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Enter electrons a5The following skeletal oxidation-reduction reaction occurs under basic conditions. Write the balanced REDUCTION half reactionNi(OH): SO}SO;" ...

Question

Enter electrons a5The following skeletal oxidation-reduction reaction occurs under basic conditions. Write the balanced REDUCTION half reactionNi(OH): SO}SO;" NiO:ReactantsProducts

Enter electrons a5 The following skeletal oxidation-reduction reaction occurs under basic conditions. Write the balanced REDUCTION half reaction Ni(OH): SO} SO;" NiO: Reactants Products



Answers

Balance each of the following oxidation–reduction reactions, which take place in acidic solution, by using the “half-reaction” method.
$$
\begin{array}{l}{\text { a. } \mathrm{I}^{-}(a q)+\mathrm{MnO}_{4}^{-(a q)} \rightarrow \mathrm{I}_{2}(a q)+\mathrm{Mn}^{2+}(a q)} \\ {\text { b. } \mathrm{S}_{2} \mathrm{O}_{8}^{2-}(a q)+\mathrm{Cr}^{3+}(a q) \rightarrow \mathrm{SO}_{4}^{2-}(a q)+\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q)} \\ {\text { c. } \mathrm{BiO}_{3}(a q)+\mathrm{Mn}^{2+}(a q) \rightarrow \mathrm{Bi}^{3+}(a q)+\mathrm{MnO}_{4}^{-}(a q)}\end{array}
$$

In each part of this problem were given an unbalanced Redox reaction. And for each one of the given reactions, we need to balance it using the half reaction method. So starting with the reaction given in part A, you first need to split up the unbalanced total reaction into 2/2 reactions. The way that we do that it was, is that we split up the oxidation and reduction reactions so chromium is oxidized in nitrogen is reduced. So that's how we know that these are the two half reactions. And now, in order to balance each one of the half reactions and then add them together, we first need to balance all of the atoms that are not oxygen or hydrogen. And then we need to balance the oxygen's with water and the hydrogen is with H plus. Since we're in acidic solution, then after that we need to balance the charges and then we can add the 2/2 reactions together to get the total balanced reaction. So starting with the oxidation half reaction above, we see that the chromium zehr balanced and we have no oxygen's or hydrogen, so we just need to balance the charges the reactive side has a charge of zero. The product side has a charge of three plus, so we need to add three electrons to get a charge of zero on each side. And now for the other half reaction, we see that we have one nitrogen on each side. So those air balanced and we need to balance the oxygen's with water. So if we add to liquid water on the product side, we can see that we now have a total of two oxygen, a total of three oxygen atoms on each side of this reaction. In essence, we're in acidic solution. We need to balance out the hydrogen is that we introduced from water with H plus. So we have four. Hydrogen is from water, so we need for equals H plus ions, and now we need to balance out the charges. On the left side, we have a total charge of plus four plus negative one from an +03 so total of plus three. And on the product side, we have a total charge of zero. So we need to add three electrons to get the charge on the left side from plus 3 to 0. And now that we have balanced both of the half reactions, we can add them together to get the total balanced Redox reaction we can cancel out. There's three electrons on either side of the reaction arrow. We can get our final balanced reaction to be for each plus yanquis. Plus I know three minus equally ists plus chromium solid goes to chromium three plus Aquarius, plus a no guess plus two liquid water. Now we can see that all of the Adams and the charges are not are now balanced. So this is the final answer for the balanced Redox reaction. Now we use that same method to get work through Parts B and C for Part B. We split up the 2/2 reactions again, and we start by bouncing the top one, and we see that we have one carbon on each side, so that is balanced. And now we need to bounce out. The oxygen's with water and we can add liquid water to the left side, and that will give us a total of two oxygen atoms on each side. So now the oxygen's air balanced, and now we have a total of two plus three plus one. So six hydrogen ins on the left side. So we need six h plus against. Since we're in acidic solution, we need to balance the hydrogen is with H plus and now we need to balance out the charges and we see that on the left side there is a charge of zero in on the right side gave a charge of six plus. So we need to add six electrons to the product side to get aid charge of zero on each side. And now for the other half reaction, we just have CE and so the Adams air balanced. And now, in order to balance the charges, we need to add an electron to the four plus charge to get a charge of plus three on each side. And now we add these two reactions together. But notice that we need to cancel out the electrons and we have one electron on the reactant side from the second reaction, and we have six electrons on the product side from the first reaction. So we need to multiply the second reaction by six, and then we can add these two together. So if we multiply that second reaction by six. We now have six elect electrons that we can cancel out on each side, and we can begin to write out our overall balanced reaction each to oh Liquid was ch three. Ohh, Equus plus And remember, Since we multiply that second reaction by a factor of six, we now have six C four plus acquis and for the products we have again from multiplying the second reaction by six, we have six C three plus Equus Plus Co. Two Equus plus six H plus Equis. So that's the final balanced Redox reaction for the given reaction in Part B, and now we do the same thing for part C. We have our reaction given in the problem, and we split it up into the 2/2 reactions. And so, starting with the the first reaction, we can see that the sulfur zehr balanced and we need to balance the oxygen's with water. If we add water to the react inside, we have a total of four oxygen's now on on each side of the reaction, and we have to hydrogen on the left side that we need a balance out with to H plus ions on the right side and now we can balance out the charges. We have a total charge of minus two on the left side and a total charge of minus of of zero on the product side. And so we need to add two electrons to the product side to get a charge of minus two on each side. And now for the other half reaction. See that man Younis is balanced and we need to bounce out those four oxygen's with four waters and now we have 888 Hydrogen is from the four. Water is that we need to bounce out with eight h plus ions and now we bounce out the charges we have on the left side eight plus and minus one. So a total charge of plus seven on the reactant side, On the product side, we have a total charge of plus two should get from plus seven to plus two. We need to add five electrons. And now when we add these two together, we need to cancel out the electrons so we can multiply the first reaction by five and the second reaction by two so that we have 10 electrons cancelling out on both sides. And so now we can go through and write out the final reaction. So we want to play that first reaction by five. So we have five s 03 tu minus acquis. And for the H plus ions, we see that we have a total of eight on the reactant side, times two so 16 and to times five So 10 on the product side. And so all of the products will be used up and we'll be left with a net of six h plus on the react inside and from the second re actually multiplied by to sue two mn 04 minus Equus. And then on the product side, we have to and then two plus after multiplying that second half reaction by two. And for the waters, we see that we have four waters times two so total of eight on the product side and one water times five. So a total of five waters on the reactant side. So we have eight waters on the product side and five on the reactive side. So all of the reactant waters are gone and we're left with three waters for a product. So plus three each to a liquid and then was five s 04 tu minus a quiz. And that's from that first reaction, multiplying it by five. So that is a balanced Redox reaction. Were they given reaction and part C.

Electoral chemistry in this podcast, Siris on what we're mostly looking at is how we're able to balance some unbalanced chemical equations and then following this identify the oxidation on reduction part. So in the first example we have, we have our oxidation part of the reaction that is province three p of 34 minus generates three p o for three miners at an electron. So we know that that is an oxidation reaction. The second half of this is M and oh, four minus. And then we need Thio ad for H plus Add three electrons gives us M N 02 to H 20 That is our reduction part. So now we can balance this equation and completed and other altogether you have three p 03 four minus at M N 04 minus at four h plus. That is a good rumors three p both for three miners at, um and to to h 20 Okay, so I'm moving on to the next example, So we'll write out the full equation this time that is balanced. Now we can identify oxidation reduction components where we have our oxidation. That is M G to H 20 generates M g O H two to H plus two electrons and are reduction component that makes up this balanced equation. At the top, we have O C L minus two h plus to the minus. You can see that this thes two oxidation reduction reactions do couple quite nicely on we got C l minus at H 20 now for the next one. What we have is H two c o to H 204 a g NH 33 plus a queer state that is an equilibrium with H c o three minus at five. H plus add four h g at 12 and H three so we can identify oxidation reduction components. We have our oxidation reaction occurring with the H two c o on our reduction, but this material

Let's balance the following oxidation reduction reactions that occur in acidic solution. Using the half reaction method to use the half reaction method, we have to separate into two half reactions a reduction, half reaction and not reaction and used the major ohh method for balancing For a we're gonna split 7 to 2 half reactions. Balance the major and we have minus three on the left, minus one on the right. Add two electrons to belts charge and we'll have C O minus two C minus. The major chlorine is balanced. Add H 20 to balance the oxygen and to H plus to balance the electrons and a two electrons to balance charge. Uh, two electrons will cancel and we will get three. I minus. Add Cielo minus two h plus to I three minus at C l minus at H 20 And there is our balanced half reaction in acidic solution for be one half reaction with a S 203 two h three e s 04 Arsenic is there a major Adam will put a to hear develops that That gives us two arsenic on each side at eight. Oxygen on the right hand side three oxygen on the left. So I need five h 20 for eight. Oxygen on each side. 10 hydrogen on the left, six hydrogen on the right. So I need four h plus to balance that to balance the charge at four electrons, second half reaction and all three minus two an O major nitrogen is balanced. Three oxygen on the left, one oxygen on the right. So two H 20 to balance. Have the oxygen for hydrogen on the right. So I need four hydrogen on the left and charge here plus three. So I need three electrons to balance the charge. Now we need to multiply by a common factor of the electrons on. I'm gonna multiply the oxidation. Half reaction common multiple is 12. So times three times four Let's rewrite thes here multiplying by three. I get 15 h 20 three a s, 203 26 h three a s, four. 12 h plus 12 electrons and multiplying by four would give me four times three is 12 electrons, 16 h plus four and all three minus four and no h 20 cancel out the electrons 12 on each side. I can simplify the hydrogen. Za sees me with four here, simplify the waters issues us seven here. And my final balanced equation is three s 203 at 403 minus add four each plus at seven. H 20 26 h three e s 04 and for And Oh, and there is my balanced Redox reaction. Percy. First half reaction would be B R minus to be our to balance the major balance. The charge second half reaction is Emma No for minus two mn two plus Mangin eases balance on both sides. Four oxygen's on the left. So four h 20 on the right. Eight hydrogen is on the left. So eight h plus on the right. So left there. Charge is seven plus two. So five electrons on the left would give me a charge of plus two plus two rates now will multiply electrons common multiple is 10, sometimes five and times to let's rewrite thes. Here I'm gonna have 10 b r minus 25 B R. Two at 10 electrons and doubling. This one is 10 electrons 16 age plus to M N 04 minus two mn two plus and eight h 20 Cancel out the electrons and my balance equations 10 br minus to elemental four minus at 16 h plus going to five b R two two mn two plus and eight h 20 on theirs are balanced equation for C for D first half reaction of ch three O h two C h 20 carbon is balanced on each side. I've got oxygen one on each side, hydrogen four on the left to on the right. So I need to h plus balance is charged two electrons. The next half reaction is dead crow mates here are 207 to minus two chromium three. Plus I needed to hear it amounts to chromium seven h 20 on the right, 14 age plus on the left and I have plus six on the rights plus 12. So I need six electrons to balance the charge here. I need to multiply. Common multiple is six groups, so we're gonna multiply the first half reaction by 33 ch 30 h 23 c h 20 and six h plus and six electrons. The second half reaction is multiplied by one. So as is electrons will cancel. Uh H plus will simplify to leave me with eight there, and our balance equation is three c h +30 H at crow Mates at eight h plus two, three ch, 20 two chromium three plus and seven h two hole and there is my balanced redox reaction for D.

All right, So we're given six different metals and noticed the way arrange them is because a C M e r rolling group to which means they're all gonna be positive, too elements or medals in this case, which means that there are going to behave the same way. So once we figure out A which is the same thing with C and E, which has changed the medal on the same would be Deanna there will, plus one their own group one. So that charge is gonna be plus one, which means they're gonna behave the same way. The only thing that changes is the metal, right? So the idea of this problem is, we have we're gonna take the medals and reacted with non metals and a type of synthesis reaction, which is a type of reductions, which is a reduction oxidation reaction and we're gonna do is we're gonna take the metal, combine it with the nonmetal. And were you meant gonna make that I had a compound, right? So what's gonna happen is the metal's gonna transfer its elections to the known medal. And in order for you to get this compound, you're gonna have to do charges. So you're going to see some scripts here? Do not transfer them here. Just put them together and then cross the charges and I'm gonna show you what that means. So we have older metals like now. Now we just need the non metals and non metals that we're gonna use is we're gonna use oxygen. Us So too is that Tomic? Sulfur, chlorine, nitrogen and grow Me and those are the atomic meaning They're in pairs when they're by themselves, right? So for his not but glowing magic number mean an oxygen. So here's we're gonna do again. If you saw a and B then see it, the enough should be pretty easy. Just copy. Um just change the metal on. The reason we can do that is because bear magnesium in costume and behave the same way. Since they're all in the same family and potassium beating Maliki and we have the same way with the non medals since they're all in the same family. So we're gonna start with barium, so we're gonna react. Bear him with oxygen gas and you're gonna put it together without the suckers. So it gives you be able and The reason we do without subscript is because we have to be charges Barium has a charge of plus two. Oxygen had a charge of negative too, since their bold the same charge. We do not do anything right. That means herbarium gets up to elections and oxygen gives up needs to elections. So games two electrons. Well, we have to. The next is we have to balance it and to balance said we look oxygen's on the react inside us to oxygen in the products that it's one. So we multiply this by two. That gives me to oxygen to bury ums. So I put it to right here. Next we do barium with sulphur and against as b a s right. We do the same thing. We didn't move any subgroups. So either charge is very Miss Pasu. So for his negative to they don't do anything we have to balance. Now we have one barium on the reactor inside won't be room on the product side. Once over in the react inside, one sold for in the react on the product side. Next we do says balance like to do barium and chlorine. So we just do B A c l. And then we have to do charges. Barium is plus two clawing as they get it once. Since they're not the same re crust, we put a one here. We should don't do anything with once. And then we put it to here, so literally cross your charges. So that's who will go there. That one were there. Get rid of the positive and the negative. And then we bones. We have two Koreans here, too, including here on barium here. One bedroom here. So that's builds. Then we have next we have with nitrogen, Gus. So we'll give you B a n and then we do charges Barium has a charge of plus soon Natural House Church Negative three. But three crosses Tagore here and not two crosses to go here across crust. And now and now we bounce. So now we have to nitrogen some bold size three Buriram's on the product side, so I need three Buriram's on the reactor inside, and for the last one, we do it with beer, too. We do a synthesis redox reactions with beer to still give you barium bromine, and then we cross charges. The charge O'Berry amiss. Plus to the judge of roominess thinking of one to cross crust what it to hear, Hear rid of your charges, and then we balance to grow Means to bro means one barium one. Very not now that we figured that out. And we know my knees, um, in calcium there on the same group, they behave the same way All gonna do? No, it just copy the same equation balance at the exact same way. And then that would work because they're giving up the same number of electrons, so they're interacting xx and way as very amiss. So we just have to you make it look the same, right? And then we do the same with sulphur. Just make mgs and then we do the same with chlorine makes and g seal to sonar does. That looks exactly the same. And it should, because they're in the same group. That idea of being on the same group there, in the same family, which means that they react the same way and this is only applicable for group one and group, too. And then we balance plus last one beer too. And once you know this trick it's really helpful, right? Makes things go much further. And then let's do the same with calcium. So we balance. We need to Coliseum's for an oxygen, and it makes to see a oh, and then we do plus sulfur. And again they look this You look just like this, right? Except But instead of barium, we do calcium men plus yield to we'll give you see a seal, too, plus nitrogen gas give you see a three and two and then two bones that when you three here Buzz beer too. We'll give you see a purity. All right. Now we do potassium, rubidium and lithium because they're all under one. So we just need to solve one to see what it looks like and it just copy it with the other metals. So we do potassium plus oxygen. Guess Well, you ko remember, move it without the sub scripts and do charges. Potassium charges plus one oxygen. And they have to cross that two goes right here. Get rid of the charges once you use them, or once you figure out that you don't need them, and you have to oxygen's on the products to accident in the react inside. So I need to oxygen the products that of someone like to not have four potassium. So put a four right here. All right, then we go to sulfur, it gives you ks and then do charges. So potassium was plus one so far is negative. Two crust says they're different. And then again, we don't do anything with once. And then we balanced. I have one sold for one. So for two potassium. So I needed to right here. Then we go to chlorine, gives UK CEO and then do charges. Potassium is plus one. Cloning is thinking of one. So we don't anything with the charges just to raise them. And then I have to corns in the reactor inside any to Corning's. On the product side 90 have two, according to potassium on the product side. So I need to potassium on the reactions. And then we go to the next one, which is nitrogen gas, which is give us Kate and do your charges. Potassium. This plus one nitrogen is negative. Three. So put a three right here. Once you cross them, get rid of the charges. I have to. Nitrogen is here, so I need to nitrogenous here. So multiplied by two Now have six potassium, some products I have. So I need six potassium on the reactant and then lost. But not least, we have brought me It just gives us KBR. And then we do charges for minutes plus one. Oh, minus one. And the potassium is plus one cross. They're gonna be the same. We have to, bro means on the reactor inside. We need to Browning's on the product side. So we're gonna multiply, like to not have to. Potassium zai have to protest. And now, since we we figure out the same that pattern repeat here, the pattern will also repeat for the group one elements. So I'm gonna do is just make it look the same just with the friend middle. So I'll give you two r b 20 and then the next one revision right of first on balance that it would be easier. So we are B two s and then put you here Notice that it should look the same plus seal too. Give you R B C l. And then it should be 212 to 1 to and then plus and two, we'll give you our be three in and then to balance that, I should be 612 and then Klaus beer too. I would give you R b br and then to balance should be to one to also just really quick. If you look add chlorine and brahmi, they're in the same group there Will that Tomic and noticed that the reaction looks very, very, very similar. Right? What you're changing is a non metal. So for the group 17 it looks so for flooring. Chlorine, bromine, nine line The reactions are gonna look very similar. So just like one and two They behave in a very similar matter. So now we have lithium plus oxygen. We give you a light too. Oh, and we balance that or two here on a four. Here again, if you look the same since they're in the same group less sulphur, it gives you a light to us two here, 211 us glorying should be ally CEO. So put it to here to here to make it look like those plus the nitrogen. And again, I'm doing this because leafy and weedy a member task you were in the same group and then and you can only buy Italy only do is a group warning to Is that because they're the only ones that have the same study? Number of elections they was.


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