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Range Question Question S from 7) (9 (s your t Gicerar towestt on the the Hz 01 blue pitch your Maximum line of your highest Hz. 1 Phonationa lowest Hz, highest whi...

Question

Range Question Question S from 7) (9 (s your t Gicerar towestt on the the Hz 01 blue pitch your Maximum line of your highest Hz. 1 Phonationa lowest Hz, highest which frequency Frequency sound you just Record Robgained your above:) highest frequency Hz: L

range Question Question S from 7) (9 (s your t Gicerar towestt on the the Hz 01 blue pitch your Maximum line of your highest Hz. 1 Phonationa lowest Hz, highest which frequency Frequency sound you just Record Robgained your above:) highest frequency Hz: L



Answers

Consider three notes: 220 Hz, 440 Hz, and 660 Hz. Rank them from highest to lowest for

a. pitch.
b. frequency.
c. wavelength.

In this question, we are given F one goes 200 hertz after he goes 2000. Hertz actually goes to 10,000 hertz. We want to rank number one. Number 23 from largest to smallest. The solution. Okay, we'll be using equals two f Lunda. Okay, so lambda is equal to be over Earth. And since b is constant, um, since we is constant, the speed of sound Mhm. So Ah, Lambda is greatest when f is smallest. Okay? Which means that their ranking you have from largest to smallest under one screener than love to square than from the tree. Okay, Right. So this is the answer.

So frequency off a note. One octave above 10,000 is 200,000 hearts. Then the brick and the frequency off two octaves above 10,000 is 4000 herds. So let me write down those. So this is one octave higher. 4000 days, two octaves higher, then one octave below 1000 hertz is 500 hertz. So this is one octave below and finally, two octaves below 1000 is to 50 hertz. So this is two octaves below. Thank you.

So to get the beat frequencies, we just have to take the difference of frequencies. So for a this is 1 36 minus 1 32 which is four hearts for be these differences 2 64 minus 2 58 herds, which is six hertz for part C. The difference is 5 28 minus by 31 which is three hearts. And finally, for the the difference is 1056 minus 1058. It is two hearts. So now every rank from higher too low lower will have be to be the highest. Then we'll have a then see followed by gate. Thanks.

Hello students in this question. The frequency of the highest note on the piano, it is equal to if not equals to 4186 3rd. So for the part we have to calculate how many harmonics that is. A small end of that note can be here. So the maximum frequency or the largest frequency that can be heard by us that is humans is £20,000. So the number of harmonics will be F M. D, whereby F O. So F M is 20,000 words whereby 4186 hertz. So from here and will be equal to four point double seven. So here we can take only whole numbers, so and from here is equal to four. So this become the answer for the part eight. Okay, now solving for the part B in which we have to calculate the number of harmonics again of that note, one octave below it, we can hear. So for this problem, the Frequency F one that is one octave below so it will be equals 2-093 herds. So the number of harmonics will be FMD, whereby F one so F M is maximum frequency that can be heard by us. That is 20,000, divide by 2093 So from here and is equal to nine point double five surrounding off to the whole number, so and it is equal to nine. So this becomes the answer for the part of the of the problem. Okay, thank you.


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