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Determine which of the statements below are true for a Galvanic (or Voltaic) cell that measures a positive cell potential. Select ALL that apply:The Standard Free E...

Question

Determine which of the statements below are true for a Galvanic (or Voltaic) cell that measures a positive cell potential. Select ALL that apply:The Standard Free Energy value for this cell will be negative.The cathode solution will e decrease in charge.Anions in the salt bridge will travel toward the cathode:The oxidizing agent reacts at the cathode_Electrons will travel from the anode to the cathode through the wire:LiCIO4 would be a good option for the salt bridge solutionThe equilibrium cons

Determine which of the statements below are true for a Galvanic (or Voltaic) cell that measures a positive cell potential. Select ALL that apply: The Standard Free Energy value for this cell will be negative. The cathode solution will e decrease in charge. Anions in the salt bridge will travel toward the cathode: The oxidizing agent reacts at the cathode_ Electrons will travel from the anode to the cathode through the wire: LiCIO4 would be a good option for the salt bridge solution The equilibrium constant for this cell will be a small value (< 1). The oxidation half reaction occurs in the anode compartment The anode electrode will gain mass.



Answers

Of the following statements concerning electrochemical cells, the correct ones are: (a) The cathode is the negative electrode in both voltaic and electrolytic cells. (b) The function of a salt bridge is to permit the migration of electrons between the half-cell compartments of an electrochemical cell. (c) The anode is the negative electrode in a voltaic cell. (d) Electrons leave the cell from either the cathode or the anode, depending on what electrodes are used. (e) Reduction occurs at the cathode in both voltaic and electrolytic cells. (f) If electric current is drawn from a voltaic cell long enough, the cell becomes an electrolytic cell. (g) The cell reaction is an oxidation-reduction reaction.

This question has several statements for which you need to determine whether they are true or false. The first one statement a says the cathode is the negative electrode in both voltaic and electrolytic cells. This is false. The cathode is going to be positive in a voltaic cell, but negative in an electrolytic cell. Why? Because electrons are always negative, they will always flow towards the more positive electrode. So the science need to be switched in order to allow the electron flow to change in a voltaic versus an electrolytic cell. The next statement B. The function of assault bridge is to permit the migration of electrons between half cell compartments. This also is false. Electrons flow through the metal connectors. They do not throw flow through solutions. The purpose of the salt bridge is to allow the flow of ions, not electrons. The next statement see, the A node is negative in a voltaic cell. This is true, as we just discussed above the an ode, however, would be positive. In an electrolytic cell statement, D electrons leave the cell from either the cathode or the anodes depending on what electrodes are used. This is false. It doesn't matter whether what electrodes are used, whether it's a galvanic or an electrolytic cell. Electrons always leave the anodes always, because that's where oxidation is occurring, and only through oxidation can you provide a supply of electrons. Statement. E reduction occurs at the cathode in bolt, voltaic and electrolytic cells. This is true. This is by definition, reduction always occurs at the cathode, regardless of the cell. And oxidation always occurs at the end of regardless of the cell statement F If electric current is drawn from a voltaic cell long enough, the cell becomes an electrolytic cell. This is false. For it to be an electrolytic cell, current must naturally flow in the opposite direction. Uh, voltaic cell will draw enough current until current stops. When current stops, it is neither behaving as an electrolytic or a voltaic cell statement. G The cell reaction in an oxidation reduction reaction. Sorry. Let me state that again. The cell reaction is an oxidation reduction reaction. This is true. This is the only way we can provide electrons to flow

Okay, So in this one, we are given statements. And if we have to see if with statements is true and which is false? Okay, so we'll do one by one. Through its statement. Let's start with the first one. Um, so it says that Corporal metal can be oxidized by a slew of what I am. Okay, so let's see. So the reaction for silver iron would be like this. Right on. He not is equal to 0.8 worlds. Okay, now for copper metal, Toby oxidized, there are two possibilities. One is that corporal forming Corporal positive. And the other one is Saudi. Your oxidizing copper is supposed to be oxidized, right? So this perform, corporal on this value of 0.52 walls, everything is given in the table on. This is also Cooper being oxidized. And this is lower because this isn't to oxidation state. So you know that e s l is equal to he get hood minus. Ian would right on. We know that this is always going to be the cathode because this is the highest one out of all the three so get hold is always the highest. Only then you will get SL as positive, which is a spontaneous reaction probability. So whatever you take, you would get a positive number. So this is always get hold. So this means so, Eiji positive. If you write the overall reaction, it will be too edgy. Positive plus Cooper forming corporate positive close to a ge metal. So it's true. Okay, um, moving onto the next one, which is in a galvanic cell oxidizing agent is in the cell. Reaction is present at and would oxidizing agent is present at and old. So this is actually falls. Why the oxidizing agent is the one that carry forwards reduction. Right? Reduction is done by oxidizing agent Which hawkers? Aunt, Get old. Okay, Soup oxidizing agent is not present at an order. It is present at get rolled. This is easy as compared to the previous one. See, bod is they have given you to say half cell reactions. The first one is a G was only aluminum gaining electrons. This has in odd off minus 1.66 Fools on you have magnesium forming M G minus 2.37 balls. So the question is aluminum is an or or get old. Similarly, you know, listen is equal toe ignored, get told, minus the not my lord so And this is always What was it, Dave? Right. So if a medium is a node, let's see, the cell would be equal to so magnesium would be get old minus 1.66 wars. On this when you will be negative, which cannot happen, Right? So in the media, miss, actually, that gets old. Hence, this is also forms. Uh huh. Moving on to the deep part, so it stays in a concentration sell electron always flow from compartment with lower and concentration to compartment with high Ryan electron always flowed from Lord, I am concentration to higher. This is true for most metal electrodes. Okay, but this is not always correct. For example, you have a A G and A B C. L um, cell. The electron flow is actually the opposite. So you cannot say this every time that the electron will flow from lower. I am higher. Fine concentration. It depends on the case. Okay, Now coming to the last part. It says in galvanic cells the negative iron in this sort of bridge. No is the same as the flu off electrons. This is falls. We all know the flew off negative irons is actually the opposite. Mhm. Okay, the flow off electrons. So this is

The first question is copper metal can be oxidized by silver to determine cynical reaction that describes this process and then calculating cell potential. After leaving the cell potential, we see that it is positive. So this statement is true. The next one in the galvanic cell, the oxidizing agent in the cell reaction is Preston Deanna. What the an ode. We have oxidation occurring, but that is because you have a reduction. A reducing agent for this is false for C in a cell, using these 2/2 reactions for magnesium and aluminum aluminum functions is the an ode. But we need to write a chemical reaction that is spontaneous, and the spontaneous chemical reaction will result in a positive he self, which is this chemical reaction shown here were living going from three plus two aluminum solid. So aluminum is being reduced. Production occurs at the cathode, not the animals. So this is faults for D. In a concentration cell, electrons always flow from the compartment with the lower I and concentration to the compartment with a higher cut ion concentration. This'd true because the higher I in concentration compartment accept electrons so that the cat ions can be reduced to the metal, thus reducing their concentration and making it more equal to the concentration in the other compartment. For Ian Galvanic cell, the negative I owns in the salt bridge flow in the same direction. Electrons. This is false because the electrons always flow from the an ode to the cathode, and the and ions always flow towards the an ode. So they flow from the Catholic to the Anote instead of the an ode to the Catholic. So this statement is false.

But with the war money, Uh, in the form of a question we have from a to f statement and we want to know which one is true and which one is false and correct is a fault. So for answering this question, we look at the 1st 2 on a which it seems that the Arnold has a negative. Ah, and negative charge. Yes, involved. Ickes said Yes, The 1st 1 is true. The 2nd 1 oxidation is a Karen Nano. Understand? In Baltic or electrolytic, it's also true numbers see electoral through toe castle number see also is true. Why number the involved excel surrounded do work on system nor number of the east false and the true off a that system do war on oh surrounding Norie. It's true because the metal is former. That castle number f is false because electrolyte solution is continuing movable on no mobile electrons. Thank you


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