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Problem 23CH,H;cNaoch; heatCH,...

Question

Problem 23CH,H;cNaoch; heatCH,

Problem 23 CH, H;c Naoch; heat CH,



Answers

Repeat Problem 10.50 with $(CH_3)_2C = CH_2$ as the starting material.

In this problem that writing the reaction at C triple bone siete in presence of Acadia So four hatch too. And so four, it will give CS three CS 2 and it is in pageants. So see http. MdB uh, as village as to it will change into C h T T h do at see http and it is in pageants cell B B E R T. It will change it into see http. See it be uh, see http. DHT CHBS CS three. So, absolutely. It's correct. So absent thee age, correct answer for this problem.

The question is to solve the given neck, but by love. Last transformation The notebook is the time to watch Henry J. I. This is one lunch If g 0.1 angry i three. I do be me seeing be I won two and he explored. So now they're using the pill chops Current low wayward get I do less i three bulls to Ivan by applying the Kirchoff World Edge Law I one on one less l b. I want Beatty last hell three b i three less. The team will be 40. So from the figure we know that l Barnicle's to 0.1 itch very closely, hoping for which are running for this food who ampere. And he was full of six words on substituting The values may get the equation. So why one less little find toe? I won. Let's go find one. My significant six. My applying the cultures more edge law in the close o d e f g b e f g be l one b. I do. Bt minus are toe. I do. It was 20 from the vigor. We came to the conclusion that Elbow Nichols was 0.1 match. You know, playing one match are the Whipple's toe one. He falls to zero words on a substitute in the value vigor 0.1, I realized minus I do, it falls to zero. The initial conditions are good one. I won zero people stra zero i to add cereal with close to zero. I drink at zero postal zero left. I won. Yes. Was to law applies off high one. Yes. I U s pulse to love blasts off I the one this I three Yes, equals love flies off. All right. Three. Yes. So love lies off. I do less. I three will be put to love dollars off 51 Which will be Porto la Blast off I two plus love plus off request by one That is I do west less I three. Yes, it was So I went Yes. By taking the lap last transform off I one dish we get love blast off. I want dash as it was to s 51 s minus society at zero. So that is s I want this Now buy a England last transform off. I read Ashley yet love lives off. Hi. Three dash. Yes. Equals a s I a three. Yes, Minus high three R zero There is s I three s minus zero. There. There says hi. Hey. Yes, Nobody taking love Last transformer dick Question twice or 51 plus zero point. I won Nash last 0.1 i three dash equals through six the oh, last 0.2 s Hi. Have oneness Last 0.1 I actually as close to six upon as by substituting. I am when this I want and sickles toe I us last I three years and the above equation we get the blessed zero point Who s I? U s less I three s Bless little 0.1. Yes, I it the Yes. Because 26 buyers which will be I who s who place zero point who s less do I three s less little 0.3 That's by Italy and sickles to six way Yes, that is I go. Yes, well, we put six minus toe s I three years minus little 0.3 Yes. This where I three s upon as to bless their appoint us by a single A plus Transform off questions or print one I three Nash minus. I could dispose zero. We got love plus off 0.1 I three dash minus. I could pull stew. Love blastoff zero. Which will be for why West was 0.1 less i three by putting I us equals whom? Six minus two west I three az minus 0.3 years square high. Yes. On as toe plus zero point us and hi us. It was a little point. Oneness. I teddy me, Jack X minus two s high three az minus 0.3. Yes, it's where I three s upon. As who less vilifying us equals to 0.1 s I three. Yes, which will mean 1/4. Why three years equals toe 300 on US 100 plus 25 rest. That's as this where Which will be worth 300 upon this as less Wendy s less fight. So using the partial direction being here 300 equals toe less B c. Is this where plus 25 way less files be less when PC doing driven by un Greg A. By comparing the coefficients on red A Was the 300 a false too three a plus B plus C questions were also fire A plus B plus four equals +20 the is three a plus B policies There also people Aceval because two minus three people minus three minus c by substituting equals 23 and five a plus B plus full Sequels to zero We get be was minus 15 minus four c sold. In this we got staples from minus four big balls to when now, substituting the value I three years will be put three of bonus less one of on s less 20 minus four upon us less if I solar plants and worse off I three s would be I treat the people sto three plus Here's to the but minus 2080 with a minus four years two by minus I he similarly for I do it will be I do s equals 26 miners to s by three s minus 0.3 Yes. This where? By three Yes. Born. Yes. So let's little find us so off the agenda Hunting and dietary like us would be equal to 30 upon s plus 20. Bless I By using the partial fraction, we would get 30 day close to a plus B s plus five way less fun TV. After solving this, we would get I so s equals minus two Were born s Pless doing being plus two upon us, Plus I so I to take it that has left us And worst, it would be minus toe Here it's about minus trying Pretty blessed to rely on minus five days. Now forward, I want I am one d pistol by duty, Less high treaty that will be for two in minus zero for minus 20. Pretty less minus who were ish by minus five D Last three days minus. Here's to the par minus 20. Treating minus four years Bar minus five less three. Thank you.

A person cylinder contains a given mass of water at a given state. The person initially rest on some stops with the top surfers open to the atmosphere with atmospheric pressure. P not. We also know the water pressure required to lift the person, and we wish to calculate the heat transfer in this process. So if we take the control volume as the water, we have a control mass, which from the continuity equation shows that M two is equal to M one, which is simply em to the mass of the water is constant. The energy equation can be written as m into YouTube minus you. One is equal to the he transfer Q plus t work than W. Yeah, so let's write down now information that it stayed at ST one we 20 degrees Celsius. We have that. The specific volume V one is equal to the total volume V over the total mass M. That's 0.1 divided by one, which is 0.1 cubic meters. The K G Equality X is able to 0.1 again from our tables. Find a zero point 001 you know, you know, to divided by 57 0.789 and so we get equality in ST one x one to be zero point 00 17 13 The internal energy of state one is you one and again. Now that we have the quality, we can calculate this to be 83 0.94 plus zero point 00171 three multiplied by 2318 0.98 And so we get the internal energy of state one to be 87 0.92 killer jewels k g. So to find state to we confined first state chicken stayed one a where the pressure is now 400 killer Paschal's on the volume remains constant and 0.1 cubic meters per k g. So since the specific volume is between the fluid and the gaseous volume specific volume, we have say, two is a saturated vapor so and the saturation papers at 400 killer passport So V two is equal to be vapor pressure v. G and thats zero point 46 25 cubic meters k g. The total volume V two is equal to the mass times the specific volume little B two and this is again 0.46 25 cubic meters And the internal energy you two is equal to the vapor internal energy Yugi 2553 0.6 Killer jewels for K G. Now the pressure is constant as the volume increases beyond the initial volume. So we have boundary work being done. New York W from state one to state two is the interval over the two states off PDV, which is the constant pressure P times the change in volume v Tu minus V one. So this is equal to the left pressure to lift the piston. I'm the change in volume V two minus 31 and we can put our values into this to find the work. So this is you live pressure 400 kg Paschal's and the change in volume 0.46 25 minus 0.1. And so we get the work them to be 145 kiddo jewels. Now we can put the work back into the energy equation and rearrange to solve for the heat transfer. The heat transfer Q is equal to him into YouTube minus you. One plus w. This is one into 2553.6, minus 87.92 plus 145 which gives us our final heat transfer for this process off. 2610.7 kilo jewels. Mhm.

Question 55 is a essentially a repeat of Question 54 which I recently just did where we have a tank. We have two gases mixed neon argon, but the given temperature and pressure, which I showed here once they're mixed, unifying two parameters thief, final temperature and the final pressure. So, based on what's given to us, we're also additionally told in this scenario for Question 55 the amount of energy loss from the system, at least for Question 54 was eight killed Jules. But in this question now we had lose eight killer jewels of energy. So we're going through basically reading Question 54 which I will show essentially my solution to question 54 below. But to do that, we're doing it with the different change in energy. So based on our change of energy, I can use the falling relationship where I can relate to my energy, los que out to our expression for mass specifically and change in temperature where if I have it for each gas, so for neon and for our gun, I some these two up to give me my total amount of energy loss and in this line I'm gonna solve for my final temperature. However, in order to that my first and just find my mask for each gas school down more I consign this mass by looking at the by determining the number of moles in my system multiplied by the molar mass the molar mass. Obviously something we can find the normal moles when you take a little second calculated out everything of initially in our system. What's happening? We have the gas is separated by a partition. So while they're in this partitions, we can treat them as an ideal gas of accuser ideal gas law. As shown here, using the given pressures temperatures in our system and using her ideal gas constant, we can find the number of bowls for each gas, which then can allow us to use this relationship above for out or energy so I can expand on my previous line when the sneer Now we're not losing 15 killed. Jules, we're losing eight killed joules of energy. And this line, of course, we have again this expansion of this line. We have the number of moles of neon times of molar mass, which I can look that up panzer specific heat times, our final temperature minus our initial temperature remaining in Celsius. As you can see, it's necessary to cancel out the units here. So my final answer I used initially will be reported in Celsius, and then we can expand it to Calvin if you'd like. So essentially all we have now is this one big line that's essentially a big algebra problem. Or on the left hand side, we have a numerical value of eight killed, Jules. And from this, only if do is expand out a little bit. Do a little algebra, which the previous line I skipped and they we'll skip again, was my solution of the previous question. So in order to find it again, just maybe one or two more lines and algebra, which I think are specifically interesting what if you do that? We would find that our final temperature is 27 degrees Celsius or, of course, 300 kelvin. It was our solution for part of a in part B. Only defined is our final pressure off our mixture, which in a scenario it is an ideal gas. Excuse me, and so begins her ideal gas relationships, holding for pressure. Consider values. So the total number of folds in this question to credit last remains the same. The silver seen I go Gas constant. Put in this scenario. Um, our final temperature teams from 289 to 300 Kelvin and we would find that our final pressure of their mixture is 144 pointed one killer pass scales 141. Excuse me. And for you, homeboy. Principally 141. There you go. I was right. It was 1. 44. I said the wrong one. I should look me notes Merry go. 144.1 Killer Pascal's. And there you go. So, using ideal gas law and our expression for energy exchanger heat exchange, we can solve this problem.


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