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The following mechanism has been proposed for the conversion 0f tert-J -buty[ solution: bromide tert-butyl alcohol in aqueousstepslor: (CH3kCBr (CHz)ct _step 2 fast...

Question

The following mechanism has been proposed for the conversion 0f tert-J -buty[ solution: bromide tert-butyl alcohol in aqueousstepslor: (CH3kCBr (CHz)ct _step 2 fast: (CHzhCt + OH"(CHa)COH(1) What is the equation for the overall reaction? Use the smallest integer coefficients possible: Ifa box Heato it blank. not needed,(H;C)3 CBr|HO(CH3)}COH|(2) Which species aCtS a5 catalyst? Entet fonmula. none. leave box blank:(3) Which speciesreacton intemmcdint Enter fonnula;mome leave box blank:(4) Co

The following mechanism has been proposed for the conversion 0f tert-J -buty[ solution: bromide tert-butyl alcohol in aqueous step slor: (CH3kCBr (CHz)ct _ step 2 fast: (CHzhCt + OH" (CHa)COH (1) What is the equation for the overall reaction? Use the smallest integer coefficients possible: Ifa box Heato it blank. not needed, (H;C)3 CBr| HO (CH3)}COH| (2) Which species aCtS a5 catalyst? Entet fonmula. none. leave box blank: (3) Which species reacton intemmcdint Enter fonnula; mome leave box blank: (4) Complete lhe rate Iaw ue otelal reaction that Coeee with this mechanism (Use the [orm KA]"[B]". Iner understood (su don"t write it)for m etc- ) Rate L(ty C); CBrE



Answers

The reaction between ethyl bromide $\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}\right)$
and hydroxide ion in ethyl alcohol at 330 $\mathrm{K}$ , $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}(a l c)+\mathrm{OH}^{-}(a l c) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l)+\mathrm{Br}^{-}(a l c)$ is first order each in ethyl bromide and hydroxide ion.
When $\left[\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}\right]$ is 0.0477 $\mathrm{M}$ and $\left[\mathrm{OH}^{-}\right]$ is $0.100 \mathrm{M},$ the rate of disappearance of ethyl bromide is $1.7 \times 10^{-7} \mathrm{M} / \mathrm{s}$ (a) What is the value of the rate constant? (b) What are the units of the rate constant? (c) How would the rate of disappearance of ethyl bromide change if the solution were diluted by adding an equal volume of pure ethyl alcohol to the solution?

So the first thing we need to do here is take a look at the equation that we have and balance out the equation. So we have four h b r Add to that is an equilibrium with two h two of, uh to be, uh to So we can determine the order of the reaction as follows for the decomposition. Oh h b r is fast order reaction with respect to H B R and two so we can determine the rate determining step where what we have is following h b r 02 generates h o b r. You have a choice o b r a h b r gives us two h o b r. Then we have a Chobe are at h b R gives us a chance to Oh, at b R. Two, we have equation one, two and three. Equation two and three involved the intermediate H O B r and H o P. R. To the intermediate, more reactive species. So Equation two and three are the fastest steps. So the reaction of HBR and so too is the rate determining step. No

Question is about side of your own reacting with recognition and dries it forms a compound. The organism really creative with give alcohol. After my condition prolonged treatment of alcohol but then equal amount of we will give this compound right? The structure of the embassy. Okay society, that is the sun. It is reacting with the magnesium. Then we are getting just come home and this compound is reacting with another. That man is Lord. So M. G plus carbon minus just by one will break here minus yes so minus attack on the carbon. Okay CS three Street for my nest. Mhm. Upon a certification we are getting what we will get see watch and this seriously here. No actually our reacted with this component so long building just put on it has two molecule gets eliminated then steam Positive charge here will come and three No really expensive really takes place. Every expansion takes place, vibrant expensive buildings please. Because our work is presented. Fire book then is present and they sent to the so five memory will get formed and positive Charles. Welcome here now we are management heard of this kind of them then we will get at this point. Okay thank you

In this next question, we have a three step mechanism associated with the formation of an alcohol. Here's the first step where the rate law is simply rate is equal to K. Multiplied by this concentration. We ignore the water concentration because it's constant. Actually, this is the overall reaction. The first step is this one here, which is the slow step for the rate determining step, or the rate limiting step. And because the rate law for this slow step is equal to the rate law for the overall reaction, then it is consistent. The mechanism is consistent with the rate law for the overall reaction. Water doesn't appear because the water concentration is constant. So it's essentially tied up in one of the rate constants, great constant here, so we don't need to include water here because the constant concentration of water is tied up in this rate constant. And then the third step is also fast, where the protein ated form of the alcohol becomes the deep rotated form the intermediates that are found are this one right here and this one right here. So these two are the intermediates and some of the overall react, or the sum of all the steps gives us the overall reaction so it's consistent.

Hi guys. Let's solve problems. 16.83 Water does not appear in them, Rachel, because water is used as a solvent for distraction and therefore the concentration off water is constant. Therefore it does not affect the rate and doesn't ever as direct and in the raid law Now we need to write down the rectum for each of these steps we know replies expressed in terms off for a lot of concentration off rectums place for the part of them respective coefficients. So in this case, direct inside the zone. Let's Trent on the radio. Rich was the fastest A bees. Okay, one which is going with a constant empty my mind, The concentration of the reactive, the sudden this state constantly scared too. Party step. It is three constant. Then we need to find a intermediates. We know intermediates and produced in one step and consumed in the next district. On this reaction, this species is producing the fastest and I'm zoomed in the second district and the other species this one produced in the second estate and consumed the artistic there for me is to other intimate IDs. No. Does this expression is considering consistent with the MacGuineas. The rate will expression. Now over on grade is determined by the story is distinct. And in this case, the first estate is the stress distinct. And therefore, this is the radio Germany State. The rate long on this asleep agrees with the observed Rachel with the constant Okay, is it gonna kill on? Therefore, the expression is consistent with the mechanism.


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