4

Given 2 1.00 solution that [5 0.60 M HF and [.00 MKF; calculate the pH after 0.14 mol NaOH Is added, and calculate the pH after 0.18 mol HCI ts added tO tne origina...

Question

Given 2 1.00 solution that [5 0.60 M HF and [.00 MKF; calculate the pH after 0.14 mol NaOH Is added, and calculate the pH after 0.18 mol HCI ts added tO tne original solution.Ka = 72*10 -+pH =when NaOH addedpH =whcn HCI is addcd

Given 2 1.00 solution that [5 0.60 M HF and [.00 MKF; calculate the pH after 0.14 mol NaOH Is added, and calculate the pH after 0.18 mol HCI ts added tO tne original solution. Ka = 72*10 -+ pH = when NaOH added pH = whcn HCI is addcd



Answers

Calculate the pH after 0.10 mole of $\mathrm{NaOH}$ is added to 1.00 L of the solution in Exercise 25, and calculate the pH after 0.20 mole of $\mathrm{HCl}$ is added to $1.00 \mathrm{L}$ of the solution in Exercise 25

This is the problem. I'm doing a voice over. And this is more work on problem 25 I think. And this is probably 27. Yes. So calculate the pH after 0.10 Moles of any wages added to 1.0 Leader leaders of the solution and exercise 25 and exercise 25. 25. We had 250.60 Mueller HF and 1.0 Mueller K off. And what we just said is we're gonna add 0.10 moles if we add 0.10 moles of O h. Find the pH and we have another pH to find, too. The K for HF We looked up when we were doing probably 25 and at 7.2 times 10 to the minus four. So first were asked to find the pH, then were asked to find the pH of we added based Be asked by the pH we had an asset. So let's do the negative Henderson has about pH equals the negative log of K plus the log of the base over the log of the ass Lago base over asset ratio. PH is going to be the negative log at 7.2 times 10 to the minus four, plus the log of the concentration of the base. Let's do the acid 1st 0.60 Mueller and the concentration of the acid will be 0.100 Moeller and another 0.1 zero Mueller. So the law be the leg of 1.1, and then we need to subtract. Um, the 0.10 moller from the denominator. Do your Matthew in the math of the first part. Excuse me? The pH of when we add the base is 3.49 Okay, Now, for the second part, we have the same problem. But this time we're gonna add 0.20 moles of HCL. We're gonna add this to our buffer system so the pH again is going to be equal to the negative log of 7.7 point two times 10 to the minus four, plus the log of in this case, it's going to be point we're going to start with our 0.1 point 00 Now, we're gonna add 0.20 because we're adding acid, which means we'll subtract that from the base and we're going to get the log of 0.8 zero is over 0.8, which means zero. So the pH will be equal to the PKK, which is the negative log of 7.2 times 10 to the minus four, and the answer is 3.13 is the pH. Let's highlight that and call this problem done for the day.

First let us Cal Khalid B K A. For this value. So the foreigner we are using its peak a is equal to minus off. Log off. Hey, so the final be care value is seven point for six. Ex used the Henderson aggression to solve the it This is the hand disintegration immigration. After substituting the values in the creation, we get a B it off eight point cool. Then he h is equal to the value off B A. What offer? Transit fiction off acid is equal to the concentration off this here. The acid concentration needs to be increased by the base. Concentration needs to be decreased in order to get both have equal concentration. What's your problem? More asset is needed to be added in the buffer solution for the last, but even in the table, our initial concentration Auntie changing concentration after adding the acidic US and at P h equals toe peek A. Both asset and bass have same concentration. Hence we can solve that and get value off X, which equals Toby. Zero point 35 m. Therefore, 0.35 mole off asset. It still must be added to initial buffer. The concentration or a said the concentration off acid on base eventually equal to one another.

First, we'll calculate the pH of the buffer solution looking up the K value of H O C L, which is 3.5 times 10 to the negative eight. So pH will be equal to using the Henderson Hassle Baulch equation. The negative log of the K A value plus the log of the base concentration divided by the acid concentration based concentration, was given to us for potassium hypochlorite at 0.9, and then hypochlorite acid was point to, and we get a pH of 8.11 when pH equals P K. This ratio equals one, so the only way to make this ratio equal toe one is to add a strong acid. We need to decrease the amount of base by adding a strong acid and increase the amount of conjugate acid. So when the ratio is one, we have 10.9 minus X. The amount X, which is the amount of strong acid added and then 0.2 plus x, which is the amount of strong acid added. Rearranging the equation and solving for X gives us an X value of 0.35 moles of a strong acid such as HCL


Similar Solved Questions

2 answers
The metric for a certain space-time geometry ism +rm ~rds2dt? m =7)(m? + 2mr +72)dr2+r2 (d0? +sin? Ad6? Ft)(m? + 2mr +72)1) Calculate the proper distance along the radial line from the centre r = 0 to a coordinate radius r = R. ii) Calculate the arca of a sphere of coordinate radius r = RS iii) Calculate the three-volume of a sphere of coordinate radius r = R
The metric for a certain space-time geometry is m +r m ~r ds2 dt? m =7)(m? + 2mr +72) dr2+r2 (d0? +sin? Ad6? Ft)(m? + 2mr +72) 1) Calculate the proper distance along the radial line from the centre r = 0 to a coordinate radius r = R. ii) Calculate the arca of a sphere of coordinate radius r = RS iii...
1 answers
Let Phe HOHZCTO projector. Show that |Plz > 1 with equality if and only if P is a orthogonal projector. (Hint: IABIz < IAleUBlz). What happens if we replace the 2-nOrm by the Frobcnius norm of F
Let Phe HOHZCTO projector. Show that |Plz > 1 with equality if and only if P is a orthogonal projector. (Hint: IABIz < IAleUBlz). What happens if we replace the 2-nOrm by the Frobcnius norm of F...
5 answers
RequiredSection13.A sales in a book store follow a uniform distribution with mean 15 Calculate the probability that sales exceed 5 books (3 Points)Enter your answerBackNext
Required Section 13.A sales in a book store follow a uniform distribution with mean 15 Calculate the probability that sales exceed 5 books (3 Points) Enter your answer Back Next...
5 answers
Puyejowa Ha secx Gineaahv aniea 1 V both sides the are V abuid are identity; inot veqifa]i 1 equation
puyejowa Ha secx Gineaahv aniea 1 V both sides the are V abuid are identity; inot veqifa]i 1 equation...
5 answers
4) Find the arc length of the curve V = 81-from X= ltox=2 Find the surface area of revolution generated by the curve v = V< fromx= 5) 0 to x = 1 when rotated about the X-axis:
4) Find the arc length of the curve V = 81-from X= ltox=2 Find the surface area of revolution generated by the curve v = V< fromx= 5) 0 to x = 1 when rotated about the X-axis:...
5 answers
Drw the structure of compaund writh the folkving spertra (15) Molecular fomula: CHuOr J4-UMR:PPHLhemicainegitionSplntingpattem Singlet (witle) Triplet Triplet sinelet
Drw the structure of compaund writh the folkving spertra (15) Molecular fomula: CHuOr J4-UMR: PPH Lhemica inegition Splntingpattem Singlet (witle) Triplet Triplet sinelet...
5 answers
Draw an arTow for each glider tO represent the direction of the change in velocity from before to after the collision. Explain how you determined your answer.Direction of . change velocity Glider Glider B
Draw an arTow for each glider tO represent the direction of the change in velocity from before to after the collision. Explain how you determined your answer. Direction of . change velocity Glider Glider B...
5 answers
Critique the following analogy: Climbing a staircase is used as an analogy for the transition of electrons to different energy levels in an atom_
Critique the following analogy: Climbing a staircase is used as an analogy for the transition of electrons to different energy levels in an atom_...
5 answers
Physics student observes light passing from air into Water: His results are as follows: angle of meidlence 10.(", anple of retraetion 0"; ad angle ol ieidenee 20,0" and angle of refraetion 15.5" Wh is the aVerage value ofthe index mf reliaetion for Waler"
physics student observes light passing from air into Water: His results are as follows: angle of meidlence 10.(", anple of retraetion 0"; ad angle ol ieidenee 20,0" and angle of refraetion 15.5" Wh is the aVerage value ofthe index mf reliaetion for Waler"...
5 answers
HomeInsertDrawDesign LayoutRelerences Matlings: Be careful Rvic" Vus PROTECTED VIEW files Irom the Internet can cantain Hop salet vinutnx. stay Unicic you i Protected Viexi feed t0 edit n; EnqbleEPrstsnakd 4 - PhroheAnthracen&
Home Insert Draw Design Layout Relerences Matlings: Be careful Rvic" Vus PROTECTED VIEW files Irom the Internet can cantain Hop salet vinutnx. stay Unicic you i Protected Viexi feed t0 edit n; EnqbleE Prstsnakd 4 - Phrohe Anthracen&...
5 answers
OHm-bromohydroxyacetophenone S-acetyl-2-bromophenol 4-bromo-3-hydroxyacetophenone T-acetyl-+-bromo-3-hydroxybenzene
OH m-bromohydroxyacetophenone S-acetyl-2-bromophenol 4-bromo-3-hydroxyacetophenone T-acetyl-+-bromo-3-hydroxybenzene...
5 answers
Choose the correct compound #1 and #2 to give the product for the following reaction:CICH,Ccl CICo NaCH,CH, NHCI;c - CH,Mlcita
Choose the correct compound #1 and #2 to give the product for the following reaction: CICH,Ccl CICo Na CH,CH, NHCI;c - CH, Mlcita...
5 answers
'. ~.,Exavwn 9rl) ~) etil {74n6/'*.^ ^~0m {llod 1i "Kily orl} HG etl:-' 1 : V "fhl | ''-10) Let fx) = xe-2x2 Using the first derivative test; find values of f the exact values of all local maximum and minimum Xc4)-()leer) 7*2-2)k 22 = (h-) ((b) Find the global maximum and the ' global minimum values offon the interval [0, 21:onl,Pat
'. ~., Exavwn 9rl) ~) etil {74n6/'*.^ ^~0m {llod 1i "Kily orl} HG etl:-' 1 : V "fhl | ''- 10) Let fx) = xe-2x2 Using the first derivative test; find values of f the exact values of all local maximum and minimum Xc4)-()leer) 7*2-2)k 22 = (h-) ( (b) Find the global ...
5 answers
Point)Let T : R3 _ R3 be the linear transformation with eigenvalues Az = ~1, Xz = -3, A3 = 3 and corresponding eigenvectors V1 = (-2,1,-1) , V2 = (2,1,0) , V3 (1,0,0).Then T(z,y,2) =
point) Let T : R3 _ R3 be the linear transformation with eigenvalues Az = ~1, Xz = -3, A3 = 3 and corresponding eigenvectors V1 = (-2,1,-1) , V2 = (2,1,0) , V3 (1,0,0). Then T(z,y,2) =...

-- 0.020751--