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9. Show the calculation of the volume of 0.987 Msolution which can be prepared using 24.6 grams of NaNOz 10. Show the calculation of the volume of 0.238 M solution ...

Question

9. Show the calculation of the volume of 0.987 Msolution which can be prepared using 24.6 grams of NaNOz 10. Show the calculation of the volume of 0.238 M solution which can be prepared using 13.4 grams of Caz(POsz:

9. Show the calculation of the volume of 0.987 Msolution which can be prepared using 24.6 grams of NaNOz 10. Show the calculation of the volume of 0.238 M solution which can be prepared using 13.4 grams of Caz(POsz:



Answers

Calculate the volume of a $23.4-\mathrm{g}$ sample of bromobenzene, density $=1.49 \mathrm{~g} / \mathrm{mL}$.

This question has two parts. In the first part of the question, we need to determine the modularity of hydrogen, phosphate or phosphoric acid Um when the mass of the phosphoric acid is given as 3.978 g and this is part of a solution Which has a volume of 185 mm. Now we know that similarity is always the unit of polarity is most per liter. So we need to determine the number of moles of phosphoric acid here and then divided by the volume in terms of liters. Right? So the number of moles of phosphoric acids, it's easy to calculate from the mass because it's just the mass divided by the molar mass. So it's going to be 0.978 crams. And then instead of the multiplying by the, sorry, dividing by the molar mass. I'm going to multiply by the reciprocal. So the monomers is 98.0 grams per mole. I'm just going to multiply them by the reciprocal. And then, so this is the number of moles of phosphoric acid. And then I need to divide that by the volume of the solution. The volume of the solution is given in terms of milliliters but similarities in terms of moles per liter. So I'm going to convert the milliliters two liter. That's a 0.185 L. And the answer here with 10 b 0.0539 mola. Right, So that's the first part of the question. In the second part of the question, they tell us that um There is um uh study my drug side solution with a concentration of 0.454 moller. And we have 11.58 mm of the solution. Question is if we use this salute solution and we neutralize the phosphoric acid, what is the volume of the phosphoric acid? That is necessary for this neutralization. So here I have written down the reaction equation but it's not balanced yet. So I need to balance it first because we will need to make use of the story geometry from this reaction equation. So I've got three sodium is on the right hand side. So I put three in front of the sodium hydroxide on the left hand side to balance this and then well that's left to is to put three year in front of the water. All right now I have my balanced equation. Question is what is the volume here? This is really awful neutralization. So what I'm going to do is um remember that we can calculate the number of moles of sodium hydroxide here from the clarity and the volume. And we know that once we have the number of moles of sodium hydroxide, we can use this together with this to a geometrical efficient uh started geometric gracia in order to calculate the number of moles off. First of all, like acid. And then it's easy to go and calculate the volume because we already have the modularity of the first forecasted according to what we calculated bus. Right? So let's go and calculate the number of moles of city of my drug site sitting my drug side number of malls zero point Because you know, 1 1 5, 8 leaders times The more clarity in terms of multiple latest 0.454 moles per liter. So this is why um I've converted the volume of sierra madre oxide to leaders so that the leaders can cancel out and I'm left with moles. Right. I'm going to do the calculation a bit later on. Next on. I need to calculate the number of malls of phosphoric assets because I need to use that in order to determine the volume. Right? So yeah, I'm gonna make use of this Tokyo metric ratio according to the psychometric coefficients in the balanced equation. Um for phosphoric acid phosphoric acid, it's 14 sodium hydroxide, it is three. So I've got a ratio year of one over three. All right now I can determine the number of moles of phosphoric acid in terms of the number of moles of Salima drug side. The number of moles off phosphoric asset. Yeah, he's equal tooth a third of the number of moles of sodium hydroxide. All right. And I know how to calculate the number of moles of sodium hydroxide. So that's easy. And then I know that the volume of phosphoric acid is equal to the ones I have. The number of moles of phosphoric acid. I can just divide by the more clarity of phosphoric acid. Right. So let's do that because I have the clarity. I've calculated it earlier on in the first step. Right? Yes. I've shown that the number of moles of Phosphoric acid is equal to a 3rd times the volume of the. What was that? Sorry? My truck side in terms of liters, 0.01158 l times the polarity Which is 0.454 moles per one liter. And that I divide by the polarity of phosphoric acid. So I can multiply by the reciprocal. So this is 0.0539 moles per liter. So, I'm just going to use the reciprocal. Yemen. I multiply Because of the division. Okay, this is equal 0.03-5 L. And if I need to give in terms of mm, it's just Multiplied by thousands. So that's three, All right, let's quickly recap here. The first part of the question asked to calculate the molar itty of phosphoric acid of a given mass in a specific volume of a solution. So I just had to go and calculate the number of moles of phosphoric acid because I already have the volume of the solution. I can then just divide the number of moles of phosphoric acid by the volume of the solution. But the volume of the solution needs to be in terms of liters. Second part of the question is about a neutralization reaction where I have the phosphoric acid with the clarity that are calculated which reacts with sodium hydroxide, the polarity and the volume of this sodium hydroxide is given. So I can calculate the number of moles of this and then use um this is to geometric ratio of sodium hydroxide too, Or phosphoric acid to 30 my drug side to calculate the number of moles of phosphoric acid in terms of the number of moles of Sunni my drug side. And from the calculate the volume of the phosphoric acid. It's just um taking the number of moles of phosphoric acid and divide that by the polarity that I've calculated in the first step of this question. And then um in the end I converted the volume in terms of leaders two ml.

Now we do problem. 50. Mhm. Okay, we have 50 here. One later contained. 41 boy, faithful friend, Abu Chemical and now two leader. You know how many grams? Good. How many grams? And they continue as you seven, 37 leader. How many grants? What chemical? Okay on now, they only your project to do significant figure. Okay. This? Yeah. Okay, because Okay. Okay. Critics. Yeah. Thank you. Okay. Okay. Yeah, she was shot for this. You have to do show this, uh, coalition Unique calculator Significance. One leader too little because that's the the captain number. So here you measure here. 737 Does a measure number. You have tow calculus if it right here, okay.

Using the balanced equation and problem 4.94. Let's calculate the mass of the sample of F. E s 04 Start by calculating the moles of every two. Plus we're told that we have 18 72 mL potassium die crow mates. Let's convert this to leaders. Convert to moles by using the mole arat e 0.1500 moles per leader and using the street geometry, one more potassium Die chrome 8 to 6 moles of F two plus using the coefficients from the balanced equation. And this works out to a 0.1685 moles of F E two plus starting from 01685 moles of F E two plus one mole of F two plus present in one more F. E s four times the molar mass of F. E s 041 mole of F. E S 04 has a mass of 1 51 91 g, and this will work out to a mouse of 2.560 g of F. E s 04 that would be required in this tight rations

So in this question, we're going to tackle the volume of substance and we're going to follow the four step method for basic steps. So first we're going to analyze. We are given first, were given the mass. We're getting the mess of two point 03 times 10 to the negative three grams when they were also given the density off. 9.133 times 10 to the negative one for centimeter cubed, which we can use as a conversion factor. So I'm gonna set it up already as a conversion factor so that one centimeter cubed will contain nine 0.1 three, three times 10 to the negative one grams grams. Now, if we so now we can convert this well, we find that our units cancel and we're left with centimeters cubed. So our final answer is zero 0.0 zero to to to so see, we executed way analyze. We found that we needed to find the volume. I can't forget the units centimeters cubed. We found the volume we needed to plan. We planned that we were gonna convert from grams zero. All right, the plan over here grams into centimeters cute and then we computed. So he multiplied. We multiplied by 1/9 0.13133 times 10 to the negative one. And now we want to check for significant figures. See, we have we have three significant figures. 123 We have four significant figures over here. By the rules of figures, we choose three. Significant. We are leave our answer and three significant figures or final answer. 0.0 zero to centimeters cubed. Now we want to evaluate. We don't have any negative number. We can't. It's not possible to have a negative density we want to make. Our units were probably cancelled out. We cancel out grams and grams and we're left with centimeters cubes. Centimeters Cube is a volume, so our answers does seem to make sense. So our final answer 0.2 times, uh, 0.2 centimeters. Cube


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