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Loadtll kdua can producad upon coolig laadlll}Ionido ions Irom soution21-(aq) - Pb'+ (aq) Pblz(s) - HetPut whlch directkn will Lia equilibnum shit Da Per1ai= J...

Question

Loadtll kdua can producad upon coolig laadlll}Ionido ions Irom soution21-(aq) - Pb'+ (aq) Pblz(s) - HetPut whlch directkn will Lia equilibnum shit Da Per1ai= Jaune thalr reeoactivetallowing chames occut lD Iho rujctonAnnaddnarnote End IloddtRighitAronceen

Loadtll kdua can producad upon coolig laadlll} Ionido ions Irom soution 21-(aq) - Pb'+ (aq) Pblz(s) - Het Put whlch directkn will Lia equilibnum shit Da Per1ai= Jaune thalr reeoactive tallowing chames occut lD Iho rujcton Annaddna rnote End Iloddt Righit Aronceen



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Brown ring resr for nirare fails if rhe mixrure of salrs, conrain along wirh nirrarc, (a) $\mathrm{CO}_{5}^{2-}$ ions (b) $\mathrm{NO}_{2}^{-\text {ions }}$ (c) $\mathrm{SO}_{4}^{2-}$ ions (d) Br-ions

In this problem, I'm writing the reaction. Just look at it carefully. Any energy for at be your ford four H two will react to form any and at four at people for plus four as to and and ME energy for add bill for will react to form and the beauty plus an STD plus as to So according to the option. In this problem option. See each correct. Was there not that we have any Beauty which reacts with metallic oxide to give colored or to post fails.

In this problem, I'm writing the the reaction so just look at it carefully in presence of concentrated SCL f e c l t six H two in potential concentrated SCL will give the product ad f e CL four I am. Therefore according to the given option in this problem, option A is correct, therefore absent age. But again, sir, for this problem.

When determining the charge on an element that is found in an ionic compound. Often all we need to do is identify the group in which the element is found. If it is a metal, it will be a cat eye on and if it is a non metal it will be an anti on. So let's draw a periodic table showing the group numbers and the common charges that are created when these elements in particular groups form compounds most specifically ionic compounds. So in Group one A. And two A. These medals when forming ionic compounds will have charges one plus and two plus respectively. Then we'll go to three A. Which is three plus four A. Could be four plus or four minus, then we begin to go to the negatives. If it's a non metal in Group five A. It'll be three minus 68 to minus seven A one minus. So cesium is in group one A. It will have a one plus charge gallium is in group three A. It'll have a three plus charge, oxygen is in group six A. It'll have a tu minus charge and then iodine is in group seven A. It will have a one minus charge.

Yeah, So we are given with cobalt as I am in Layton system of naming The name for cobalt have plus two charge. So it'll be see you too positive. And the second option we have co Baltic I am in this case the charge will be Ceo 34 different as discussed in previous two questions. The only compound with low charge That is plus two hair. We'll have a suffix or us, but with the high charge will have a suffix. I see last three.


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