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7/0.6 points GVSUChem116v2 17.f.1.PO02_My NotesReaction ProfilesThe following reaction profile is for reaction at 380 K that occurs at constant pressureEnergyReac...

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7/0.6 points GVSUChem116v2 17.f.1.PO02_My NotesReaction ProfilesThe following reaction profile is for reaction at 380 K that occurs at constant pressureEnergyReactnisProductsExtent of ReactionThe AHrxn for the reaction -104. kJlmol The Ea for the forward reaction 44.0 kJ/molLabel each nf the followina narts nf the reaction profile (a-d) by matching the names to the regions below: region The transition state region Ea for the reverse reaction region The AH for the reaction Ea for the forward re

7/0.6 points GVSUChem116v2 17.f.1.PO02_ My Notes Reaction Profiles The following reaction profile is for reaction at 380 K that occurs at constant pressure Energy Reactnis Products Extent of Reaction The AHrxn for the reaction -104. kJlmol The Ea for the forward reaction 44.0 kJ/mol Label each nf the followina narts nf the reaction profile (a-d) by matching the names to the regions below: region The transition state region Ea for the reverse reaction region The AH for the reaction Ea for the forward reaction region The AG of the reaction_ The intermediate What is the Ea for the reverse reaction? How many steps are involved in this reaction? Answer with number not wora



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Consider a reaction that occurs by the following mechanism:
$$\mathrm{A}+\mathrm{BC} \longrightarrow \mathrm{AC}+\mathrm{B}$$
$$\mathrm{AC}+\mathrm{D} \longrightarrow \mathrm{A}+\mathrm{CD}$$
(a) What is the equation for the overall reaction?
(b) Write structural formulas for all species present at reaction stages $1-5 .$ Identify each species as a reactant, product, catalyst, intermediate, or transition state.
(c) Which of the two steps in the mechanism is the rate determining step? Write the rate law for the overall reaction.
(d) Is the reaction endothermic or exothermic? Add labels to the diagram that show the values of the energy of reaction $\Delta E$ and the activation energy $E_{\mathrm{a}}$ for the overall reaction.

Everyone. So the first part of this question we have the free energy change changes related to the equilibrium constant. By this following reaction we know Al Taji North equals two minus R. T. K. Migration one. So as the gas contents gas constant which is eight point which value is 8.314 jewel Permal. And the East temperature and energy is energy. And for a reaction. So we have the equilibrium concert at 2 98 0.15 caravan. That is a 4.3 into 10 days to the bubble six. So we'll have to now using the calculation values to calculate the free energy change of reaction will get delta gene or D equals two. Now we'll have to put uh the values in the situation. So we'll get minus 37.9. After the calculation formal, the three energy change of destruction is 37.9 minus citizen 19 So now be part to calculate equilibrium constant at $800 resources will have to use another world. A world of equation that is okay. Do you want to bone? Okay 82. He was two minus. There is an order of honour one of all. Two to minus on upon Stephen. This is the question one. No. So now substituting the values in the question one and calculate T two at 1073.15 Calvin. So we'll get so at 1731073.15 cats when they'll get after subject between the values for boy 19 to 10 days to devour minus four. Now coming onto the C. Part knowing the thermodynamic time chemical equilibrium constant at 800 degrees Celsius. Okay is equals to 4.9 into 10 days of the power minus four. So we know that the equation for delta G. Nobody goes to minus Rt in K. So use the values uh to calculate the free energy thing at the reaction of that Internet results is so we'll get after substituting the values in this equation will get 68 0.0 kg jewel Parimal. So does the free energy change. Is this now for the D part for a reaction to be spontaneous, the free energy change should be negative. And if it is positive, the action, it is non spontaneous. So the reaction becomes non spontaneous at the high temperature. So 800 degrees Celsius as it has positive free energy change while the reaction is spontaneous, as at 25 degrees Celsius due to its negative energy value. So, last part we have been asked. So even though the reaction between non spontaneous the high temperature, the reaction proceeds faster at higher temperature. That's it. Thank you.

Problems 17.88. The um there's a lot of different parts. So the first part you need to calculate the delta G. Not 25 degrees Celsius. And to do this you use this formula I have written here and plug in what they give you. So the daughter G not would basically be negative. Rt which is negative 8.3 14 tools over Calvin times the temperature which is Which is 298 0.15 Calvin times O. N. Of K. P. Which they give you is 4.3 times 10 to the power of six. So this will calculate this, you find that the ideology Not this negative 3.79 Times 10 to the power for jules per more. So this would be your answer her party and four party. They want you to calculate the K. 800°C. So to do this, you want to use the ramparts equation and the T. one is what they give you which is 25°C. So we use the K. Constant. They give you here The 4.3 times 10 to the power of six. And Katie to which we're trying to find. And the Delta H. is negative 78.58 times 10 to the power of three jewels. And make sure to use the jewels because we're working with um jules instead of killer jewels for the are constant. And you do the T. One which is 2 98 kelvin minus um one over 1007 The three Calvin. And that is found through adding a 273-800 because it's 800°C right in the right here. And this should equal um K. P. At 107. The three companies over 4.3 times 10 to the pepper six equals E. To the power of negative 22.9. And when you saw this you get that the K. P. 800°C. The resource ius equals 4.9 times 10 to the power of -4. All right. So the next part they asked you to calculate the data Gee not 100°C. So we go back to using this formula here. So you plug it in negative RT 8.314 Rules over Kelvin times the temperature which is now in 1073 Calvin's times out. And of the K. P. Which we found earlier here. So you plug that in here. 4.9 times 10 to the negative four. When you find that the cape or dot org not of this reaction is 6.80 times 10 to the power for draws over move this will be your answer here. And for party they ask you, how does this ponting respond to you? Funny Movie of the four reaction 800°C compared with that 25°C. So right. That is at the forward reaction At 800°C is not spontaneous because the data G is positive as we found here. And the For a reaction at 25° soc it is spontaneous. And this is because we found that the delta G is negative as we calculated here. Yeah. Uh So for if they ask you um why do you think the reaction make sure is heated in the industrial preparation of ice? I'm so octane. So the reason why the reaction picture is heated is because when you heat a reaction, make sure it speeds up the rate at which the equilibrium is reached. So that's why. And this doesn't heating up. The reaction doesn't have anything to do with like shifting or equilibrium to the product or anything because uh the heating actually decreases the amount of product. President and the equilibrium because this reaction is excellent thermic reaction. And since we have a negative delta age, so if you increase the um temperature, then you actually shift to the left and increase the reacted. So the answer for this is heating up the reaction, nick sure will speed up the rate, which equally free um is reached. So, for part f they asked you what would be the effect of adding and catalyst to the forward or reverse react reactions. So, the catalysts were the forward and reverse reactions at the same rate to the same extent. And this has to do with kinetics, it doesn't have anything to do with the equilibrium. So, adding a catalyst would not change the equilibrium. It just increases the rate at which the reaction will reach equilibrium. All right, so these will be your answers. Oh?

The graph that were given is of the natural log of the concentration C H three N c versus time and this is linear. And so this should always just ring a bell in your head that what we have This graph the natural log of a certain substance versus time and it's linear. That means that this is first order with respect to this reaction. And so that's the information that we're gonna be needing. So what is the rate law? Well, we could get that from knowing that this is First order with respect to ch three and see the rate equals first a rate constant K times ch three and see Yes, uh, what is the equation? So the reason, um, it's a straight line. If it's up draft like this for for stories comes from the integrated rate law, Remember, the integrated rate law is that the natural log a C h three n c will be equal to negative Katie, plus the natural log of the initial concentration of CS three NC. And so this is fully for a first sort of reaction. But let's take a look. So here this over here is a constant because there's just only one initial condition. So would just label this be this over here is variable. It changes over time and that's what we're graphing on the y axis here. And so we'll call this why Time K is a constant time is our variable that we graph on the X axis. And so we're really saying we have Why equals negative que x plus b And so this should be ringing about who we're seeing that this is our sloping herself form commonly written as y equals MX plus B. But either way, we have that our Y intercept is equal to the natural log of C H three n c. And our slope is equal to negative K. And so this is the equation for our show line. We can we can fill in, fill in the gaps there If we could figure out what K is So the figure. Okay, we're going to figure out the slope and so remember, slope equals rise over run. And so I got for my slope. I got that. It was negative 2.4 times 10 to the negative fourth in verse. Seconds, I believe, is the units that were given to us. Yeah, the second. So inverse seconds. But since that's equal to negative KK, our rate constants 2.4 times 10 scenario fourth for seconds. This I enter the 1st 3 parts. Um, from there on out, it's all a bit easier. Um, wherefore asked you out. How long does it take for this amount to go toe half it? That's asking, basically, what is the half life? The half life is by definition, like in from the integrated Ray largest. How derived Allen of To overtake we have today. We plug it in and we'll find that it is equal to 2888 seconds. Then, uh, our next step is to figure out we'll use the integrated rate lock to figure out what it is. At T equals, uh, 10,000 seconds and so memory. The integrated rate law is a natural August ch three and see equal to negative Katie, plus the natural log of the initial concentration. We don't actually have this specifically, but we can look at the graph and see that overly from the y axis, the be the Y intercept is right around negative foreign. So So I just plug it in here. I said, This is negative four. Our time we have that. We have our rate constant K still throw that in there. And so then we can get We can solve for C h truancy. And when you do that, that initial concentration is equal to 1.6 six times 10 to negative Third Moller, and you can check this by a few. Plus, if you take the natural lot of this and plug it back into into the graph, you'll see that it's negative 6.4, which is right around where it should be.

To solve this problem. I will use the equation. Are nes equation K is equal to eight to the power minus E. By E R. T case. Great content. A pretty exponential factor. E. H. Activation energy. Our guest content. Each temperature the solving party I can write the value of K is equal to 3.98 Multiplication 10 to the power minus 13. Once again multiplication need to depart minus 1632 people you know multiplication 8.314 multiplication 298 And here it divides, saying now going forward and solving it further. So I can write develop period three point 98 multiplication 10 to deport 13 multiplication. Need to depart minus 64.85 Which one simplification And I get 3.69 multiplication 10 to the power minus 15 per second. As our answer for party. Now for part B I can write the value of K. Is equal to 3.98 Multiplication 10 to the power 13 multiplication E to the power miners. 160 people zero, bye 8.314 multiplication 388 0.15 which aren't solving. I get the value of cage 1.17 multiplication 10 24 minus eight one second as our answer for part of it.


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