5

Sample of helium is initially at 645 torr in volume of 2.85At24.7 "Cyou found Ihe density of He to be 0.139 g/L and the densily of Ar to be 1.39 g/L even thoug...

Question

Sample of helium is initially at 645 torr in volume of 2.85At24.7 "Cyou found Ihe density of He to be 0.139 g/L and the densily of Ar to be 1.39 g/L even though both samples had the same number of moles, Which one of the following best explains why the densities are different?Argon is heavier atom than helium; sO has more mass in the same volume occupied by (he gasB) Argon is Iarger alom than helium so occupies more volumeC) An argon atom is more dense Ihan helium atom:D) The densities are

sample of helium is initially at 645 torr in volume of 2.85 At24.7 "Cyou found Ihe density of He to be 0.139 g/L and the densily of Ar to be 1.39 g/L even though both samples had the same number of moles, Which one of the following best explains why the densities are different? Argon is heavier atom than helium; sO has more mass in the same volume occupied by (he gas B) Argon is Iarger alom than helium so occupies more volume C) An argon atom is more dense Ihan helium atom: D) The densities are different only because rounding



Answers

Suppose you have 22.4 $\mathrm{L}$ of the following gases at STP: neon, Ne, argon, Ar, and
xenon, Xe.
a. How many atoms are there in each gas sample?
b. What is the number density of atoms, $n / V,$ for each sample?
c. Which sample has the largest mass? Explain your reasoning.
d. Which sample has the largest mass density, $m / V ?$

So we're going to end up calculating the density of a few gases in this problem. Okay, So, if we manipulate the ideal gas law a little bit, we know that density is the molar mass times the pressure over our and T. So for the air, we're gonna go ahead and use the molar mass of air, which is given as 29 g per mole. Mhm. The pressure was given a 7 70 of Mercury. So, I'm going to divide that by 760 so that we can get into ATM. All right. And then we'll go ahead and divide by 8-1. That's our our And our temperature, which is 2 98 Kelvin. Okay, Remember we need to be in kelvin there. So, we get that air has a density of 1.2 g/l. So, what we want to do now is compare that, uh, to heal him. Okay, so similar idea the density of helium, It's just gonna be its molar mass, which is four. Okay. We're at the same pressure. So 7 70 over 760. What would be your ATM? Mhm. We'll go ahead and divide by .08-1 And again we're still at 2 98 Kelvin. So the density or helium This .166 g/l. Okay because our density of our air is bigger than the density of helium. That's why a helium balloon would float in air. So now we're gonna go ahead and compare what would a balloon filled with co to do? So we'll go ahead and find its density. Okay so the molar masses 44 1 Again we've got our 770 over 760. All right. So we're in atmospheres there R. R. is .08-1 And to 98 Kelvin. So we're going to get 1.82 grams per liter. Okay. All right. Since the density of my co two is greater than the density of my air, The Co two balloon will not rise

So in this question we have given the molar mass of the helium capital and it is equal to four point double zero g per mole. And for the part we have to calculate the volume of one mole that is N equals to one of helium at STP that his temperature is 2 73 Calvin and pressure it is equal to 1 80 M. So from the ideal situation, volume V, it is equal to N. RT the airway pressure P. So and is one. Our is a country even four temperature is 2 73 Calvin pressure is 1 80 M. That is one more player by 10 to the power five paschal's. So from here volume V comes out to be 22.7 more player by 10 to the power minus three m cube. Or it can be taken as 22.7 liter. So this become the answer for this problem. Okay, part eight. Now, solving for the part B in which we have to calculate the density of the helium at STP so density, it is equal to Master River by Monica must never be volume. So mass it is equal to a mass. It is equal to four point double zero g. Okay, because a number of moses equals to one. So um it is equal to actually and molecular by capital. And Okay, so they were by volume which is equal to 22.7 molecular by 10 to the power minus three m cube. So density from here after solving 0.176 program per meter cube. So this become the answer for the part B of the problem. Okay, now, solving for the party in which we have to determine the density of the oxygen gas had the same conditions, so the volume will remain same. So density of the oxygen. This will be equal to mass of the oxygen by volume. So mass of dark season will be 32 g. That is 32 molecular weight. Into the power minus three. So here this is a massive big program. So we will use here 10 to the power minus three because it is in the ground. Okay, divided by volume, which is 22.7 molecular weight, and to the power minus three. Okay, so from here, density of Galaxies and gas comes out to be 1.41 program per meter cubed. So this becomes the answer for the party of the problem. Okay, thank you.

For this question, we have one leader of helium gas and one leader of argon gas. They are both at room temperature and atmospheric pressure Are gone. Has a molar mass. 10 times that of helium party wants to know if the atoms of helium have the same average kinetic energy as the are gone Adams and the answer is yes. The average kinetic energy equation is independent of Mueller mass. It's only a function of temperature. So if they're at the same temperature they will have the same average kinetic energy. Part B asks do the atoms of the helium have the same average velocity as the atoms of argon? The answer to this question is no. The helium atoms will have a greater velocity than those of argon because they have a smaller molar mass, the smaller the molar mass, the greater the velocity part C asks, do the argon atoms because they are more massive, exert greater pressure on the walls of the container. Well, the answer to this question is I hope an obvious no. Because the question began with the them telling us that they both have the same pressure. They're both at atmospheric pressure. So if they're both at the same pressure than one cannot be exerted a greater pressure than the other. Another explanation is the pressure is equal to the force per unit area and the force is going to be the same. This is because the slower, more massive argon atoms are going to exert the same pressure as the faster, less massive or lighter helium atoms and then last of all, which gas sample will refuse the quickest. This will be helium because of the inverse square root relationship. The smaller the molar mass, the greater the rate of effusion.

So in this question, we have a one simple of helium gas in a one leader sample of argon gas. Um, there at the same temperature and same atmospheric pressure on, we're going to answer a few questions about them. So the 1st 1 a is do the atoms in the helium sample have the same average kinetic energy ISS, Adams and Argon sample the answer that is actually yes, on the reason weaken kind of explain. That is because average kinetic energy has nothing to do with the actual identity of the molecules. In fact, we have this equation written down where we have the average kinetic energy just three halves times our teeth, uh, considering are is constant for all gases and t It says that the problem is the same for both these gases. You'd expect both samples of the same kinetic energy average kinetic energy. All right, moving on to part B. Ah, and asks, Do the atoms in the helium sample have the same average velocity? Now, the answer that one is going to be no on the reason for that is we know that kinetic energy ah is equal to 1/2 m b. squared, so we know they have the same average kinetic energy. But we also know that organ is a lot heavier. Eso therefore, helium has a have a higher velocity in order to account for that fact for C um, it asks. Since the organ atoms are bigger, do they exert more pressure on the walls of the container? The answer this one again is no on. We can explain this using the ideal gas law, right? So I can say that PV physical to end our teeth, right, if I want to. Aiken kind of rearrange this a little bit ready as p equals and times are t over v all right. So, as we can tell, P and N are directly proportional. So as an increases, so will Pete and as and decreases so peak. Therefore, we can kind of partially that the pressure is not a result of the size of the particles per se, but more over the number of particles that are present and, uh, moving on. Lastly to d, it asks which gas has the faster rate of infusion eso as a general rule. The smaller the molecule it is, the faster it moves So in this case, the answer is going to be helium on. If we need a more mathematical explanation, we go to Graham's law, which is that the rate of effusion is proportional to one over the square of the molar mass, which means that as Mullah Mass increases, the rate of infusion will decrease.


Similar Solved Questions

5 answers
8 points each) Determine the following: (a) 6z? cos(r? )dx
8 points each) Determine the following: (a) 6z? cos(r? )dx...
5 answers
Ee & FHHHUH 8 1 Hl 6 ? Z [ 1 #+ 3 8 28 { JE [ | Xp 0 [ H 8 V # 1 ll L 1 [ { 7 1 [ F W U 1 # 1 2 IV 0 HL L Atf
Ee & FHHHUH 8 1 Hl 6 ? Z [ 1 #+ 3 8 28 { JE [ | Xp 0 [ H 8 V # 1 ll L 1 [ { 7 1 [ F W U 1 # 1 2 IV 0 HL L Atf...
5 answers
Question on bottom pleaseTheorem 3 1.10 M f u ekekdelia = € = & Ea i feaica FFu)e tafnei @ LPIcNE OacGk;fu)AtDtkScreen Shot 2018-05-06 at 12.16.29 PMThcorem 3141 6 f #int- LatntueEfua #altaiAid an Fun Iederfue E F (Ie)i Jh Wrtar [niteo DaF(a) tal Kf wo F2() = f()Screen Shot 2018-05 06 at 12.18.26 PMGue fudt .
Question on bottom please Theorem 3 1.10 M f u ekekdelia = € = & Ea i feaica F Fu)e tafnei @ LPIcNE OacGk; fu)At Dtk Screen Shot 2018-05-06 at 12.16.29 PM Thcorem 3141 6 f #int- LatntueEfua #altaiAid an Fun Iederfue E F (Ie)i Jh Wrtar [niteo DaF(a) tal Kf wo F2() = f() Screen Shot 2018-05 ...
5 answers
Fuanla ^Suru 3nin B With 120 rolls of die,the result is as follows. It is tested whether the die is balanced or not at the 5% and significance levels, respectively: Which of the following interpretation of the test results correct? GelenGelme Savisi45Unbalarie 4:Unbnlarce)35 Baleicdi Tra uriueleniceo745 Ralar Ta bAlanted35 Uobelanceu Bele"Ce
Fuanla ^ Suru 3nin B With 120 rolls of die,the result is as follows. It is tested whether the die is balanced or not at the 5% and significance levels, respectively: Which of the following interpretation of the test results correct? Gelen Gelme Savisi 45Unbalarie 4:Unbnlarce) 35 Baleicdi Tra uriue...
5 answers
14. Five equally-spaced holes are placed on the circunference of circle whose radius 1s 35.4 cm Find the center-to-center dis- cance W between two successive holes _ Round to tenths .
14. Five equally-spaced holes are placed on the circunference of circle whose radius 1s 35.4 cm Find the center-to-center dis- cance W between two successive holes _ Round to tenths ....
5 answers
21. Let C be a circle and 2 any complex number. Prove that the point 2* symmetric to z with respect to C is unique:
21. Let C be a circle and 2 any complex number. Prove that the point 2* symmetric to z with respect to C is unique:...
5 answers
Go to fileffurps 1Op2 *57 Filter Spain France Italy Greece Swordfish 204 183 60 141 Grouper 159 96 24 66 Sole 21 36 12 39 Bronzino 18 12 21 21 Tuna 87 36 123 Salmon 123 72 12 54Showing 1 t0 6 0f 6 entriesConsoleTerminal
Go to fileffur ps 1Op2 * 57 Filter Spain France Italy Greece Swordfish 204 183 60 141 Grouper 159 96 24 66 Sole 21 36 12 39 Bronzino 18 12 21 21 Tuna 87 36 123 Salmon 123 72 12 54 Showing 1 t0 6 0f 6 entries Console Terminal...
5 answers
OncdeHteeFNLTAM MleteuerIhr Wca {o I= Yut =
Oncde Htee FNLTAM Mleteuer Ihr Wca {o I= Yut =...
5 answers
-2<t<0 is 0<t<2The Fourier series for the function flt)=-flt) = _ T,u sin(t#_ flt) = _ 2u 7 cos(o#) odd flt) = _ 2 Ksir(y odd f(t) = 27 sir(otc) odd
-2<t<0 is 0<t<2 The Fourier series for the function flt)=- flt) = _ T,u sin(t#_ flt) = _ 2u 7 cos(o#) odd flt) = _ 2 Ksir(y odd f(t) = 27 sir(otc) odd...
1 answers
Draw and label each ray. $$\overrightarrow{Y X}$$
Draw and label each ray. $$\overrightarrow{Y X}$$...
5 answers
Find the zeros of the function and state the multiplicities_p12x 27x +15x
Find the zeros of the function and state the multiplicities_ p 12x 27x +15x...
5 answers
Without doing calculetions; malch the following thcmodynamic propertics with thcir appropriate numericel sign for the following endothermle TenctonNxle) + 20,() 2NO-(@)Clear =4Han4G_nQo T,<0 high T~0low T > 0 Eigh T(Prux ous6)Sit ETE
Without doing calculetions; malch the following thcmodynamic propertics with thcir appropriate numericel sign for the following endothermle Tencton Nxle) + 20,() 2NO-(@) Clear = 4Han 4G_n Qo T,<0 high T ~0low T > 0 Eigh T (Prux ous 6) Sit ETE...
5 answers
(Begin by finding the mean number of rocks per slab.) The numberof rocks in a slab has a Poisson distribution. If I cut off1/3 from the concrete block and realized that there will be nostones in it with probability of 1/7. What is the probability thatthere are at least 10 rocks in a whole slab?
(Begin by finding the mean number of rocks per slab.) The number of rocks in a slab has a Poisson distribution. If I cut off 1/3 from the concrete block and realized that there will be no stones in it with probability of 1/7. What is the probability that there are at least 10 rocks in a whole slab?...
5 answers
Question 112 p11. Water is a reactant in which of the following reactions?synthesis of monomers into polymersformation of peptide bondsformation of ester linkageformation of phosphodiester linkagebreakdown of polymers tO monomers
Question 11 2 p 11. Water is a reactant in which of the following reactions? synthesis of monomers into polymers formation of peptide bonds formation of ester linkage formation of phosphodiester linkage breakdown of polymers tO monomers...
5 answers
4 (12 points) Consider the vector functions r(t) and w(t) with the following information_r(t) (2.4.-3) (1.-2.3) 75,8.2) (3, ~2,0)2 (t) w(t) w' (t) 74,1.0) 71,8,2) 73.1.-1) 5.41) 75.0.4 2.6.3) ~1.3.-6) (8.1.-37 (3.0,31 72,3.51 77,6,1) 4.0_If €(t) = 2r(t) _ 3w(t), then calculate f' (2) . (b) If g(t) = r(t) w(t), then calculate 9 (3)
4 (12 points) Consider the vector functions r(t) and w(t) with the following information_ r(t) (2.4.-3) (1.-2.3) 75,8.2) (3, ~2,0) 2 (t) w(t) w' (t) 74,1.0) 71,8,2) 73.1.-1) 5.41) 75.0.4 2.6.3) ~1.3.-6) (8.1.-37 (3.0,31 72,3.51 77,6,1) 4.0_ If €(t) = 2r(t) _ 3w(t), then calculate f' ...
4 answers
(10 points) The graph of a function f(2) is given below: Sketch the graph of the derivative f' (2) on the interval 0. 0)
(10 points) The graph of a function f(2) is given below: Sketch the graph of the derivative f' (2) on the interval 0. 0)...
5 answers
C,H;O, salicylic acidCzH_Oz acetic acidCgH;O_ aspirinHzO
C,H;O, salicylic acid CzH_Oz acetic acid CgH;O_ aspirin HzO...
5 answers
An object of mass 27.0 kg has three forces acting on it in the x-Y plane_ One force has a magnitude of 100 N and acts at a angle of 135"9_ The second force has a magnitude of 150 N and acts at an angle of 2539_ The third force has magnitude 75 N and acts at 1809. Find the acceleration & of the object, ignoring friction.
An object of mass 27.0 kg has three forces acting on it in the x-Y plane_ One force has a magnitude of 100 N and acts at a angle of 135"9_ The second force has a magnitude of 150 N and acts at an angle of 2539_ The third force has magnitude 75 N and acts at 1809. Find the acceleration & of ...

-- 0.024311--