5

3x + 33 = 3(1 + 6x)...

Question

3x + 33 = 3(1 + 6x)

3x + 33 = 3(1 + 6x)



Answers

Solve the equation.
$$|7 x+3|+2=33$$

Explicitly or explicitly should equal one because any number say, five divided by five or native one divided on anyone. Any number divided by itself is gonna equal one. Thanks for watching.

So to solve this equation when clear the denominator, your first by most playing everything by acts. So the reason we do that is because the access will cancel out there. Just leave us with six. We have X Times three, which is the reacts an X Times the 11 which is 11 x couple steps to solve it. Now just subtract the re X from both sides. We have six equals eight X and then we'll divide both sides by 8 6/8 is like three force, yeah.

So for this question we're asked to solve the equation and pretty much what we want to do is find what X. Is. So if we want to isolate X, that means we have to get rid of this 33. So if I go ahead and subtract 33 from this side, the 33s were cancelled out. So I just get an X. But whatever I do to one side of the equation, I have to do that same thing to the other side of the equation based on the addition and subtraction properties of equality. Just because we want to make sure that the equation is still true, that it's still balanced and it still holds. So in this case, if I subtract three from the left hand side, I also have to subtract it from the right hand side. So sorry, that's 33. So then we get that X. is equal to eight. Yeah.

Given three X plus six equals zero. We're gonna graph this line and determine the domain and range. So I'm gonna start by solving for X. Subtract six from each side. We get three X equals negative six, Divide both sides by three. And we get x equals -2. So X equals negative two. And X equals line is a vertical line. Because if I draw this as a vertical line, we can see That my ex valley was always at -2. My domain. My ex values. I'm going to write this in. Set notation is always negative too. And my range. Well my range can be anything. It goes up and down in both directions forever. So my range is negative infinity to infinity.


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