writing the hybridization and in one side I'm writing the name. So just look at it carefully. N. O to death. N. O to death eight sp hybridized vial Annual three Egypt SP two hybridized it and energy for this age as we do hybrid, I did so according to the option in this problem. Therefore, Option B. EG, correct answer. Well, this problem. Option B. Correct answer for this problem.

In this problem I can write the reaction and CST CH two managed to in perchance of action or two 0-5° integrate will give this compound CS three CH 20 H. And this component to denso. PBL three will give CST CH two beyond and this compound in pageants of GCN we'll give CST CH two M. C. And this component presence of AL I am at full well finally give CST CH two NHCS three. This is compounded by this is component so according to the option, option C it correct here, option siege, correct answer.

Is the pair of its salts is expected to have same collect in their freshly prepared a quick solution. Okay, So We have VOCL two and secondly, see you theory Cuz here to have plus twisted VOCI do have plus four step. So having a chronic conclusion that is reliever you could have 39 so one electron and period they are colorful In the rest of the molecule. CUCL two 26 to be named three d 6 half full electron pair would have won the compared so they will not have them. Hello, the same and electron will have same color here is the correct option.

In this problem, the yellow solution yellow solution, which age I need to see R 04 on reaction will give us yellow PPT and the yellow PPT here. Age B b CR 04. Therefore, according to the option option C. H, correct answer for this problem, Option C. Each correct answer for this problem, I hope you understand the the action of this problem.


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