5

Fill in the blanks in the table for aqueous solutions of the compounds shown The density of the solution is in gmL. Abbreviations: m is molality. Mass % is the mass...

Question

Fill in the blanks in the table for aqueous solutions of the compounds shown The density of the solution is in gmL. Abbreviations: m is molality. Mass % is the mass percentage of the solute; Mole Frac_ Is the mole fracti on of the solute and M is molarity of the solute:Compoundfw.d. solnMassMole Frac _HCI NaOH C zH0 236.47 40.01 62.071.179[ 1.2848 1.013436.008.782959

Fill in the blanks in the table for aqueous solutions of the compounds shown The density of the solution is in gmL. Abbreviations: m is molality. Mass % is the mass percentage of the solute; Mole Frac_ Is the mole fracti on of the solute and M is molarity of the solute: Compound fw. d. soln Mass Mole Frac _ HCI NaOH C zH0 2 36.47 40.01 62.07 1.179[ 1.2848 1.0134 36.00 8.782 959



Answers

Fill in the blanks in the table. Aqueous solutions are assumed. $$\begin{array}{llll} \hline & & \text { Weight } & \text { Mole } \\ \text { Compound } & \text { Molality } & \text { Percent } & \text { Fraction } \\ \hline \mathrm{KN} 0_{3} & & 10.0 & \\ \mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H} & 0.0183 & & \\ \mathrm{H} 0 \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH} & & 18.0 & \\ \hline \end{array}$$

This question is F in for the morality, which we know is equal to the moles of solute divided by the mass of the solvent. In part a were given 2.5 molar concentration off sodium quarry with a density of 1.8 grams. Pyramid leader. First, we have to change our density over two grams per liter. Next, we just add in to our equation to get 2.3 times 10 to the negative third morality in question be were given a four point 48.2% potassium bromide solution. Find the morality we're going to need to use the moles off solution equal to percent by mass times one mall over the more massive solution. This gives us 4.5 times 10 to the negative three morality. And in this question, they found out the molar concentration of potassium Bro my in order to use for the equation

This is foam 18 from Chocking 13 and we have to find the morality. So for a we have 2.55 molar solution, okay? And a CEO. So to find the granted anything, I would have a multiply and moves by the molar mass. So give us the similarity. So usually we're gonna assume one leader. Don't assume one leader of this. Therefore the rules. It's going to be 2.55 books. Those 2.55 with one. It's a 2.55 Then you have to most apply that about the molar mass of sodium chloride strictly eight point by and a CEO sectioning. The grantor ago and 1/2. It's 149.2 grand Church. So he and chloride okay the next court, the company also give us the Green City. There's 1.8 Grand Spergel Reader, which is also equal to 10 Greeny Vanspor leader. Okay, so when we also against a serial later, this means we have going to have 1080 grams. The next player that 10 80 grams nine. It's still worth 49.2 grams and who's going to come out to be 930.8 grants. But we want this and kilograms. So in kilograms this inside by 1000 and 1.9 great kilograms, Kuzma loudly meets his molds over a kilogram. Okay, so now that we have the moles a 2.55 over it kilograms, you consult for the mill ality. So to 0.55 most over point 938 it is going to come out to be too 0.74 for the morality. Okay, four be. This time we have a percentage if 45.2% of a mass of passion bromide. And so the rest of the solvent you do 100 minus 45.2. The rest summer is gonna be your t four point, Gramps. So which means we have 0.0 life for eight killer franks. Next, we're gonna take the flight 5.2 crabs and divide that by the molar mass of potassium provide to get the holes 45 to crams over 119 grams per mole comes out to be a point three a morse. Okay. And how we can divide the most by the killer grants a point 38 most over a point Nero five or a kilograms, and it's gonna come out to be six 0.93 for the mill ality.

In this question. We're going to be looking into the morality, morality also known as solid ability. And this is going to be equal to the malls of solid divided by the mass all to solve it. And we're going to be reporting this in more a G. We're used to more clarity molar which is given in terms of the volume of the solution. So, but this time around we're just looking at the morality which is given two Kg of the sovereign. So looking at the first part of the question, the mass of The mass of one liter of solution. This is going to be equal to remember, density is equal to mass divided by volume. Therefore moses equal to density multiplied by if only. And this is going to be equal to 1.0 8g familiar liter multiplied by 1000 ml which is one little So the mass this is going to be equal to 1080 correct. Then looking at the mass of H 20. Mass of H 20. This is going to be equal to 1080 minus two point bye bye. 58 24. Yeah. What we did here, We're looking at the mass of the H two. All because you're saying number of moles is equal to must divided by the monomers. Therefore the mass of a substance is equal to the number of moles multiplied by mama. So this is why we have this expression here. So the mass of our age tour. This is going to be equal to nine 34. Yeah. And this is going to be equal to 0.934 kg. Remember we want to describe our morality in terms it's so moving on to the morality, if you're going to call them, This is going to be 2.5 moles divided by the mass of the solvent which is H 20. Which is your point 93. Cool. So this is going to be equal to 2.68. Yeah. Where this Emirates representing the more repair kg. Now moving on to the next one where we have 100 g of a solution which contains potassium bromate and a certain amount of H tool, we actually use the same approach. The number of moles of our K P. R. This is going to be equal to the mass of KBR activated by the mamas. So the masses 4 8.2 divided by the molar mass of KPR. I would use 119. And this gives us 0.405 models of KPI. Then moving on to determine the mass of H 20. The mass of H two. Or this is going to be equal to right point 5 1.8. Dreams, we want to divide this by a 1000 So that we get it in K. S. This is zero 0518. Katie is off. It's too. Therefore the morality R. M disease. The number of moles of solute 0.405 divided by the mass of the solvent, Which is open 0518 H 20. So this gives us a morality of 7.82.

Okay. So in this problem, we're working with aluminum nitrate. Why don't we go ahead and start by finding its molar mass. We'll need that. So that's 2 13:01 grams from old. Okay, so one aluminum, three nitrogen and nine oxygen's. So in the first one, we're given the mass 1.672 g. So we'll go ahead and change grams to moles using our molar mass At 7849 Time. Send a -3 moles since polarity is moles over leaders. I'm just going to take these moles and divided by leaders. Okay, 145 million liters is .145 L. And that will give us our polarity. Mhm. So in the next one, we're starting with different monograms. So 2.544 g. Again. Let's go ahead and start by changing grams to moles. We use the molar mass here. So now we've got our moles since polarity is moles over leaders. We can say that leaders is moles over polarity. So we're just gonna come over here and divide our moles, fire polarity 688 Moller. So that will give us our leaders 7073. Which will change to mill leaders because that seems to be what they're using in the table. So that's 7.073 ml. And in our final example, okay, you know that moles is more clarity. Times leaders. So we'll take the polarity which is .7-9 moller and we multiply by our leaders. Make sure use leaders. Okay? So that will give us our moles which is .652 moles. We'll just go ahead and change moles to grams. Using the mauler mass. We'll see that we have 139 g.


Similar Solved Questions

5 answers
B [6 pts]OHHO_NH2
b [6 pts] OH HO_ NH2...
5 answers
Define a relation R on the set of positive real numbers, Rt,by x Ry if,ez Prove or disprove: R is an equivalence relation on Rt
Define a relation R on the set of positive real numbers, Rt,by x Ry if,ez Prove or disprove: R is an equivalence relation on Rt...
5 answers
Given the equation y 5T0 4csc 57 I + 2The period is:
Given the equation y 5T0 4csc 57 I + 2 The period is:...
5 answers
AirN Linseed oil WaterN
Air N Linseed oil Water N...
1 answers
Find the recurrence relation and general power series solution of the form $\sum_{n=0}^{\infty} a_{n} x^{n}$ $$ y^{\prime \prime}-x^{2} y^{\prime}=0 $$
Find the recurrence relation and general power series solution of the form $\sum_{n=0}^{\infty} a_{n} x^{n}$ $$ y^{\prime \prime}-x^{2} y^{\prime}=0 $$...
5 answers
Question 210 ptsUSE A RIEMANN SUM WITH 2 RECTANGLES TO ESTIMATE THE AREA UNDER THE CURVE f (1) = 12 + x+7 ON THE INTERVAL 0 < x < 4 GET THE HEIGHTS FROM THE MIDPOINTS
Question 2 10 pts USE A RIEMANN SUM WITH 2 RECTANGLES TO ESTIMATE THE AREA UNDER THE CURVE f (1) = 12 + x+7 ON THE INTERVAL 0 < x < 4 GET THE HEIGHTS FROM THE MIDPOINTS...
5 answers
Which of the following is most likely the major product of the reaction shown in the box?CHyMgClCH_CHzCHzClCH;CH-CH_MgClzCH;CH-CH,MgCH;CH,CH-MgCHz (+ Clz)CH,CH,CH CH,
Which of the following is most likely the major product of the reaction shown in the box? CHyMgCl CH_CHzCHzCl CH;CH-CH_MgClz CH;CH-CH,Mg CH;CH,CH-MgCHz (+ Clz) CH,CH,CH CH,...
5 answers
2 / 2R00L0J CeFor the function f(x) = x + 12x3, give intervals of increaseldecrease and intervals of concavity: (Perform tbe" first and second derivative tests either separately Or together).Increasing n:Decreasing On:Concave up 0n:Concave down On;
2 / 2 R00L 0J Ce For the function f(x) = x + 12x3, give intervals of increaseldecrease and intervals of concavity: (Perform tbe" first and second derivative tests either separately Or together). Increasing n: Decreasing On: Concave up 0n: Concave down On;...
5 answers
Problem 1:Using the Kappa Notation and a clearly labeled diagram, describethe bonding of one of the two [GeW9O34]polyanion ligands that sandwich a Mn Oxo double cubane cluster incompound 1?Na4.K(C 4H10NO)7{[GeW9O34][Mn1114Mn112 O4 (H2O)4]}15H2O (Compound1)
Problem 1: Using the Kappa Notation and a clearly labeled diagram, describe the bonding of one of the two [GeW9O34] polyanion ligands that sandwich a Mn Oxo double cubane cluster in compound 1? Na4.K(C 4H10NO)7 {[GeW9O34][Mn1114 Mn112 O4 (H 2O)4 ]}15H2O (Compound 1)...
5 answers
9. [-/7.69 Points]DETAILSSCALC8 11.6,025.Use the Root Tesl t0 deterinine whether the series convergent divergenl 5(0.) Idencn BEvaluate the following lirriic . V/ TanlSinceVTantSelocl-Need Help?nlchlk
9. [-/7.69 Points] DETAILS SCALC8 11.6,025. Use the Root Tesl t0 deterinine whether the series convergent divergenl 5(0.) Idencn B Evaluate the following lirriic . V/ Tanl Since VTant Selocl- Need Help? nlchlk...
5 answers
Show that the infinite series(2n- T(En+D)converges and determine its SuI
Show that the infinite series (2n- T(En+D) converges and determine its SuI...
5 answers
2 If cos(0) and 0 is in the Znd quadrant; find the 3 exact value for sin(0) .sin(0)Preview
2 If cos(0) and 0 is in the Znd quadrant; find the 3 exact value for sin(0) . sin(0) Preview...
5 answers
Q6 (3 points)The angle in degrees between (1,1,0) and (0,1,x) is 60 degrees_What is x? Explain your work _
Q6 (3 points) The angle in degrees between (1,1,0) and (0,1,x) is 60 degrees_ What is x? Explain your work _...
5 answers
The Isctope TI-208 undergoes beta deQy wth a half-Ife of 3.10 min. How many minutes wlli itake for 99,0% of a sample of pure 71-208 t0 decay? Polnts)20.60.2243.10
The Isctope TI-208 undergoes beta deQy wth a half-Ife of 3.10 min. How many minutes wlli itake for 99,0% of a sample of pure 71-208 t0 decay? Polnts) 20.6 0.224 3.10...

-- 0.022482--