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Ka Aj [email protected] 12O t20 Coyjtlao L(t)EO (lfcl>` EnA 4he Pess ilc squilbriun_tempetolue_diS-ributea s Solue em @[email protected] Jeaou e Tv Lb tne e Ancs 4a2 an cons...

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Ka Aj [email protected] 12O t20 Coyjtlao L(t)EO (lfcl>` EnA 4he Pess ilc squilbriun_tempetolue_diS-ributea s Solue em @[email protected] Jeaou e Tv Lb tne e Ancs 4a2 an consa"! Yi pax i 9e 1 Lrge discees 494 feSuls

ka Aj dxl @CosLLto 12O t20 Coyjtlao L(t)EO (lfcl > ` EnA 4he Pess ilc squilbriun_tempetolue_diS-ributea s Solue em @[email protected] Jeaou e Tv Lb tne e Ancs 4a2 an consa"! Yi pax i 9e 1 Lrge discees 494 feSuls



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licre the ycllow and orangc precipirares arc, rcspectively (a) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{-}$ (b) $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}$ (c) $\mathrm{Na}_{2} \mathrm{CrO}_{4}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$ (d) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$

In this problem, the yellow solution yellow solution, which age I need to see R 04 on reaction will give us yellow PPT and the yellow PPT here. Age B b CR 04. Therefore, according to the option option C. H, correct answer for this problem, Option C. Each correct answer for this problem, I hope you understand the the action of this problem.

In this problem we have to find a frequency distribution for the given data of the viewing Audiences and Millions for the Top 20 Television Shows. And here we are going to use the cut point grouping as a data or continuous. So it's given we have to use the first class. Wolf 12 213. Okay. Mhm. So here. Yes. Yeah. Medium season limb. Yeah. Uh huh. Mhm. So the first classes Child 213. Yeah. Okay. Mhm. To the next class is 13 to wonder. 14. This will be 14 two Under. Hmm. So it goes still 20 10 to only 16. Thanks, Jonathan Under 17. Mhm 17 to Mhm Under 18. Mhm 18 to UNDER 19, 19, 2. And I can t So first twin Chill. The 13 will be Mhm. And one. Okay. Three. Next will be 13 to 14 Will be 1, 2. Yeah. 345 Yeah. Yeah. Yeah. 14 to 15 would be 12 12 Beautiful. 15 to 16 will be Mhm. Mhm. 123 in four. 16 to 17 would he run? And 17 Tueting Divine. Mm 18-1921. Year one. If you see the total of the sample size is 20. Now we have to find out later frequency distribution which will be the corresponding frequency divided by the total sample size. Which is 20. So three by 20 will give us 0.15, Extremely five x 20. She's going to be 0.25. It's just full by 20. Just point to Thanks jess one by 20. Yeah, That is .05. Yeah. Right. Yeah. Now facing the daughter, It's going to be one. We have to construct construct instagram. Now here is instagram. Yeah. For the frequency, the top broadcast shows. So if we see 12 UNDER 13, we have taken the classes, cut point grouping glasses along the Yeah, horizontal axis and the frequencies along the vertical axis. So for 1213 It will be three. So it's your 13 and 14. Just five, 14 and 15 before it's going to before the rest will be one each. Now, this is the instagram for the later frequency, which is our option D. So we have taken classes Along the horizontal axis and related frequency along the vertical axis, and the vertical bar presents a corresponding later frequency of the particular class, 12- 13 and 13. The related frequency is .15, which is here for the next class it is .25. For the next two classes, it is point to here And for the next four classes at this point 05 Yeah. Right.

In this problem, I'm writing the reaction. Just look at it carefully. Any energy for at be your ford four H two will react to form any and at four at people for plus four as to and and ME energy for add bill for will react to form and the beauty plus an STD plus as to So according to the option. In this problem option. See each correct. Was there not that we have any Beauty which reacts with metallic oxide to give colored or to post fails.

This problem involves similar triangles which uses ratios and proportions. First draw the two similar triangles with their given lengths and we'll assume the length of X. Y. S. M. Now ratios of lengths from corresponding sides of similar triangles are equal and side VK corresponds to side Z. Y. Therefore the ratio is nine, it's 24 US 10 is to um Mhm. Yeah. By the cross product property nine times M. Yes. nine a.m. Yeah. and four times 10 is 40. Now we'll simplify by dividing nine to both sides, so the left side is just going to be M. and 40 divided by nine is 40/9 or four and 4 nights. Therefore the length of X. Y is 40/9 or four and 4 nights.


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