5

For each of the FILL IN ANY (shape} c) all _ follomng = BLANKS IN bond give Lelecuonc TABLE L give anglos (when' gcometry BElOw prediclion), distoned one pairs...

Question

For each of the FILL IN ANY (shape} c) all _ follomng = BLANKS IN bond give Lelecuonc TABLE L give anglos (when' gcometry BElOw prediclion), distoned one pairs of about centale electrons Oraw the best tnree - angla grcater alom, outer dimensional Imohaar atoms dnuctute ? less tan " VSepR geonetyy includo (onireonance Pieaeon tonula geometoy tnem On the Cental atomi stcturtes electroni e) tend Hso molccular polar tetrahedral distortion Vulone auucture (cleztrons polaan Iona pa bonaing8/

For each of the FILL IN ANY (shape} c) all _ follomng = BLANKS IN bond give Lelecuonc TABLE L give anglos (when' gcometry BElOw prediclion), distoned one pairs of about centale electrons Oraw the best tnree - angla grcater alom, outer dimensional Imohaar atoms dnuctute ? less tan " VSepR geonetyy includo (onireonance Pieaeon tonula geometoy tnem On the Cental atomi stcturtes electroni e) tend Hso molccular polar tetrahedral distortion Vulone auucture (cleztrons polaan Iona pa bonaing 8/2 = 4palrs KrF 3812 pairs square planar Wedged > ond cnea 0n8761 square pyramidal dashed* _ Embenupete 4212 pairs tngonal 2212 = 11 bipyramidal pairs trigonal planar 18/2 = pairs SCh 34/2 pairs ne pair- Cl-S_Cl CIF} 28/2 pairs shaped



Answers

List the correct electron and molecular geometries that correspond to
each set of electron groups around the central atom of a molecule.
\begin{equation}\begin{array}{l}{\text { a. four electron groups overall; three bonding groups and one lone pair }} \\ {\text { b. four electron groups overall; two bonding groups and two lone pair }} \\ {\text { c. five electron groups overall; four bonding groups and one lone pair }} \\ {\text { d. five electron groups overall; three bonding groups and two lone pairs }}\end{array}\end{equation}\begin{equation}\begin{array}{l}{\text { e. five electron groups overall; two bonding groups and three lone pairs }} \\ {\text { f. sixe electron groups overall; five bonding groups and one lone pair }} \\ {\text { g. six electron groups overall; four bonding groups and two lone pairs }}\end{array}\end{equation}

So now we'll work on problem five Problem 19 from Chapter five and this problem were given several different conditions. Several different number of electron groups, Bonnie groups and lone pairs and were asked to give the Elektronik and molecular geometries so we can draw a table for each of these, uh, situations. So we have overall electron groups. First, we have bonding groups, we have lone pairs and then we're asked about the Elektronik geometry and B molecular geometry. So we have seven arrest about seven conditions here so we can start with part, eh? We were given the conditions that were given his four electron groups, three of which are bonding, and one is a lone pair. So since we have four electron groups, the Elektronik gentry would be Tetra hydro. But since we only have says one of them is alone, pair the Malek molecular geometry would be tribunal pure Amital with these three bonded Adams, four mean a triangular pyramid for Part B were given for electron groups again this time two bonding groups and two lone pairs. So our electronic gentry will be tetra. He'd roll again because we have for electronic groups. But this time, these two bonding groups will form a bent molecular geometry. In Part C were asked about five electron groups for bonding one lone pair and for five electrons groups. The electron in geometry is tribunal bye pyramidal and remove one of these Adams, one of these binding groups from Triggered by Perimeter. We get a seesaw molecular geometry in our D were asked about five Elektronik groups again. This time we have three bonding to loan hairs so we could have electron geometry again of tribunal by primitive. But this time we remove one more of these bonding groups and we have instead of a seesaw, we have t shaped for our molecular geometry in party were given Father, five Elektronik groups. This time two are bonding and we have three lone pairs. Our electron geometry is the same because we haven't changed a number of electrons route. This time, though, we only have two bonding groups. So we have a linear molecular geometry. In part F were given six electrons groups, five of which are bonding. One is a lone payer through our electron geometry for six groups is octa He'd roll and then when we remove one of those atoms, We get a square pyramid, so we have square, uh, perimeter. And then in part G, we have six electrons groups again. Four bonding to lone pairs. And we have our cathedral again. And then when we removed, too from up the hero, we have a square plainer geometry.

All right, So in this question is asking us to give the correct electron and molecular geometries that correspond to each side of electron groups around the central atom of a molecule. It lists frustrate each of these letters the correct electron groups over all the correct bonding groups and the number of lone pairs. We can then use the chart on page 4 36 table 10.1 electron in molecular geometries to help us to answer each of these questions. So for letter A, we are told that we have four electron groups on this abbreviate that we have four electron groups, three bonding groups and one lone pair. So from that we can take a peek at our chart, and we know that that is going to be past three Tetra. He'd roll for its electron geometry because that's a given. So it's tricking drone, and then four are We have three bonding groups and one lone pair. That means it's gonna be tried Bonal hye rim. It'll for the molecular geometry. Try Gunnel Tyra Middle. Yeah, let me see if I can make this text fit on the screen a little bit better, so that's gonna be for the first lady for letter A because of what they tell us there. So let's take a peek at the next one. The next statement says that we have four are left from groups again. So again, we automatically know that that means it's gonna be a tetra. He'd roll electron structure and it says we have to bonding groups and too long pears. So what does that mean for us? So we take a peek at our chart. We know that we have a tetra he dro electron geometry. And because of what we know about our chart saying that we have two bonding groups and therefore to lone pairs, we know that this has to be bent. Let me move this over so I can finish typing that. That's a bent molecular Jeon trains somehow that got upset again. There we go. There we go. Okay, so and again, this one up here was the molecular geometry. Okay. Our next one tells us again I'm gonna make this tiny so that I can see it, that we are going to have five electron groups, so we know that that's gonna be different. We have four bonding groups would mean that we have one loan pack. So again, looking at our chart, what does that tell us? Since we have five, that means that we are going to for sure be try. Go Mull Pirate Middle for our electron geometry. That's for our electron geometry. But because of our bonding groups and our lone pairs, we know that we have a seesaw molecular. So get him a spell. That right? OK, so that's our next one. Okay, let's take a look at what we have again. So for this one, we have five electron groups again. Means we're gonna be tried Bonal by perimeter, all for our electron geometry. And then this time we have three bonding, and that would mean we have to lone pairs. So what does that mean? That means that again we're gonna be tried going all five high rooms, pirate middle for our electron geometry. And since we have three and then two, that means there's going to be t shaped molecular geometry. So again, all of this is found in that chart in your book. So let's see for the next one. This one says we have five with two and three. So we have five electron groups to bonding groups and three loam pears. So what does that mean again? Take a peek at the chart, and we know that we need to have a tribunal. Planer are, but I'm sorry. Tribunal by perimeter. All because we have five electron groups are my text isn't typing over here for now, So try going on. Bye bye. Rim, it'll electron. Yeah, on the truth. And then, based on what we know about the molecular geometry, we would know that we have a linear structure. Okay, let's see here. That was a B, C, D and E. We just have f n g left. This time we have six electron groups. So this time we have six electron groups and we have five bonding groups in one long pair. Five bonding groups. One loan pair. What's that going to give us taking a look at our chart. So we know that is gonna be octahedron, because any time we have six electron pairs, it's gonna be Octa. He'd roll, and that's for the electron geometry. And then our molecular structure is going to be s square. Hiram, It'll which means the bottoms and looks like a square. And then the top is a pyramid. So that would be square Hye rim. Oh, and that would be the molecular geometry. So make that visible for you. Okay? And then we will lastly have one more. Which says six with four and two. So one more time. Put some text on the screen. Okay, here we go. We have six electron groups with four bonding groups and to lone pairs. So what does that mean for us? Let's see. We take a peek at our chart and we see that that means again. It's got to the optic, Pedro. Every time that you have sex, it's going to be Octa. He drove electron geometry and finally, it's gonna be square, plainer square plainer. And that's for the molecular geometry. And again, you can see all of these things by looking in your book at table 10.1, just following along with the number of electrons groups, the number of bonding grips and the number of lone pairs, and you'll be able to see it the appropriate shapes for each

Hi, everybody. So, in this question, yes, that is used the VSC peer model to predict the bonding and geometry about each highlighted later. Remember to take into account the presence of an shirt. Pair of electrons. Now enough. Foster needs ethanol now, you know, bonding around this carbon into carbon. There are four single bonds. These poor single body forms provision of electron density and therefore predicted born angle is 109 degree, five minutes. So 109 degree, five minutes around carbon and therefore geometry expected to be taped ahead. Yeah, Then around oxygen. You know, there are two single bombs and too long payers. Therefore one second, there are four regions of electron density around this option atom and the bonding will predicted to be 109 degree. So 109 degree, five minutes around oxygen. Therefore, one second it is expected to be the federal might actually obtaining. We started a title because of presidents of Poland. Then next one is, you know, predicted bonding around this carbon is 1 20 degree. Since there are three different regions of electron density due to one double one and two single bombs. So 1 20 degrees around carbon, carbon and expected Giamatti's tribunal planer Lana everybody than next one is carbon. The expected born angle is here. You can say, uh, you know, there are two regions of electron density that is to single, born and one triple born. Uh, around this carbon is one single one and one trip and one. And that's why to regions of electron density and therefore expected warning. And it's 1 80 degree, according to BS. If here so relate 1 80 degree around carbon. I am expected. Kilometer is linear. Yeah, thanks a lot.

The first compound is a Salford with two chlorine. Therefore so for will be the central Adam have to. Chlorine is coming off of it and then it will have to compared Alright, trance and just are the rest of my impaired period of electrons. And the geometry of this one will be bent. Since there's on Lee, two things connecting so for the next example we have is P I three. So phosphorus will be the central Adam and then it will have are dying coming off of it in three places and then it will have one set of impaired electrons and the geometry of this one will be tribunal criminal. The reason for that is because it will have three substitue INTs in one, um pair, pair of electrons. The next example we have a seal to with an oxygen so the oxygen will be our central Adam. Since it's like to bonds, both of the CIA will be bonded to it. So just like our first example, it has to substitute wince and then two pairs of, um paired electrons. And so again, this geometry will be that a next example is in H two with a Corinne. So nitrogen will be our central Adam and then to the too hard Children will be connected to it as well. A so chlorine. And then I'll have one set of unparallel our trunks. And so, just like our second example, we have we had, it will be tribunal perimeter all because it had three Substitute Wint's in one hair of electrons that are not paired with anything. Our next example. We have a sigh, which will be arson. True, Adam. And then I'll have three chlorine za round it and then one bro Ming. So since it has four substitute Wint's, the geometry of this compound will be tetra. He'd roll. Then for last example. We have oxygen, nitrogen and chlorine, so nitrogen will be or central compound and they don't have a chlorine connected to it and then will be double bonded to an oxygen. Since an oxygen likes to have two bonds and arches, one likes to have three bonds, so this will give nitrogen one pair of impaired electrons and this compound is also spent. Find that out, get free all


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