So we're interested in finding about a massive spring a little bit different from before, right? And we're told that it has a sort of infinite Tess Imo Mass that's given by here but that each part of it moves sort of in phase right with whatever the total v of the masses. Right? And so if I'm interested in finding the kinetic energy of something, we typically have just 1/2 MV squared. But the EMS and the V's are veering and depend on different things. And we have the EMS here, so I'm gonna actually do an integral here. And I want to integrate each individual infinite testable mass get into individual kinetic energy and that and them all up. But we actually just get to plug this in, right? So this is actually really not that bad. So we get em over l times DX. So that's the d M part. Let me have X V over l squared. And now we're integrating over DX. Someone integrate along with length of the spring. So I'm gonna pull out the appropriate Constance here. What? You're gonna see you get a 1/2 MV squared and then randomly, maybe not surrounded my l cubed in the bottom. Then we're gonna integrate from zero l. And the thing that's left over is X squared and e X, But this is 1/3 l cubed eso that l cube and that cube cancel into the Connecticut or give just the spring is actually gonna be 1/6 MV squared. And then we do have the mass still oscillating at the end of it. And that's 1/2 and B squared still right. So this is the new term were also asked to identify what happens to the period. I'm gonna kind of cheat here. All right, so here's our to buy em over. Okay, I want you to notice that the spring has a kinetic energy of 16 mv squared, right? It's sort of what if I suggestively wrote it like 1/2 AM over three b squared? It behaves as if it has a mass that's actually like 1/3 of it, right? And that's because parts of it are moving slower in parts of removing faster. But I'm going to use that over here. All right, so we need the total mass. Normally, we would just add them together, right? So I take the block. But I'm just gonna treat the spring as if it only had 1/3 of its mass, because that's what it looks like over here with the kinetic energy. When you actually do it, this actually ends up being the right answer.