5

Determine Detetmine the force the force H of the hethrusa Statewt Suate whether reachm each member merbet in tension tension or compression: 1LSm...

Question

Determine Detetmine the force the force H of the hethrusa Statewt Suate whether reachm each member merbet in tension tension or compression: 1LSm

Determine Detetmine the force the force H of the hethrusa Statewt Suate whether reachm each member merbet in tension tension or compression: 1 LSm



Answers

Determine the force in members $C D, H I,$ and $C H$ of the truss, and state if the members are in tension or compression.

In this case, we need toe right. The values for the force is in my members H I J. If I am the eve. So we need to calculate force F h I for us effort. If I and then the fourth set f ive in order to tell Claire these forces, we need to apply the moment equations off program about point at and some other points. So let's start by writing that moment equations about point and for which we can white plus sigma off m A. So this is the net talk about point our moment about point, and this should be calls to zero for the body, which is in the program. So from here we can write energy, which is the force about point that point G into 2 m minus four Newton in tow. 2 m minus five. Mutant into phone meter minus in Newtown in tow, at meter, minus six. New done into Tell me toe So this is equal to zero. From here we can write the value for this energy as n G is equals to 12.67 multiplied by journalists power three Newton or it can be written as A and G is supposed to 12.7 multiple away. Generous Part three Newton. Are we considered? This energy is equals to 12.7 kilometers. Now let's said rather diagram for the other moments. Now, applying the moment equations for this diagram. At point I we can write Theis Plus Sigma Am I use equals two zero. So from here we can write, uh, 12.6 hour Nugent W Newton into 4 m yeah, minus six Newtown into 2 m minus. If e F into 3 m is equals tau zero. So using this equation, we can write the value for this F F as f e f is equals to 12 point and to my multiplied by terrorist power three Newton. Or it can be written as, uh, if if is equals to 12.9. Clue needed. So this is the one of the forces which we need toe calculate. Applying the same moment in question at point G. We can write to this segment plus off submission off and G is equals to zero. And this implies that minus, uh, f f I sign off 64. 56.31 degree into 2 m last six. New done into to Mitya is equals to zero. So this equation will you as the value for this f f I as f f I Z equals two are 7.21 continued ID. Now the moment about point if it is written as a plus, submission off and eh physicals to zero. And this equation will imply that the 12 point 67 balloon you turned into 2 m minus F h i into three by five in tow. 2 m is equals to zero. So from here we can write the venue for this. Uh, if h I is equals to 21.1 Colluded. Please note that the 1st 22 forces which are, uh, this effort ive f f e r e f and f i f f i. These two forces our attention and the last one which is Ah, this f h I. This one is compression and of the question thing

We'll be looking at structural analysis. Uh consider this problem. We need to determine the forces in the members of the structure as well as uh nature uh to do this will apply uh what you call the method of joint uh to determine. All right, Who starts with 20 is a convenient place to start from. So of john D. G. D. Now this force coming like these and that force reasonable force into force. The forces should be coming out of the joint is a joint D. Yeah, We have these 12 new team in the question. Mhm. Yeah. These are force. Uh huh Suspect e going from 22 e. And this is F four steps with this degree from Jan di your Children to see. Now this angle is 63 14 degree. You can get the base of the financial given the question. Okay. Now, if you take assumption of forces in the horizontal direction of the Aldebaran at my loss. That's so sweet. This this see man is also sweets. Yeah. E. Of course three 0.4 degrees. You go to zero. Can call this equation one. Yeah. Okay, there will take assumption of forces. Your resume to direction. Sorry, in the vertical direction. 1st 1 is the horizontal direction. Your result of direction. Yeah, a little bit right back. Uh Under 12. Using the the models through food. Yeah. A true for the joint the sign 63 right. Yeah. 14 degree. She brought to zero. Besides, we're going to Yeah mm. All right. Well, come from the ocean to you can determine uh F. D. E. Absolutely. D. Equal to uh 13. So just making sorry that problem and solve it out. I would be that important for two for two kill a new T. Yeah, you can see that it's positive. Remember on the attention. Okay, then we can put this value into equation one to do that. You're going to arrive at F. So sweet. D. He seems to be equal to. Mhm. Man of Cisco. New team 60 little. Your team. You can see that this member is negative uh giving a negative sign. Is there? So that is a member on the yeah impression. Yeah. You see, okay, we can look at other joints. You can look at you in to see just see look at that joint. We have uh this you look like this the diagram for the joint we have a force so sorry to do indicate this other for the joints in the diagram. Okay, so in the kitchen so continue. So this is joint. See that's just indicated. See This forces going from c. two. I'll be uh remember CB From joined c. two can be We have this one f. So, as we received Cd of course this is C. E. Going to join E. All right. Now, if you take submission of forces in the horizontal direction. Yeah. Yeah. Mhm. We would arrive at minus F. South street city. Yeah. Plus F. Saw streets Cd the equal to zero. So that when you saw this out you don't have s so street to yeah C. B. Because the city is already six clue new team. Cisco unity. So they are equally forces are equal. So I don't know how uh It will be -6. Your new team. Okay so the force is on the compression. Sorry the members under compression. Remember CBD kids understand kids as a Mitchell. You can also from inspection you will see that uh force the actual the C. E. zero. The mandatory falls. There is zero because the member is in between the joint where it is coming up from the sea between to colonia. Our members and the best on our force or national company wasn't true. So you can see as of the C. E. C. Zero. Mhm. Okay. Then can continue to look at joint E. Joint E. Yeah. To discover that we have a force. Okay I force this how it falls. This hardly fought. The forces looked like and it doesn't look like okay you know. Okay this is obsessed with E. D. That's it E. G. Okay. This is so sweet E. B. Mhm. And this is F. Sunscreen. Easy good. Okay Know this angle is 26. This angle is 26.6 degree. Just figure it out from there can be given any This is 45 degree. Okay. All right. When you take sumption of forces terrorism in the vertical direction. Okay. Yeah you do arrive at my nose. S suspect E. B. Mhm. Because for five degree. Uh huh. So sweet E. G. Calls 26.6°. Mhm. Cost 26 26 degrees. 10 Monica. Yeah we saw these outs don't arrive. Uh Making acts of evil, celebrated formula. Yeah. I'm plugging. Have you had a body? I've been getting careful like not to arrive at A. S. A. P. D. Plug it in a half. Remember 16 point I was 16 97. Hello? New T. Okay mm. Mhm. Of course. Do not forget to apply the values given a few one of on the P. 20 diagram. So you have that one. And of course the value is a member on the compression as you can see. Given us a negative. Just tell her that I remember is under. Did you sign there? Okay then we can we can look for we can take a submission in the that in the horizontal direction. Selection of forces in the horizontal direction. If you do that. Okay. Yeah I know how minus ss with E. V. Get that kind sign. We're going to like it goes up wonderful. 45 degrees Moss. Mhm. Our source with E. D. Sign 26 point. Okay. Okay. Six degrees good minus F. So sweet E. F. Yeah. What is zero? So we solve this at and make S. Of E. F. Consulting formula putting every value that I've got to. Okay locking them in. I'm going to have it equal to you think you're muted? Can see is positive. You remember on the attention this is a positive Signed a four step. All right. So you can look at the joint joint F. G. F. If you blue dots have this force coming like this. Oh, forces are like this and call me like this. So call me like this. This is Steph From John F two. Going to G. Yes, I don't F. Uh Forces should be coming out of the joint. These on our assumption E. S. P. Why disease? Mhm. FCS with E. B. Absolutely. F more folks. Mhm. Going to be from F. To be F. B. Okay. On the these east going from have to a little bit have to eat. Absolutely. Have Okay, eat Okay. Now if we take assumption of forces sumption of forces in the mhm reason to direction we're going to arrive at minus F. So streets F. G. You know. Okay. Loss. S so sweet. F. E. Right. Mhm. Yes. Fdd Yeah. My lords. Absolutely. F. D. A. Mhm. Mhm. Okay signed 26 points design 26 16 degrees. It was zero. You can call the situation one just for that joint. I don't know. We have many equations there. Pixel mission of forces in the a political direction To be equal to zero. We are going to have minus F. So what's with F. Mhm mm. Of course. And six ones. Yeah six degree. Yeah minus F. So the F. B. It was zero. So I will sort this out. Okay, we're going to have to solve this one out. Of course. We know the value of F. B. The king is one F. F. Desultory formula for these uh particular one. Yeah. Is the question here, Can I have this one to be 20 two point seven kg newton. Mhm. Yeah. Okay negative. So just speak quarter 22 0.7 people. 22.7 27 kg muting. Remember on the compression negative. Okay, now from one we just I'm just delighted. You can just have R. F. Have you plug in this value already got taken to and have the energy to equal to It's mm 0.7 peace. This is true. What are you going? 8.0 seven kg. New team. All right. And see that this member is on the tensions that nature. Okay, now we can just consider uh b look at you and be have this force coming down like this. Okay, sorry, So I'm going with some comments. Yes. Coming now. Yeah, I'm enjoying it. Of the Okay, so call me like these forces should be going up the joint This angle is 45°. use the information given in the Diagram This forces F. So sweet B. E. These forces have so sweet Bc. Okay, this is F. Socially be it. And this is absolutely the of now we can take sumption of forces in the vertical direction. Okay. We're going to arrive at -8. Hello sticks mm Most F. I saw three BF. Yeah. Yeah. Right. Yeah. Plus mm. Social E. Yeah. Okay. Using a diagram for the joint. Yeah Signed 45°. Usually that. Yeah. Yeah because you will solve this. Are they gonna have I'm plugging in uh S. A. V. E. It was the happiness of BF. He has to be equal to yeah. Okay. Okay. Mhm. Absolutely beat health. Quarter 20 kg new team kill routine. Remember on the attention and nazis positive to remember on attention. Okay then we have we can just take submission of forces in the region to direction. If we do that. 40 we're going to arrive at my nose. F. Social. B. A. Mhm. Mhm. Okay. Mhm. E. A loss F. So cbc. Yeah mm. Yeah. Beautiful. Thank you. Lost episode streets. B. E. Mhm. Okay sign. Sorry because of course of course yeah. Yeah. For the five degree that every year but not close the sea has every busy close F. D. He Cost 45 degree. Yeah Is equal to zero. Now we will solve this out and make F. B. E. So be a deserved a formula and plugging every other values that are known. Yeah. For other parameters than plugging their values They want to arrive at 18. Yeah. Kill a new team considered it's negative. So it's supposed to 18. What? Kill a new team? Okay. Mhm. A member on the compression. So these are the forces among the forces in the members, as well as their nature.

We're looking at structural analysis. Okay, consider the problem where we need to become my uh the magnitude of the forces in the member of this structure as well as their nature uh to solve this problem. Who need to apply the method of joints. But before that we need to determine the supporter uh reactions who takes so much in a moment. Okay. So much movement about a. Mhm. Mhm. Quarter zero. Mhm. Who have you do that? You're going to arrive at Almost eight times 8. Lost our E. R. Associate with reaction at E. Okay. Comes four. It was zero. You see a little half uh as it. Oh is it? Yeah. Mhm. Each time speaks, it's just it's okay. So, we're gonna have our e the reaction I eat to be equal to. Uh huh. It's still a new T. Okay, so, you can also look at reality. Take consumption of uh upward and down forces. Okay, Political forces, you are going to arrive at your reaction at D. Two equal to it is a new team. Sorry, reaction at the reaction arts. He is here 16 km. Use testicular beauty 16. Okay. And when you saw this like a little All right, but a new team. Now, we can look consider the joints. Let's look at joint uh joint A that wouldn't have uh forces. Now, we're only forces to be going out of the joint. This is joint A. For those that are coming for several that are coming in naturally. So this time This is for 50 60°. So use your the information given him being any question to become mind answers for us. E. It was never E. Okay, this one is this force going this direction. This is for A B. Going from point A. To B. E. So if we take assumption of forces in the the political direction. Yeah. Zero little arrive at F. So sweet A. D. A. Yeah. Mhm. So he will be it. Okay. Loss. S Afridi the uh sign and put it. Sorry sorry. A have some street A. B. Okay. Yeah. Yeah. Yeah. 5 60 degree. Okay. Mhm. Quarter zero. So in some of these ads on behalf so sweet baby, she's not forced to be equal to and was 9.249-4 kilo Newton. Of course this is a member. She was 9.24 kill a new team going for remember wanda compression you can see because of the negative sign is telling remember on our cooperation. Okay then we can take assumption of forces. Yeah. The assumption of forces in the horizontal direction. Yeah. We want to just now let's put a rush on what? A. Zero. Yeah, I'm going to arrive at FT. Started E. Yeah. Plus F. A. B. Causes the degree. Cool. Yeah. Oh 60 degrees 60. Mm. So I saw these ads of course you already know sort of A B. Force F. A B. Going to that member. Maybe you already know needs. So so you're going to arrive at S. E. You called people. Yeah. E. Yeah. I love money. But that's what the game B. The ram at least equal to 4.62 4.6. Thank you. two kg newton. Consider this member is under tension. Okay? Can also consider joint joint. Mhm. B. If you do that, you're gonna have the diagram who look like this. Yeah. Oh, this is a 60° based on the information given. You can figure that out. Yeah. Yeah. This is our source. Sweet B. See going from 20 to see this is absolutely speed. Yeah. Force. Okay. Came from 1st from Joint B. two E. Okay, this is F. So it would be a. Yeah. Yeah. Take some action of forces in the horizontal direction. Okay, assumption of forces in these sorry, the vertical direction to equal to zero. We're going to arrive at minus F. Yeah. Something be it people. Yeah. Be a science 60 mm. Since 16 60 degrees member. Okay, my nose. If the E. Okay. Okay, 60 degrees mm hmm. Quarter zero. Please stop this out. You're going to arrive. But F. B. B. So it should be easy to be equal to Myers S. O. B. I remember wanting to be a. So what you do dogs to give you Yeah. To eat what to 9.2 to fuckin um You team. Okay. Remember on attention. Mhm. Can go further and look at some exotic submission of forces with us and join in the no yeah, result of direction. Yeah. For the zero. You do that. You're going to have uh All right. About milo Steph. Mhm. Mhm. Mhm. You know, mm. And so ST B. C. Yeah. Sorry, the costs. Mhm mm. Yeah. Oh, 60 degrees. Okay. Anything like that? Thank you. Mhm. Yeah, cost 60 degrees. Mhm. Yeah. Most ever. Mhm. So ST B. E. host 60° 16°. Mhm. Most of for for B. C. Yeah, equal to zero. When you saw this art, you're going to arrive at F plugging values that have been gotten already into that here here in this equation, you get a source with BC Equal to -9.2, 4 months. 9.24. Yeah kilo newton. Yeah. Later's all that force is the member is under. Okay, compressive force. It's under compression. That's what I love. Then. We can also look at joint C. If you look at joint C. Mhm. We're going to arrive at this diagram. Mhm. Mhm. Mhm. 60 degrees. Mhm. Mhm. Yeah. This is 60° as well. Using the information given in the Dia ground joints should be going out of the joint. Okay. This is john C. This is F. So sweet. C. B. Came from the sea Toby. Okay. Okay. This is absolutely hcG. You can see to eat and this is F. South Street E. D. Um So you see the cd cd. Mhm. Yeah. Yeah. Well, C. To D. It. So we'll take submission of forces in the the minister. Let's go direction reporter Zero. We arrived at Milos. Uh So sweet uh C. E. Signs 60 degree mhm minus L. Surface. So you see A. D. C. D. Side. Yeah. Yeah 60 degree. Mm. Get the report zero. Mhm. Okay. Okay. We sort this out lulu have F. So you see the mhm. To be equal to F. My most earth such receive E. Therefore, yeah. You can take assumption of forces in the tourism too. Consider some of force formation of forces. Okay. The horizontal direction as well. You're going to arrive at my nose. S. A. B. C. E. Yes, consisted degree. Mhm. That call 60 degrees. Oh plus F. Most earth. Okay so the Cd consisted degree I call it, I don't think. Mhm. Look at that. Mhm. 60 degrees. Yeah. Yeah minus F. Sub receiving absolutely C. B. So all we need to do okay is to uh solve uh question. Okay. Yeah somebody quits on From one. We can call this 1 1. Okay this equation I will have here, you can call these two yeah two who served him. They don't arrive at Absolutely. C. E. Stop them plugging all the relevant values into them. So we're gonna however, S. R. C. E. To be equal to Mhm. Nine point 24. Mhm. The community mm. A lot of information and the plugging have been good. It's just plug them in your course. You sign open. you're going to have that one and you can see that this one is on the attention. Okay? That members on attention. The force then plug this value back into those equations. Anyone where you can get your F. C. D. There you arrive at -9- four. It's nine 124. Kill a new team. Okay, consider this member is under. I'm 1- four kg 19. Mhm. Cold. Okay. This member is on that compression you can see because of the negative sign. Yeah. Education then you can consider join. T Consider Joint D. If you look at 20 kinda like that we're going to have uh I'm sorry, something I look like these. Okay, I'm sorry. We have this force coming like this. And that is forthcoming. Like this is a horizontal force. So let's go to work horizontal. Yeah. Some colleagues putting from force F. E. During the week from Joint D. Is Argenti right? This one is going from 22. Uh see Okay. Mhm. Then we come because look, I just wanted is coming down. Yeah. Mm hmm. These are eight kN. eight kg newton. Uh huh. It's coming down at that joint. So we take submission of forces in the Mhm horizontal direction. Oh yeah that's fine with me forces in the horizontal direction. Big quarter zero that we're going to write about and before if so D. C. Okay that's okay. Called 60 degree. Mhm. You know. Mhm. Across 16 degrees melissa S. Starts with E. E. Yeah, because Sorry because you know, so when you solve these yellow the half F. Saw streets the E. Mhm. Waiting for too long. I was 4.62. It's four boy seeks to kilo newton. You can. Mhm. Yeah. 4162. Okay, pillow muting. Consider this is a member on the compression. So these are the forces in the members of the structure as well as their nature.

We're looking at structural analysis for the problem at hand will be combining the management of indicated of the forces in dedicated members as well as uh nature. Okay. To solve this problem will apply the method of joints. A good place to start from the joint. So let us look at your Earth than ever help force coming like this. I would help this one. Uh If it's a force coming down, this is a Given the problem with that. You see there it's one out of 500. Okay. And we have this force coming. I don't know. This is F source with F. G. Yeah. Okay, forces should go out naturally several that are coming in the assumption that forces you are the subject of the community naturally. Okay, so these forces are going out. All right. So if we take assumption of forces in the the horizontal direction a little uh please let's indicated this is john F Yes, call it G. F. Mhm. So I joined F. Yeah. All right. So we're going to have a F. Yeah, it's nothing if Mhm. Oh, the most so please F. G. Yeah. Of the course 3.1°. Now this angle is 3.1 way is inclined to before this inclined to that angle 253.1 degree. Now, use your the information given in the diagram. Okay, to determine that angle. Okay, we can also take assumption of forces in the vertical direction to do that, you don't have some kind of forces in the You have my 1500 loss. Yeah, that starts with F. G. Sign 7 53. Yeah then yeah. I want one degree. Yeah. Quarter zero. So we saw this this one in particular. Uh This is thank you. Making certain formula have It will be between one it 7 5.7 for muting. Yeah. Sorry sorry not 19. Mhm. It is an ivy I. Yeah. Yeah. So these are actually positive volume. Slow Member is on the. Okay so that's the nature of okay of that force. Then we can look at F. From here. You can get our absence with me. You just plug in his body that we've got to use. You push us using push on along the X. Direction. So I have to equal to 11 26 12. The and this bye baby. Yeah. No this member is on that compression. She is actually equal to 1126 point 2 3 i. D remember on the I'm pressure you. Mhm. All right. Yeah mm. So we can also look at other joints. Let's see uh take joint joint G. J. G. They will have this first country like he went out of the joint G. Yes I. J. G. Mhm. This is false. Yeah. Coming down streets. Thank you. Okay please I. M. G. And G. E. Brain transplant G. Two E. And there's this force coming. Sorry forces you go out. This is for earth. Mhm. Yeah. Half. Now this is also into 36. This is implanted. 26.9 degrees. Using information given in the diagram. Two to the to the commander. So we can look at submission of forces in the forces in the I don't know. Yeah consumption of forces in the horizontal direction. Mm I don't know how as well on this one. Yeah. Okay. Ge fish. Yeah. Using a diagram just drum loss. F. G. F. Uh Sign at 6.9. So this is G. F. Sign. Mhm. Okay. Yeah. 26.9° equal to zero. No, you can solve these. If you solve these you have your never jellyfish Putin value of F. G. And having Yeah, she's good. Okay. Doesn't mean you ever been before putting their Subsequuted and you have this one to be 112 1:26.23 and another one. Hi baby. You can see that. It's supposed to be brown music tells you like in nature the members on the attention that number. Yes. Okay. So we can look for okay, uh submission of forces in the horizontal direction. Okay. If you look at some regional forces in the sorry individual direction. Yeah. Zero. Okay. You're going to have my nose F. G. The sovereignty. So the ge my nose F sauce trees. Social E. G. The F cost to deny the cysts for 90 years To the Quarter zero. So we'll make a so pg It is also the formula I'm plugging every other value of E. F. Every other value. You haven't got the right box. Making Key to the -1 out of 500 morgan develop. Absolutely F. Yeah. Another 500 is a remember on that compressive force On a contraction so small five zero zero ivy ivy. The individual is compressed on that compression. Remember is on that compression. So you can consider joints joint E. G. E. We do that. We have these force forces like this arranges with. Yeah, we have this force F. Is a joint E. Have this force going out uh E. To G. We just want going from E. To F. This one going from E. T. O. D. Yeah. And this one is 501 out of 500 idea that joint given to Ross. Yeah. Yeah. Okay. It's going down naturally from because so if we take assumption of forces in the horizontal direction, I want to have. Yeah. Okay. My mom was F. B. D. Or S. O. B. D. My nose S. E. A. Because with a 3°. Yeah. Political elections, well there are 3.5 3.1 Degree. Yeah. Mhm. Okay. Most s. Is with bdf, most earth sorcery E have equal to zero. Now we can also look assumption of forces in the horizontal direction. Sorry, in the vertical direction. If you do to us they will arrive at E. Sorry F. E. H. Yes. Okay. Mhm. Signed with the 3.1 degree. Sorry there's a there's a force we did not indicate as a forthcoming. Yeah that's indicate ease. There's a for that to come from here to look at the diagram from the structure. Just give it. Ish. Okay. Eat a sign. Now it is inclined to 53 point 3.1 Degree. Yeah. To sign 3.1 Degree. Yeah. Y'all. Mhm. Information. Give me a question to do that. Figure out the angle. Hmm. 3.1° loss. Also streets uh E. G. My last one out of 500. She waters you. So when you saw when you solve this one you're going to arrive at big lots of it. The images certain formula before this one without her. I'm until three just plug in every other value into right boxer one night four years. Okay 700 51.48 Ivy. Consider it is positive. Remember on that tension as in the job of course with regards member. Okay so we can also look at it. You just plug in values into the same question. Okay. It's yeah. Uh Presente equation. Okay assumption of that equation. You have your your E. D. Plug in every other value. Haven't got it. So you have your essence with eating to be equal to uh 33 78. Mhm .69 Ivy. Yeah so actually it's a Member on the compression. Yeah I remember on the compression because I'm going to have a negative. Yeah. Yeah, you can. Yeah. Okay. So that the value, these are the okay, the man usually forces in the members of the structures.


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Let u = and (a) Show that i 2 @ my linear combination 0 and then the first entry ofe equal the JuIu of thie SCCOnd third entries It qay help start by recalling that line t combination o vector of the fortu Qu Show that nnd ue in te nullspace of the matrix (1 51j: Is {u,v} bsis for the nullspace of /...
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1. Evaluate the following line integral:[ = | xzydx + (x - Zy)dyover the part of the parabola y = x2 from (0,0) to (1,1).Evaluate [ = ydx + (x + 2y)dy along the Path Cl and C2 as shown The initial point is and the final point is f. Cl is parallel to X-axis, C2 is parallel to y-axis(0.0
1. Evaluate the following line integral: [ = | xzydx + (x - Zy)dy over the part of the parabola y = x2 from (0,0) to (1,1). Evaluate [ = ydx + (x + 2y)dy along the Path Cl and C2 as shown The initial point is and the final point is f. Cl is parallel to X-axis, C2 is parallel to y-axis (0.0...
5 answers
Question 15 ideal BCC metallic crystal is: Coordination number for an a) 8 b) 6 c) 12 d) Varies for different metals
Question 15 ideal BCC metallic crystal is: Coordination number for an a) 8 b) 6 c) 12 d) Varies for different metals...
5 answers
Kuntns -Nm~0 6+U 6 , Design Lavowi ReferencasDocument]DavmMailinosRcviewShareCalibr (Bod2 =ABUCcDdLcRabk CdCAaRoCcDc AaBuCcOdE: AaBb( Soa-nm HeJoino K-jltCMLS679sultseek 1)0.83 0.5 1 0.3Y = 1467.1x + 0.1668 R2 = 0.9983000050.00010.00015 0002 0.00025 0.0003 Concentration (mol/l)000350.00040.00045canadaacRopl ProWVicw
Kuntns -Nm ~0 6+U 6 , Design Lavowi Referencas Document] Davm Mailinos Rcview Share Calibr (Bod 2 = ABUCcDdLc Rabk CdC AaRoCcDc AaBuCcOdE: AaBb( Soa-nm HeJoino K-jlt CML S679 sults eek 1) 0.8 3 0.5 1 0.3 Y = 1467.1x + 0.1668 R2 = 0.9983 00005 0.0001 0.00015 0002 0.00025 0.0003 Concentration (mol/l) ...
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Queston 11Noiyrt Ansurred Marttd QUt Of 1.00Fleg queatcnThe slope of the linear function f(2) _ 5 - 3r isNone of these 6,0 40 6.03.0Qvestlon 12Notyct Hnefed Maraco out ol |,0JFleg queseicnThe half-Ille of insectlcide DDT Is 31 years. If a larmer uses 20 gm then how much will still be active after 13 years?A - 20(-3) # gm 4 = 20(-2) # gm None of these 20(3) + gm 20(2) + Em
Queston 11 Noiyrt Ansurred Marttd QUt Of 1.00 Fleg queatcn The slope of the linear function f(2) _ 5 - 3r is None of these 6,0 40 6.0 3.0 Qvestlon 12 Notyct Hnefed Maraco out ol |,0J Fleg queseicn The half-Ille of insectlcide DDT Is 31 years. If a larmer uses 20 gm then how much will still be active...
5 answers
What is the kinetic product obtained from the addition of1 = equivalent of HBr to buta-1,3-diene?Multlple Choice2-Bromo-but-+ cne3-Bromo-but-I-ene2-Bromo but-2-ene1Bromo but-Z-ene
What is the kinetic product obtained from the addition of1 = equivalent of HBr to buta-1,3-diene? Multlple Choice 2-Bromo-but-+ cne 3-Bromo-but-I-ene 2-Bromo but-2-ene 1Bromo but-Z-ene...

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