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Consider the following reaction at 298 K. Cult(aq) Crlt(aq) Cut(aq) + Crt(aq) Which of the following statements are correct?Choose all that apply E"cell < 0...

Question

Consider the following reaction at 298 K. Cult(aq) Crlt(aq) Cut(aq) + Crt(aq) Which of the following statements are correct?Choose all that apply E"cell < 0 delta Go < 0 n = ] mol electronsK<1 The reaction is product-favored.

Consider the following reaction at 298 K. Cult(aq) Crlt(aq) Cut(aq) + Crt(aq) Which of the following statements are correct? Choose all that apply E"cell < 0 delta Go < 0 n = ] mol electrons K<1 The reaction is product-favored.



Answers

A redox reaction employed in an electrochemical cell has a negative $\Delta G_{\mathrm{rxn}}^{\circ}$
Which statement is true?
a. $E_{\mathrm{cell}}^{\circ}$ is positive; $K<1$ b. $E_{\text { cell }}^{\circ}$ is positive; $K>1$
c. $E_{\text { cell }}^{\circ}$ is negative; $K>1$
d. $E_{\text { cell }}^{\circ}$ is negative; $K<1$
A redox reaction has an equilibrium constant of $K=0.055 .$ What is true of $\Delta G_{\mathrm{ran}}^{\circ}$ and $E_{\text { cell }}^{\circ}$ for this reaction?

So we have a spontaneous reaction. Well, we I'm sorry. We have a reaction with negative Delta G zero. Ah, but yes, that does mean it's spontaneous, at least under standard conditions. Um, and of course, that is why the standard conditions are everything at one. Well, all of the acquia substances in the reaction at one Moeller all of the gases in the reaction at one atmosphere is because that makes Q equal to one under standard conditions, and the the reaction will go to the right under standard conditions. And when it comes to equilibrium, you'll have more products than react. It's and K will be greater than one. So the 1st 2 are definitely true. But ah, a negative value of Delta G zero does not mean a negative value for Delta H necessarily. Certainly a negative Delta age contributes to a negative Delta G, whether at standard conditions or not. Ah, but the reaction can be, uh, entropy driven. If the entropy is great enough in the temperature is high enough. Then you're gonna be subtracting a big positive from a positive and you can get a negative, so could be negative. Um, we don't want a check here. We want a big red X. That one is false.

Hello. So we know that the relation between the free energy change and the equilibrium constant K is delta G. It was 2 -10ie in K. So the relation between the free energy change of reaction and e not sell is delta G. Not Equals 2 -3F. We have started it before. Also you should be aware of it. So it really goes to a refugee not equals 2 -3F. Not sell. Therefore there is uh do you know equals two negative. So here we can see that equilibrium constant case should be positive and energy cell should be positive. So hence the correct option is option B. Option B is the correct answer. Thanks.

So, uh, brutality. Because, too, it's no nurse the equation, because to any half minus any f Okay. And also it goes to minus Artie knowing, right? The question said it has an active Gallinger. So that means this should be passed. You the data e should be positive. Oh, sorry. The standard should be positive. And the k standard should bigger than one. Okay, because this is minus is this isn't like you, so option a is correct.

So hello. So the relation between the equilibrium constant for a chemical reaction K. And the standard uh cell potential in our cell, is he not said it was too 0.05 92 We have read this before one in Lucky. This is the kind of formula we can see. So here N is the number of molds and there's a number of moles of electrons like Librium constant, K Is 0.055. And the value of Laki is negative, look is negative. So therefore the value of standard self potential energy is negative. He not sell well your standard sell potentially in ourselves is negative. So now the relation between the standard change in three energy for a chemical reaction to G. Told and the standard electoral potential in order to is we know cartagena, he goes to minus and yes, he no I said we have read this before. So here Fst Faraday's constant and the value of F. S. This this is the value of Faraday's constant, 96485 gula upon mall electron two and at the end and it's the number of moles of electrons. So since the value of standard cell potential electron is negative, the value of the standard change in free energy for a chemical reaction, the liturgy is positive. So this indicates that the reaction is non spontaneous, so detection is non spontaneous. That's it. Thanks.


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