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6(a) (10 points) 1.0 mol Hz O(g) at 400 K and 1.0 bar is added to 10.0 mol HzO() at 300 K in thermally insulated container maintained at a constant pressure of 1....

Question

6(a) (10 points) 1.0 mol Hz O(g) at 400 K and 1.0 bar is added to 10.0 mol HzO() at 300 K in thermally insulated container maintained at a constant pressure of 1.0 bar The system is allowed to reach equilibrium. From data in Table 4.1 of your text (Appendix A), determine the temperature of the system at equilibrium: You may assume that any relevant heat capacities are independent of temperature. You may not assume that the enthalpy of vaporization of water is independent of temperature_ You wi

6(a) (10 points) 1.0 mol Hz O(g) at 400 K and 1.0 bar is added to 10.0 mol HzO() at 300 K in thermally insulated container maintained at a constant pressure of 1.0 bar The system is allowed to reach equilibrium. From data in Table 4.1 of your text (Appendix A), determine the temperature of the system at equilibrium: You may assume that any relevant heat capacities are independent of temperature. You may not assume that the enthalpy of vaporization of water is independent of temperature_ You will need data from your text: Note that 373.15 K is the standard boiling point of water.) (10 points) Calculate the change in entropy; 4S, for the process described in a)



Answers

One ton of liquid water at $80^{\circ} \mathrm{C}$ is brought into a well-insulated and well-sealed $4-\mathrm{m} \times 5-\mathrm{m} \times 7-\mathrm{m}$ room initially at $22^{\circ} \mathrm{C}$ and $100 \mathrm{kPa}$. Assuming constant specific heats for both air and water at room temperature, determine (a) the final equilibrium temperature in the room and $(b)$ the total entropy change during this process, in $\mathrm{kJ} / \mathrm{K}$.

Everybody. So for this one, I need find the total charge and entropy. You see, table 8.5. That's again. We'll find values. Your table 8.5. So we have the c t next, all right? And it's gonna be 0.4 times 1.872 plus 0.6 times 0.842 And this will give you 1.254 Hey, rules for kilogram monies paid. And now we have the art Knicks. And that is going to get you people 0.4 times 0.4615 Okay, plus 0.6 times 0.188 ni. It's gonna be 0.29794 There are jewels for kilogram times. Okay, So not gonna find the change in pokey. No, I'm saying that weird to get doesn't eight apiece as maybe your seat he licks. Um, Times t Teoh minus one. Okay, so yet one points, Teoh by four times one fouls in minus 400 million to your cop leader, and you're gonna get seven by two points for killing tools for really? All right. And now for, uh, your interview. Yeah, dealt us equals R C. He mix times log of comfort to minus and through one minus our next times the law. Um, the first two divided by one. Okay, on. So this, people to one point Teoh five, four times the log of 1000. Divided by 400 and minus 0.29794 times the log. Uh, times 1 20 divided by 1 20 And just in time to your calculator and you're gonna get 1.149 He would rules her Phil Gramm's times. Kelvin for your guys.

Okay, We are provided with the heat off fusion Off line. Delta Edge Fusion equals 5610 along with Delta H for freezing. That means negative. 5610 These both are jewels. Formal Delta G equals negative. 10 on temperature, which is 10 degrees Celsius equals to 63. Kevin, this is a very easy question. Just let me read the formula first. Did the H off system minus then touching, divided by team. Just substitute all the values we have. Negative. 5610 Minus to him. Divided by to 63 killer. And so, for this is negative. 20.5. Jules for Children. We also know that Delta s four system equals negative. Delta H off the system, divided by temperature, substituting the values we were here. The answer is 21.33 jewels. Were Kevin home no degrees and get further. Delta s for the universe equals Delta s our system. Plus delta s. But this was surroundings, substituting the values we have obtained from previous toe equations. Negative. 20 point, Frank. Yes, 21.33 It gives us zero point 83 Jules per Children. What

So this question is about There's enough water. So we have a history of liquid going to boost you or solid. Now we're told that they doubted you bought this reaction. So that's a reaction. This, uh, my nose too. Gino's? Oh, on the prosecution of eyes, that's all these temperatures. So that's a huge infusion. These 56 once Theo skills for more. So find the entropy change of the universe s address. That's for the law number one more water. And that's temperature. It's my understanding her. So she is, which is 63 45 So we know that they doubt has universe we. So Dr Hess System No doubt his so on down to his sarong. And this negative. That's a huge Oh, this used them. Well, let's see. Know which castle 5610 Joe's. Whoa, Temple jar Mistress 60 t. So this is your mind knows 21 points too. Use for Calvin. That's the doctor Has some surround them and it got a heads off. The system can be found by stay. Dr. G. Does it cost to get a hedge minus? Steve got hiss. We move. Got to keep it to remind us to team gills from all. And that's a hitch. This by six once, you know, use Moom honesty. Justice. To do what? Don't do this for you. 10. So we've got to Hess. I want to cheer Waas one Jules 71 more. So most disturbing is from a cyst. Now you got two hands, Universe, the question you but they have some assistance Sentence. You want one years for cow there? Lost? That's ahead of the story. Now what you want to do this job on this should be 0.8 two Jews counting. I want to be more explicit in District A mold once. Denver for move in this yesterday, the whole one hole.

So this is a lengthy problem. So for this problem, I find it easiest actually sketch out like a quick little heating curve because we need all of the parts of the heating curve here. We're starting below freezing quiet, and then we have to melt it, and then we have to boil it. And then we need to get above the boiling point. So we actually need to basically dio five separate calculations, one to get us to melt, one to melt, one to get us to boiling, one to boil and then the heat past boiling. So that's how I work on are going to break it down and then we'll add them all together. So for part one, and because it's all gonna be in solid, say we can use Q equals M C, Delta T or what's going on with ice. So we want to make sure we're using the specific heat of ice here. So we've got Q equals the mass of the water, which waas our using moles so that would be bowls of water. We have one more. It's gonna be 18.2 grams, just the molar mass times the specific e of an ice cube of 2.3 times the temperature change. And so it's just for this section. So it's just from final minus initial. So cue per step one ends up being 1.1 and at times 10 to the third jewels. So Step two is now the, uh, melting process. So this is actually a q equals, um, and Delta each fusion problem. So we've got our moles with just one mole times the heat of fusion for water, which was provided for you. We just had to put it into jewels before we plugged it into. Our equation equals 6.2 times 10 to the third jewels. We got steps. One step two. Step three We're gonna heat are liquid water up to its boiling point from zero degrees. So I've got another Q equals M C Delta T problem. So we still have 18 grams times a specific heat of water now, and we're going Teoh, raising the temperature by 100 degrees. So Q per step three is 7.53 finds 10 to the third. Jewell's Step four is another Q equals and but now it's H because we're doing the heat of vaporization. We've got one mole times the vaporization of water, which is 40 points of in times 10 to the third jewels for mall. So we have 40.7 ton Stender. The third jewels. I see you've got steps. 34 Lastly, Step five, we're going from boiling to, ah 140 degrees or raising the temperature of 140 degree or by 40 degrees. So mass is still 18.2 We're going to use a specific heat of steam, which is 2.2 times the temperature change 1.5 times 10 to 13 jewels on. Then the last stuff that we need to do is just add up all of our pieces. I think it's easier to deal with them. Is killer jewels. You may find it easier to do Obama's jewels, so we have them up his jewels. First it's 5.69 times 10 to the fourth jewels or 56.9 eligibles. Both would be correct answers


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