A 1.8 sample of an aqueous solution of nitric acid contains an uUnknown amount of the acid. [f26.2 mL of 0.910 M sodium hydroxide are required neutralize the nitri...

What is the molarity of a solution of nitric acid if $0.216 \mathrm{~g}$ of barium hydroxide is required to neutralize $20.00 \mathrm{~mL}$ of nitric acid?

Hello students in this question we have to calculate the concentration of nitric acid in moles per liter. Okay, moles per liter. In a simple which has a density of 1.41 g per millimeter. And mass percentage of nitric acid is equals to 69%. Okay, so we can calculate that we have given the density. So for 300 ml we can calculate the volume for the 100 grand. We can calculate the volume be so it will be equals 200 g divided by 1.41 That is equals two 70.92 million L. Okay, so number of modes can be calculated from the mass liver by molecular mass. So masses given as 69%, that is 69 g. Can be taken from 100 g. And we have given the molar mass which is equals to the 40 nitric acid. The molar masses 63. So we get a number of moles equals to 1.39 moles. Okay, so these are the number of moles in this given mass. Okay. No, we can calculate the modularity or concentration. So this concentration, this will be equals to the polarity of the solution. So it will be equals to the moles, develop a volume of the solution Manipulated by 1000. Okay, So we can right here that number of moles are 1.09 and volume is 70.9 to curb this 1000. So from here we get the concentration, it is equal to 15.37 moles per liter. So this become the answer for this problem. Okay, thank you.

To calculate the polarity of nitric acid solution. Polarity is moles per leader. We need to know the moles of nitric acid in the leaders of the nitric acid solution. The leaders of the nitric acid solution was given to us at 20 mil leaders. Or when we convert that to leaders, it'll be 200.2 leaders, but to calculate the moles of nitric acid, it is a little bit more challenging but still not too difficult. We'll start with the volume of K. O. H that was used to titrate the 20 mL solution of nitric acid. Convert those mill leaders into leaders. Then we can convert the leaders of K O H into moles of CO h using the molar ity of K o h. 00.1 moles per leader at 0.1 Moeller concentration. Then we look at the balanced chemical reaction. This is a strong acid reacting with a strong base. The stoy geometry is one toe one So one mole K o h is required for one mole h n 03 This then gives us the moles h n 03 which we can put here in the numerator to calculate Armel Arat e in the denominator, as I mentioned, that was given to us a 20 mL, which we convert to leaders, which is 200.2 leaders. We then divide these two numbers in order to get the mole arat e of the nitric acid solution at 0.2167 Moeller.

This is Chapter 18 number 44. So we're looking for a ah neutralization problem here. So we know that our volume of base is equal to 43.33 mil leaders and our polarity of base physical to 0.1000 Mueller, we know that our volume of acid is equal to 20 milliliters and I'm Alaric have asked it isn't unknown. So here we could just say that the volume of acid time similarity of acid is equal to the volume of the base times the polarity of the base because one of the moles are equal. And when you multiply similarity by a volume, you get moles. So here we just saw for unknown you get the polarity of acid is equal to the volume of the base times the polarity of the base over the volume of the acid. This you don't get here as 43.33 milliliters times your 0.10 Oh Moeller. And then you get 20.0 milliliters! Down here. Those units cancel you get polarity. So we know that the polarity of our acid is equal to 0.2167 Moeller for significant figures because all of these values have four significant figures

We're told that our solution is 70% by mass, which by definition is going to be 70 g of the nitric acid in 100 g of solution. And we want to get the polarity. So we want moles of nitric acid divided by leaders of solution. So on the top will divide by the molar mass to get the molds of nitric acid. We know that one mole of nitric acid is 63 .01g. And then on the bottom will take the 100 g of solution and the density is 1.41 Grass from ml. So one middle eater Is 1.41 g. And then since its polarity will need leaders, one leader is 1000 millimeters. So then we'll multiply and divide everything out. We have 70, divided by 63 points A one on the top And then we'll divide by 100. Yeah. And then Times 1.41 and then times 1000. That gives us 15.7 Yeah moles per liter or 15.7 moller nitric acid.