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Homework: Topic 4 69 0f 87 (77 complete) HW Score: 80.8224. 70.320l Score: 0 of 1 pt Queation Hele 7.3.9 109 body temperatures hag 98 20"F and 0.64"F Cons...

Question

Homework: Topic 4 69 0f 87 (77 complete) HW Score: 80.8224. 70.320l Score: 0 of 1 pt Queation Hele 7.3.9 109 body temperatures hag 98 20"F and 0.64"F Construct 907 confidence population with norial distribulion simiple random sumple Trom femperature of all healthy humang estimaie of the standard deviation of body Click the Icon view the table 0f Chi-Square critical valuesFaodre<~-D" (Round fvo decimal places as needed )

Homework: Topic 4 69 0f 87 (77 complete) HW Score: 80.8224. 70.320l Score: 0 of 1 pt Queation Hele 7.3.9 109 body temperatures hag 98 20"F and 0.64"F Construct 907 confidence population with norial distribulion simiple random sumple Trom femperature of all healthy humang estimaie of the standard deviation of body Click the Icon view the table 0f Chi-Square critical values Faodre<~-D" (Round fvo decimal places as needed )



Answers

Construct the confidence interval estimate of the mean. Data Set 3 "Body Temperatures" in Appendix B includes a sample of 106 body temperatures having a mean of $98.20^{\circ} \mathrm{F}$ and a standard deviation of $0.62^{\circ} \mathrm{F}$. Construct a $95 \%$ confidence interval estimate of the mean body temperature for the entire population. What does the result suggest about the common belief that $98.6^{\circ} \mathrm{F}$ is the mean body temperature?

Mhm. MS question given that end it's 40. What X is 1 25? Yeah. Mhm. And because Standard deviation as 12 and nine. Okay. Uh D T up over to value for 99 confidence interval. Thanks 39 degrees. Mhm. Freedom Okay. is 2.70 and uh value table T Alice. So now to calculate 99% confidence interval, the opposition, you can use this general, you know, it's funny that So plugging in the values that we know 20.5 plus or minus 2.7 earlier Times, Over the square root of 40. Well I should give us two distinct values for the upper and lower bounds. Um Expectedly She will be 1 14.98. Lower bound and the upper bound will be 126.02. So this is the region for the 99% Clinton's level.

Okay. This problem is for number 55. Um, we're estimating the B m I with the standard deviation being 7 45 And, um, we're estimating the mean of the and I, uh, with a plus minus one. Okay, with 99 percent confidence level. So in this case, if you're looking for the minimal sample size gonna be an minimal We have formula is the ALF of the two times sigma and over e and then square over here. Standard deviation 7.5. Where is gonna be the eat? So there's there's gonna be the signal within plus minus one. So we didn't call to being one, which is the maximum era for 99% confidence level, You know, disease, or what goes case will be to going 57 So if we know that we can just go ahead and plug everything we have, we're into the Cingular to coin fired. Stellar five times. Sigma 75 desire by, uh, Mac Margin of the era can large in the era which your one square I was in cockpit or you have 19.31 25 inside of the open Percy's. We're square. That getting 372 point mind. Seven. Because this is the minimum sample size, we need to round this up too. 373 so the minimum sample size would be 373.

Our degrees of freedom are one less than the sample sizes so far in numerator, we're gonna have 40 and then a denominator. We're not 19. We can find the critical values in table eight. Since we're doing a 10% significance level, that means we have 5% on each side. So the f statistic cream you're looking for in the back of the book is F 0.5 Have this many degrees of freedom and we find that it is 2.3 Now the F of 095 is going to be equal to mhm. One over these things reversed which is 1.185 Yeah, approximately 054 Okay. Now we can plug them into these boundaries using these formulas right here. Well multiply them out. And for this bottom one we're going to get 1.37 and 2.11 Therefore our 90% confidence interval is from 1.37 to 2.11 Okay. Mhm.

In this problem we have to construct the dot plot for the for AIDS and schools in an introductory statistics squares. Oh okay. Yeah. Mhm. So first we'll draw horizontal axis. So here's your horizontal axis that displaced possible values of the quantity to NATO. Okay. So if you see the minimum value here is 34, maximum Around 100. So we'll plot From 30 200 So we'll start with 13. Mhm. Soon Here if you see to be 35 and This will be 14. Yeah This move a 14. Yeah. Just give me 45 mm 15. Okay let's keep five. Mhm mm 16. The music's too quiet. Mhm. It's moving 17 feeling It is 175 80 185 in 19 95 And it's going to be a 100 sooner. It's my first observation. Just we have to record each observation by placing a lot over the appropriate value on your glasses. So if you see 88 it is over here. Yeah. Mhm. I'm 82. Yeah, 89. Uh huh. Yeah. Okay. Mhm. Yeah. Is 85- 88. Okay. Is over here and take it to it's going to be here mm. From 89 Next to 88. No. Mm hmm, 17. Mhm. All right, 85. Pretty Girl. Great, 63. Yeah. Thank you. 100. Cool. Yeah. Mhm. 86. Mhm. Okay, 67. Okay. Mhm. 39. Mhm. Mhm. 19 96. Mhm. Mhm. Mhm. Oh, Mhm. 76. Yeah. Okay. 34. What? 81 64. So my In full in 83 and 64. Let's do. Mhm. Stupid thing. 75. Yeah. Yeah, 84. Right. Mhm. Mhm. 89. Okay. Yeah. So we can mark a baldy Bolivia is blocked, you know, Because it's again you can talk about it, mm hmm. Yeah. Yeah. Please don't. Mhm. You see this is uh Mhm. Dark locked. Mhm. Yeah. What


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