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Based 01 acid base equilibria: HzPO4 T HSO4 HzPO4 + SO4 Identify the base-conjugate acid pair in the reaction....

Question

Based 01 acid base equilibria: HzPO4 T HSO4 HzPO4 + SO4 Identify the base-conjugate acid pair in the reaction.

Based 01 acid base equilibria: HzPO4 T HSO4 HzPO4 + SO4 Identify the base-conjugate acid pair in the reaction.



Answers

Challenge The products of an acid-base reaction are $\mathrm{H}_{3} \mathrm{O}^{+}$ and
$\mathrm{SO}_{4}^{2-}$ . Write a balanced equation for the reaction and identify the
conjugate acid-base pairs.

Here we have three different reactions, and we're going to identify the Bronson acid, um, base and each reaction in their Condi It partner. So we're going to start with this first reaction. We have eight C A to H with writing with H 20 which yields a zero to minus and H three or plus We know that a Bronson acid is a species that donates a proton razor. Bronson bases a species and accept approach. Exception proton. So here we can see that H c O to H donated proton to eat shuo to become H 20 to minus. So you know that HCIA to H is the acid and h c o to minus is It's conjugated it biggest well, it's too. Oh is the base and it's 30 plus is it's conjugated acid moving on to the next reaction. We have NH three ratting with H two s, which yields NH four plus an HS minus. We can see that NH three is accepting a proton to become NH four plus so therefore, any three is the base and NH four plus is it's conjugating acid. Well, age to us is the acid because it doe not donated to pro time while HS minus is it's conjugated base. In our file reaction, we have hs 04 minus reacting with O h minus and we see the hs A for minus donates proton to become s 04 to minus So hs a four minus is the acid while s 04 to minus is it's conjugated base and O h minus is the base Well h 20 is it's conta Get acid!

The first reacted is that seal on the last product is conjugated based off glory negative and the second reactant is conjugated based off an edge for positive. Therefore, the Bronze State Glory Asset base and conjugated base pairs are it's Ian Less image. Three gifts. An itch for positive bless clearly negative. So a seal will be acid and the three will be based image. Four will be acid on dhe. Chlorine will be based.

The question is identify the brown straight acid or base in the given reactions. So we are going to discuss how can we identify which is brown straight acid or Brown street base. As we know that Brown street as it is a proton donor and bronze to the base is a proponent except er in the chemical reaction. So in the first part activation is and I less water liquid and that gives as to you plus plus minus plus. Okay, now we can observe carefully that in H I there is a huge plus iron which is present and in a water molecule there is a long pair of electrons so it can donate long bear or it can gain H plus it can accept H plus from a child. Okay, so actually will be acid and water molecule will be based in B reaction. We have a two C two H three or two plus H. S minus and we get H two s plus si two S three or two minus. Okay, now, in this reaction, acidic acid will be a acid and h S minus will be our best because H. S minus accept protons from ascetic acid. Okay.

In order to answer this question, we simply need to be able to identify what is the acid and what is the base? The acid is going to be something that donates. Ah, hydrogen ion. The base will be something that accepts a hydrogen ion. We also need to be able to identify what is soluble and what is not soluble based on some soluble ity rules. In order to determine the Net Ionic equation, those things that are soluble or strong electrolytes will completely separate into their corresponding ions. So for this first equation, we'll rewrite it here, as given to us. We recognize that the hydrogen sulfate is donating a hydrogen ion, and the, um, hydroxide is accepting the hydrogen ion. So the H two s 04 the acid in the calcium hydroxide is the base sulfuric acid. H two s 04 is a strong electrolyte, just the first hydrogen. So it will completely disassociate into H plus in H s +04 minus calcium hydroxide is a relatively moderate base. It's not very strong, but because it says solid here, I'm inclined to keep it as a solid here. But the calcium sulfate is soluble according to the soluble ity rules. So it'll separate into calcium ion and sulfate. Ion and water will stay as a liquid. If the concentration of calcium hydroxide is very low, then it actually will completely separate. So depending on whether we have a high concentration or a low concentration, we could write the Net Ionic equation this way where the calcium would cancel for the next one. We have lead two carbonate reacting with sulfuric acid. So sulfuric acid is theus it and lead two carbonate is the base lead. Two carbonate stays is a solid. The H two s 04 as above separates into H plus and H s +04 minus. The lead to sulfate is a solid according to Saudi ability rules. So this would be our net ionic equation for the next one. We have calcium hydroxide reacting with acetic acid. Calcium hydroxide does not separate well, so we'll keep it as a solid this time. Acetic acid is a weak acid. So we have our acid here and our base here weak weak acids or weak electrolytes that do not completely disassociate. So when we write the Ionic and the Net Ionic equation we keep everything together for the calcium hydroxide and for the weak electrolyte acetic acid. Then, according to Saudi ability, rules re recognize that calcium acetate does completely dissociated in tow one calcium mine and to acetate and ions. This would then be the Net Ionic equation.


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