5

4.Arestaurant uses the ratio method of pricing: It has annual nonfood costs of S800,000 and desires a profit of $150,000.Last year the restaurant spent S400,000 on ...

Question

4.Arestaurant uses the ratio method of pricing: It has annual nonfood costs of S800,000 and desires a profit of $150,000.Last year the restaurant spent S400,000 on food costs What will be the selling price of an item with food cost of $5.00? (6pts)

4.Arestaurant uses the ratio method of pricing: It has annual nonfood costs of S800,000 and desires a profit of $150,000.Last year the restaurant spent S400,000 on food costs What will be the selling price of an item with food cost of $5.00? (6pts)



Answers

A catering company estimates that, if it has $x$ customers in a typical week, its expenses will be approximately $C(x)=550 x+6500$ dollars, and its revenue will be approximately $R(x)=1200 x$ dollars. (a) How much profit will the company earn in 1 week when it has 12 customers? (b) How much profit is the company making each week if the weekly costs are running at a level of $$\$ 14,750$$ ?

Let's talk about question. About 26 were given the cost off a catering company, uh, the expenses off a catering company, which are Lieutenant C X as 5 50 x plus six five double zero. Well, it's revenue is 1200 x dollars x are the number off customers. In a typical week, Party asks about the prophet look, of which the company will on and one week if it has 12 customers. So first of all, the profit has given by a revenue minus cost or revenue is 1200 x minus. If we do the cost and the cost of hers would be 1200 X minus 5 50 x plus 6500 eso. This comes out as 6 50 eggs minus 65 double zero. But we're already given that the number of customers are, uh, well. So for 12 we substitute X as well. So we get the final valuers 1300. So this is the profit and part B. It says that it z weekly cost are given, so let's right that we already know the cost function on the weekly cost will substitution that. So that is 14750 This is the weekly cost. It has given us 5 50 x like 650 So from here, if it's attracted 6500 both sides, we have 14750 minus 65 Double zero is 5. 50 x. So from here, the value of X By dividing by 5. 50 both sides, it is 14750 minus 65 double 0/5. 15. So the value of X from here comes out us. You are, uh, no. Off these customers, we need to find a profit on. We already have the equation off profit, which is 6. 50 x minus 6500. So the prophet will be 6. 50 eggs that excess 15 minus 6000 500. So this comes out us three to 50 dollars. So this is the profit

All right. So the cost function a restaurant is given by sea X y equals one forest X squared plus for ex plus two I squared. Plus why? Plus 10. Okay. And we want to find the okay. So X is the cost of labor. Why is the cost per dish? And we want to find the average cost per hour on this interval. So costs per hour ranging between 30 and 60. Mm. Cost per dish ranging between 15. 80. Okay, so we need to divide by the area of the region we're integrating over, which is just this rectangle. So 30 by 30 squares, that's nine 100 that will divide by so one over 900. And then we'll integrate secret up to 60. Integrated zero. Yeah, 30 to 60. There you go. And then 50 to 80 and we have 1/4 squared. Plus four x plus two. I squared, plus y plus 10, the y the X. All right, warned over 900. Okay, so we need an anti derivative with respect to why. So I'll be 1/4 x squared y plus four x y plus two thirds. Why cubed plus one half y squared plus 10. Bye. Evaluated from 50 to aiding. All right, so let's go over here. So we have one over 900? No. And then in your girl, 30 to 60. Mm. Okay. One for us. So these wise will all just get a factor of 30. Said that will be 30 over four x squared, and then we'll have 30. Everyone 20 x. Yes. Okay, two thirds yq. So why cute? We're going to do. Let's see. 80 cubed. Minus 50 cubed. So that is any cube minus 30. Cute. Mhm. Mhm. Okay, so 387,000. And then all times two thirds. 258,000. Okay. And then one half of okay, y squared. So they got to do 80 squared, minus 50 squared and then divided by two. Okay, 1950. And then plus 300. Okay, anti derivative time. One over 900. This is going to be 10/4 X cubed plus 60 x squared plus 258,000 us. Uh, sorry. 210,000 x was, and we can actually just add all these together might be best for now. So 258 1000 plus 1950 was 300 is 260,000. 250 x evaluated from 30 to 60. So this one is going to be easy. We're just gonna multiply this one by 30. So that's seven 807 500. Yeah. Okay. Stood on this one over 900. Right. We need to do 60 cubed, minus 30 kids, times 10 over four, 472 1005 100. And then we needed to six a C 60 squared, minus 30. Squared, right times 60. That's 100 62,000. Okay, so it had these up work. 200 seven 807 100. Okay. Got 8,442,000, and then we'll divide by the area 900. So we get the average cost. 9000 $380. Oh,

Okay, then we have advertised in a newspaper that's two by four cost $36.75. And that's based on the size of the ad that says you want. So double the length and with sir going from two by 4 to 4 by eight. Okay, so if we just find the area of these two shapes, this area would be eight, plus the units on this inches so eight square inches for $36.75. And this new, its new ad would have an area of four by eight, just 32 square inches, so we can see that the area is four times as much now. And since the cost is based on the size are new costs would be $36.75 times four, he says, four times as big costs four times as much. And that's gonna work out to $147. Even make sure you answer the whole question. Yeah, that's it. So his new advertisement, if he doubles all the sides before times as much as the original or $147 There you go

Here we have the equation in equals selling price minus cost. So we do selling, which is 2231.81 minus 16 53.19 in ruinous attract. So that gives me seven 11. Minus nine is to someone's with six 11 minus three. It's eight 12 oneness by yes, seven and then, so the answer is 178 point 62.


Similar Solved Questions

5 answers
Ore:1203/1800ResourcesGive Up?Hintsf 18Consider the reaction.2 Pb(s) + 0_(g)2 PbO(s)An excess of oxygen reacts with 451.4 g of lead. forming 345.6 g of lead(I) oxide. Calculate the percent yield . ol the reaction:percent yield:
ore: 1203/1800 Resources Give Up? Hint sf 18 Consider the reaction. 2 Pb(s) + 0_(g) 2 PbO(s) An excess of oxygen reacts with 451.4 g of lead. forming 345.6 g of lead(I) oxide. Calculate the percent yield . ol the reaction: percent yield:...
5 answers
Draw graph of the ceilivg function for I 0 <I < OH thle graph below.
Draw graph of the ceilivg function for I 0 <I < OH thle graph below....
5 answers
Find the domain of the following function.X+4y = 2 15 - Vx - 64
Find the domain of the following function. X+4 y = 2 15 - Vx - 64...
5 answers
Un17052anicwin-YfnlIu(cuwScni LidOru1ne4AhTanc KknEenentany Sthintlcs (Fall 719/74 031Homework: Section 3.1 Homework Score: 0 Cilct ComccintHw Scorc: 1596, 3 0 20 pt3.1.13 mncntOennWttnGun €(ennh] und thm undamtF MTn mctetn; 6TtDcrrlnasy "0lna)NSaaStaid
Un 17052anicwin-Yf nlIu(cuwScni Lid Oru1ne4Ah Tanc Kkn Eenentany Sthintlcs (Fall 719/74 031 Homework: Section 3.1 Homework Score: 0 Cilct Comccint Hw Scorc: 1596, 3 0 20 pt 3.1.13 mncnt Oenn WttnGun € (ennh] und thm undamt F M Tn mctetn; 6 TtDcrrlnasy "0 lna) NSaaStaid...
5 answers
Determine the internal normal force, shear force, and moment at point $C$.
Determine the internal normal force, shear force, and moment at point $C$....
5 answers
1081) Consider the function f(x) 108a) Find the instantaneous rate of change of f (x) atx = -3_ {10 pts}b) Find the equation of the line tangent to f (x) at x{10 pts}
108 1) Consider the function f(x) 108 a) Find the instantaneous rate of change of f (x) atx = -3_ {10 pts} b) Find the equation of the line tangent to f (x) at x {10 pts}...
5 answers
Will the solution be different? If yes, what is the new solution? If nor, explaim why
Will the solution be different? If yes, what is the new solution? If nor, explaim why...
1 answers
A voice signal occupying the frequency band of 0.4 to $3.5 \mathrm{kHz}$ is used to amplitude-modulate a $10-\mathrm{MHz}$ carrier. Determine the range of frequencies for the lower and upper sidebands.
A voice signal occupying the frequency band of 0.4 to $3.5 \mathrm{kHz}$ is used to amplitude-modulate a $10-\mathrm{MHz}$ carrier. Determine the range of frequencies for the lower and upper sidebands....
5 answers
Question 200 ptsBAT 4J,4E. Nitric acid is 68.0% HNOz by mass and has density of 1,42 g/mL What is the molarity of nitric acid (MM 63.02 g /mol)?15,3M HNOg1.53M HNO;10.8M HNOg1.08 M HNO]
Question 20 0 pts BAT 4J,4E. Nitric acid is 68.0% HNOz by mass and has density of 1,42 g/mL What is the molarity of nitric acid (MM 63.02 g /mol)? 15,3M HNOg 1.53M HNO; 10.8M HNOg 1.08 M HNO]...
1 answers
Prove that the result of exercise 27 is always true by showing that $\int_{a}^{b}[f(x)-A] d x=0$
Prove that the result of exercise 27 is always true by showing that $\int_{a}^{b}[f(x)-A] d x=0$...
5 answers
Explain how to simplify a rational expression.
Explain how to simplify a rational expression....
5 answers
If a gumdrop is 2.0 cm^3 in volume, what wouldthe volume of an Avogadro number of raindropsbe?If a raindrop is 0.0951 cm^3 in volume, whatwould the volume of an Avogadro number of raindropsbe?
If a gumdrop is 2.0 cm^3 in volume, what would the volume of an Avogadro number of raindrops be? If a raindrop is 0.0951 cm^3 in volume, what would the volume of an Avogadro number of raindrops be?...
5 answers
Which of the following series converge?C m =12 m = Iln3.1. 2 m =1+ 1Select one:nonc. 2d. 3
Which of the following series converge? C m =1 2 m = Iln 3.1. 2 m =1 + 1 Select one: non c. 2 d. 3...
5 answers
Explain why an alcohol, such as ethanol, is soluble in water buthydrocarbons such as alkanes are not soluble in water
Explain why an alcohol, such as ethanol, is soluble in water but hydrocarbons such as alkanes are not soluble in water...
1 answers
In Fig. $35-45,$ a broad beam of light of wavelength 683 $\mathrm{nm}$ is sent directly downward through the top plate of a pair of glass plates. The plates are 120 $\mathrm{mm}$ long, touch at the left end, and are separated by 48.0$\mu \mathrm{m}$ at the right end. The air between the plates acts as a thin film. How many bright fringes will be seen by an observer looking down through the top plate?
In Fig. $35-45,$ a broad beam of light of wavelength 683 $\mathrm{nm}$ is sent directly downward through the top plate of a pair of glass plates. The plates are 120 $\mathrm{mm}$ long, touch at the left end, and are separated by 48.0$\mu \mathrm{m}$ at the right end. The air between the plates acts ...
5 answers
16.Draw the acetal fonned in the following reaction(Spts)CH? CH3Hgc _2 HOCH CH,OH
16.Draw the acetal fonned in the following reaction (Spts) CH? CH3 Hgc _ 2 HOCH CH,OH...

-- 0.017872--