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1 For Adx)ouou subsct of R under what circumstances any, 8...

Question

1 For Adx)ouou subsct of R under what circumstances any, 8

1 For Adx)ouou subsct of R under what circumstances any, 8



Answers

Under what circumstances, if any, is $L_{q}$ equal to $L$ ?

Time we want to solve negative to our plus eight equals negative one. And we start by unraveling this in reverse order of operations. So I'm gonna subtract eight first and that leaves me with negative to our equals. Negative nine. And then since I want the are by itself And it's currently multiplied by that to our I will that negative to I should say I will divide by that negative to to get the are alone So I will have our equals nine halfs. And then, of course, we always want to check So negative two times nine halfs plus eight Is it equal to negative one? So this too in this to cross off I get negative nine plus eight is that equal to negative one And it is indeed true so are equals 9/2

You know this problem we want to find the value of N, choose one. Now in general in choose our is able to in fact Toral over our factory and minus our factory. I'm making use of that here to find and choose one, then this is equal to in fact Toral over one factory in minus one factory Now one factorial is just one. In fact total means in times in -1 Times in -2. All the way down, two times three times two times one. I said one factory was just once we don't need it And then in -1 factorial is in -1 and minus two all the way down three times 2 times one. Now notice here that we have an N -1. On down, both on top and on bottom and so those the law cancelled. So the only thing we left here is in its our answer, it's just yeah.

Are. So if the occurrence of one event has no effect on the currents off the second event, then this two events are independent. Where I saw this tube in depends nothing on each other. So we call it that institute and so independent. If, on the other hand, if you want the occurrence of won't even has has effect on the occurrence of the second event, then we called it dependent right. In this case, it's independent.

The problem we want to find the value of N choose and minus one. Not evaluated combination. It's important remember that in choose our is equal to in fact Toral over our factory. All in minus r fact or. And so making use of that here in choosing my swan is equal in fact to roll over In -1 factorial one. Factory. In fact corals in times N -1 all the way down, two times three times two times one. In -1. Factorial is in -1 and mine is too On down to three times 2 times one and then one factory is just one. And so we don't need it Now we have an N -1 on top and bottom. And so all of those will cancel just leaving us within. And so that means in choose and -1. It's just yeah.


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