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Prupose a Keasondblc mcknalsm For" #e co(cing reactio)WLMbv(MzCKb CHbBr UlbMzc...

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Prupose a Keasondblc mcknalsm For" #e co(cing reactio)WLMbv(MzCKb CHbBr UlbMzc

prupose a Keasondblc mcknalsm For" #e co(cing reactio) WL Mbv (Mz CKb CHb Br Ulb Mzc



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licre the ycllow and orangc precipirares arc, rcspectively (a) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{-}$ (b) $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}$ (c) $\mathrm{Na}_{2} \mathrm{CrO}_{4}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$ (d) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$

Okay, This problem is asking us which of these molecules between all four of these is my m ing going to naturally to tomorrow's into. So let's go ahead and define a couple terms here. First off to Tom Rice or to Tamar Ization is essentially I saw memorization, right? Because whatever we have right here in this case, we have an I mean, the Tomur, the Tanamor is going to be in equilibrium. It exists in equilibrium with my I mean so in order to exist in equilibrium, that means that we're going to have basically the same atoms as we do in this. I mean, but just in a different order, right, we're gonna have different connections. Basically another item, er which is going to be called the totem. Or in this case, so we're looking among all these molecules, Which one has the same atoms just in different connections. So over here we have an oxide. Does this have the same number of atoms in the same type of atoms? The answer is no, because we have an oxygen here that is simply not a cook cook component of Miami. So this is not going to be an option. Next step. We have a hydro zone. Is this considered to be the same atoms as we do in my me? The answer is no. Because we have another nitrogen, right? We have the extra nitrogen. That is not a option. Next up we have this semi carpet zone. This is obviously not the right answer because this one has way too many nitrogen, right? We have one too many. This is not gonna be an option. The last option is my enemy. So does this have the same number of atoms? Same type of atoms and just in different connections? The answer is yes. So it's going to be my enemy. And what is that? Because if we're to simply use a base, for example let's go. You had a user base. My bass is able to Deep protein ate the aesthetic proton associative right here. So this is analogous to my alfa hydrogen usually associated with carbon nails. So I'm gonna take off the hydrogen. Moving the electrons onto this carbon or another way I can show is to move these electrons onto the single bond to create a double bond. As I do that, I'll have to move these electrons up to this nitrogen to produce this intermediate in which I have a nitrogen with a single bond because it has a negative charge. My method group right there and then my double bond right there. Right. So this is very, very similar to my enemy, which I have drawn right here. The only other thing missing is the presence of the hydrogen, which can simply be used over here. We have HB used from the protein nation of be in the previous step that can simply get pregnant by HB to eventually form my enemy shown right here. So this is a Tanamor because this exists in equilibrium, right? It just depends on the reaction conditions. But normally we're going to have my maybe the most stable form that is going to be the one that is present in the greatest excess, right? So enemy and I mean those are taught Immers, and they're going to exist naturally.

K two Cr awful gives a yellow precipitated it's a yellow policy heated on reaction with on reaction with Be a two plus, as well as B B two plus, therefore, option C and option the uh, correct answer for this problem, Option C and option B. R. Correct answer for this problem.

Hello and welcome to this video solution of numerous you have to tell how silver is refined. So silver is defined by the process known as which is a an option or sorry B accumulation. Mhm. No this is a process that takes place at high temperature. Okay hi to Britain and controlled operation to separate noble metals okay like gold, silver and other base metals. How noble metals like gold, A. G A. U. School, silvery and base metals like lead PB. See you like this and maybe you think we can say think yeah and which are present in that alloy right from which you can actually have beautified a refined silver. I hope this is clear to you and have a very good rest of the day.

In this problem, k i and KI 03 odd the service stance used for preparing used for preparing. I would I'D so g i N, The I 03 used for preparing iodized salt so it's an A and B are correct here. The airport option A and D r correct answer for this problem.


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