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12 Suppose we have the matrix AFind A? + 24 +1(b) Find A-!...

Question

12 Suppose we have the matrix AFind A? + 24 +1(b) Find A-!

12 Suppose we have the matrix A Find A? + 24 +1 (b) Find A-!



Answers

Find matrix $A$ if $$B=\left[\begin{array}{rrr} 4 & 6 & -5 \\ -6 & 3 & 2 \end{array}\right] \text { and } A+B=\left[\begin{array}{rrr} 6 & 12 & 0 \\ -10 & -4 & 11 \end{array}\right].$$

Okay for this problem. Looking at Matrix a part A. We need to identify The items that are in the first row. 2nd column, 1st Rosett columnist negative, too. A 21 2nd row. First column is negative. Four 3rd row. We're gonna have a 3rd row. Um So this does not exist. You can identify it because it's not there. And then Part B. They want a 11 which is one times a 22 which is five plus three. And then this is the sticking point. 2nd row, third column. There is no third column. So this does not exist.

Okay. All right, ladies and gents, we are trying to solve this problem. Are matrixes over here. It is a two By three Matrix as two rows, 3 columns. So part A. Just asked you to identify different parts of the matrix. So I want a 12 1st row, second column. That is the number two, A 21 2nd row, first column, which is four. A 32 is 3rd row, 2nd column. So are there three rows? You can't identify that because there isn't uh, A 3rd row. So there is no a 32 per B. I want to identify this term. So a 11 is one, A 22 2nd row. Second column is five plus three times A to three second row, third column, which is six. So we get five plus 18, which is 23. And so that's your answer for that problem.

In this problem. Our goal is to find Matrix A and we know matrix B and we know matrix a plus B. So let's go ahead and say that Matrix A has elements A, B, C, D, E f. And when we add Matrix B, which has elements for six negative five negative 632 We should get the Matrix with elements 6 12 0 negative 10 negative for 11. So a class B is equal to a plus B Now, when we had matrices, we had elements in, like position, so we would have a plus four equal six. And that means that a is to we would have B plus six equals 12 And that means that B is six. We would have c plus negative five equals zero And that means that sea is five. We would have d plus negative six equals negative 10 So d is negative, for we have e plus three equals negative for So that means e is negative seven and we have f plus two equals 11. So f his nine. So if I put this back into matrix format matrix a has these elements to 65 negative for negative 79

In this question, we have to find the determinant off the metric mhm. Minus e be minus B plant. Represent this metrics by a equals two metrics A minus, E b minus B. Now, in order to find the determinant off this metrics, we will expanded by first row determinant off equals toe multiplied by minus B minus minus A multiplied by B Simplifying it. We got minus a B plus a B. So the determinant off is zero. Thank you.


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