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Problem 6 (12 Pts): Answer the following questions regarding IUPAC naming_ (Q22-023) Provide appropriate IUPAC names for the two structures shown below: (024) Draw ...

Question

Problem 6 (12 Pts): Answer the following questions regarding IUPAC naming_ (Q22-023) Provide appropriate IUPAC names for the two structures shown below: (024) Draw the structure of 5-(1-bromoethyl)9-chloro 4.Z-dimethyldodecane using bond-Ilng tormatQ23022

Problem 6 (12 Pts): Answer the following questions regarding IUPAC naming_ (Q22-023) Provide appropriate IUPAC names for the two structures shown below: (024) Draw the structure of 5-(1-bromoethyl)9-chloro 4.Z-dimethyldodecane using bond-Ilng tormat Q23 022



Answers

Use the IUPAC rules to name the following structures.

This question is asking us to structures. So let's see this one. This It has a ring, and this ring has one colors 12345 apartments in it. So because it's a ring, it's going to be sly chlo hunting. And we've got this month now we could just call it metal cycles contain. And you actually don't need a number out front because there's only one of them and it's a circle. So actually, underwear you start. So this is actually just metals second structure. We're gonna do this thing it 123456 carbons Loaned Ridge. So this is Psychlo, Texas, and let's figure our groups. So this is Apple. This isn't true. And this is going to be metal. And now, Now, uh, we want to count so that these are the smallest number possible until the smallest possible that the count is a point end up being one Here, here, three. Now we go alphabetically. So, Ethel, you point n and the and so that has to go in front of this. And so this entire complex is going to be too asshole. One four Tri metal. Yeah. Wrote cycle axe. So it's to Ethel one for help. Leslie. Same thing has a rate. That's the most important part. So we're gonna figure out 1234 minutes. Four carbons in the green. That makes it Psychlo. You did. And it's got one to Ethel groups. And it was kind of hoping number. These kind of being one. Sorry. 123 So, over all this conflict is going to be one me die at all this one week.

All right, So for this question, were asked to name the following structures. That's a party we have. It's only option. So it would count the number of carbons in the longest change who have 12345 Listen, we have five. We know that this is a, um plantain Poets write that up and we always have a pension because, um, it's just ah, single bond and yeah, it's a single bone between every carbon and hydrogen and etc. We know that the ch three, this is metal, and it's in position to. So what we have to do is write to metal and then the pension. That's the name of our for structure. Now for a 2nd 1 For Part B, we have the fallen Chuckie. Let's count our number off longest chain carbons. That's 123 So since we have three longest chain carbons, that is probing and they're all Cinnabon, and then if you know, there are two, um, situational groups attached to that But there are two of them. We put a die in front, and then so it's too. Hi, Ms. Okay. Actually, we need to do to save her presentable. for them, all right, and left the airport seat, which is, As you can see, this is a ring structure. So we know that we're gonna have to add Psychlo before the name of the longest languages, every structure. So it's count the number of, ah, carbon. But 123456 That means we have vexing. And we add a cycle in front of that since there is a construction and okay, so it's identify what are situational groups are. So we have a street, the three of them, and it's called metal and then we have to the extreme and this is cod. If you refer to your table, this is I don't well, we know eagles before m so we need to order it so that kids to see its three districts. So we'll start with one. We could go either clockwise counter called quite Oh, actually does matter, because if we do that one and then we go this way, we have you here. But if we're called the other way would get to here, which would create a a smaller amount of numbers. But that's what we want. So let's go out So we have 2345 and six. So we know that those first because it's, uh we're ordering it alphabetically. So we have one apple, and then we have 245 try missile, and then we combine that with Michael. Heck sing.

So in this podcast, we're looking to name some AIPAC structures. And so by using this universal system, we can quickly draw out what molecules someone might be intending us to understand inthe e standardized naming system. So in the first example, what we have is two missile plantain on DSO. What we know is that it's a five carbon chain with pent. Ain't means that we just have single bonds. Missile means that we have a ch three substitue in on the second carbon. So the next example we have is to die missile propane. So from this name, we know that we have a three carbon chain pro. Ah, we have single bonds again. We have died, so we have to substitution off. R C H threes aren't thesis unde carbon Now. Next we have one e style three for six try missile cyclo hexane. So that is quite a long name. So that is one e Thile 346 Try me style site low. Heck saying so we'll just unwrap this name now. So the first thing we have is a cyclo. So we know that this is a cyclical molecule and instead of any sort of linear chain that we do have a cyclical structure present. So this is what we expect. Heck, sane means we have six carbons in that chain. All of them are single bonds because we have a Nathi end And now to look at our substitue INTs. So, on the first carbon, we haven't s I'll chain just ch three ch two on the first carbon and then on the third, fourth and six carbon. We have a missile group, which is ch three. It's try Mithal because we have three of those, man.

This is the answer to Chapter 20. Problem number two from the McMurray Organic chemistry textbook. This problem is sort of the opposite of problem number one. So in this problem were given six AIPAC names and asked to draw corresponding structures. Um, okay. And so for a ah, the AIPAC name that we're given is to three dimethyl Hexen OIC acid. Okay. And so we should start with the base chain here, So Hexen OIC acid. Um, so it's gonna be a derivative of heck sane. So 1234 56 So six carbons are carb oxalic acid here. Um and so, of course, that's going to be carbon number one, the carbon with carbon oxalic acid. Ah. And so now we need to put metal groups at carbons two and three. So if the carb oxalic acid carbon is carbon number one, Uh, the very next carbon would be carbon number two. Um, and then the carbon after that would be carpet number three. Okay. And so there's are are you pack structure. Our There's our structure for the AIPAC name to three dimethyl hacks. Noah Gasol. Okay. Uh, and so, um, the rest of the problem is going to follow the same pattern. So for part B, we have four methyl Penton OIC acid eso Penton OIC acid. So this is gonna be a derivative of plantain. So 12345 I will put our car box silly gas it here on. So this would now be carbon number one the carb. Oxalic acid. Ah. And so we need to put a metal group at carbon number four. So 123 four. This would be carbon four. There's our method group. I'm so there is form Ethel Penton OIC acid. Okay, Um, for part C, we're given Trans 12 cyclo butane die carb oxalic acid. Okay. Eso from that we should get that The base structure here is gonna be a cycle of butane. So let's start by drawing our cycle of you teen. Uh, then we're told Trans one to die car box that like acid. Okay, so there are two carb oxalic acids and their stereo chemistries are opposite one another. So let's put one here on the wedge, and then we should put the other here because it's one to die. Carb, oxalic acid. So what about the other one here on the dash. Okay. S Oh, there we go. Trans One to cyclo butane die Carb oxalic acid. Okay. Eso for part D Um, we have orth Oh, hydroxy benzo Weak acid. Okay, so this is Ah, Ben's OIC acid derivative. So the first thing that we should draw should be the benzene ring. Let's draw that, um and then it's a benzo a gas of derivative. So let's put Arbenz OIC acid here, okay? And so then the rest of the name is Ortho hydroxy. So we need a hydroxy group or throw to the carb oxalic acid. So let's put that in. And there we go. Or the hydroxy Ben's OIC acid. All right, so that's part D for part E. We have Oh, boy. Nine z 12 z 9 12 Oct A decade. Diane OIC acid. Okay. Um, so 12345678 number. Okay. Yes. So this is an 18 carbon chain. Okay, so let's start with our carb oxalic acid. So that's gonna be carbon one. Um, we need an 18 carbon chain with unsaturated ins at carbons nine and 12. Okay. So, one, 2345 6789 chi. And then here we have our first double bond. Um, let's draw that. And they were told that both of our double bonds here are, uh, in the Z confirmation. So carbon nine, carbon 10 carbon 11. Then here is carbon 12. So our next double bond carbons 12 to 13 again with disease stereo chemistry. 13 14 15 16 17 18. All right. Um not so bad of a structure. Kind of Ah, scary name. Eso That's 90 12 z 9 12 Oct A decade Dienno gases. All right, um and then lastly for F for part F Here we have ah, to Penn Teen night trial. Okay, so Pentti night trial. So this is gonna be a five carbon chain, um, with an AL Keen at carbon to So let's start, uh, by drawing the nitro. So there's are no trial and carpet one, So here would be carbon too. Um, so we're gonna have a double bond there. So carbon 12345 Okay, so there we go. Um, that would be to Penn Teen night trial. Alright. Ah, and so that is the answer to Chapter 20. Problem number two


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