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You performed the limiting reagent lab as described in the lab manual If you used 0.36 g of sodium bicarbonate to reach the endpoint with 5.00 mL of vinegar (acetic...

Question

You performed the limiting reagent lab as described in the lab manual If you used 0.36 g of sodium bicarbonate to reach the endpoint with 5.00 mL of vinegar (acetic acid in water) , what is the % v/v of acetic acid?The molar mass of sodium bicarbonate is 84.007 g/mol. The molar mass of acetic acid is 60.052 g/mol and the density of acetic acid is 1.049 g/mLPlease enter your answer as a % not in decimal form:Your Answer:Answer

You performed the limiting reagent lab as described in the lab manual If you used 0.36 g of sodium bicarbonate to reach the endpoint with 5.00 mL of vinegar (acetic acid in water) , what is the % v/v of acetic acid? The molar mass of sodium bicarbonate is 84.007 g/mol. The molar mass of acetic acid is 60.052 g/mol and the density of acetic acid is 1.049 g/mL Please enter your answer as a % not in decimal form: Your Answer: Answer



Answers

A $25.0 \mathrm{~mL}$ sample of vinegar with a density of $1.01 \mathrm{~g}$ $\mathrm{mL}^{-1}$, containing acetic acid, was titrated using $0.504 \mathrm{M}$ $\mathrm{NaOH}$ solution. The titration required $42.54 \mathrm{~mL}$ of the base. What was the molar concentration and the percent by mass of acetic acid in the vinegar?

So in this video, we're gonna go over Question 80 from Chapter four, which says a 10 milliliters sample of vinegar and a quick solution of acetic acid eyes tight, traded with 0.5062 molars sodium hydroxide and 16.58 milliliters is required to reach the prevalence point. In part, they were asked, What is the polarity of the seed of acid? So how could we? How could we possibly figure this out? So first we want to know what iteration is. So it's iteration is where we gradually add quantities of base to a solution of acid or gradually add acid to the solution of base. Um, until the pH changes, Um, as we add that a CZ we add based to our solution of acid are pH will change. And when we reach the equivalence point of the Thai trey shin, you'll have a neutral pH because all of your acid will have been neutralized by base. Um, so we know that at our equivalence point, the number of moles of base that we've delivered must equal the number of moles of acid that we started out with, because that's how many moles it took to neutralize all of the acid so we can use the fact that we, um that we had this very specific volume to reach the goblins point to know how many moles of acid that we started out with, and then we know the value of the samples. So then we can calculate the concentration. So let's do that. We have a number of miles of hydroxide ions are number of most of sodium hydroxide that we've added is equal to the volume that we've added times the concentration. So we have 0.1658 leaders of 16.58 milliliters times 0.5062 moles per leader. And that gives this 0.8394 moles and the drugs the same number of moles on of acetic acid that we started out with. So we take that number of moles and we divided by the volume of our sample, which is Tena leaders or 0.1 leaders. And that gives us 0.8393 Mel's prove leader. So that's our concentration of acetic acid. Next and be were asked if the density of vinegar is 1.6 grams percent per cubic centimeter. What is the mass percent of acetic acid and vinegar? So the mass percent is equal to 100% times the mass of your soul. You divided by the mass of your solution in this case are Saul. You is acetic acid. And our solution is vinegar, eh? So how are we gonna get our mass of acetic acid? Well, we can take our number of moles that were in our 10 milliliters. Um, and multiply that by the molar mass. And that tells us what massive acetic acid is in 10 milliliters. Um, of our our solution. So we have points 0.5040 grams of acetic acid. Um, and in our solution on and then we want to know how much our 10 milliliters solution ways. So we take our 10 milliliters and we multiply it by 1.6 grams per cubic centimeter on me and a cubic centimeters. The same thing is a middle leader. So our units of mill leaders cancel out and we're left with grams, so our vinegar solution weighs 10.6 rounds. S. O R mass percent is just 100% of times the mass of our acetic acid divided by the mass of our vinegar. That gives US 5.1%.

Chapter six Problem 76 tells us about a tie trey shin of vinegar with an a O. H and asks us to determine the polarity of the acetic acid in the vinegar and the mass percent. So first, what's right out chemical equation To determine what's happening in this tie. Trecia. We're starting with an a quickest solution of acetic acid or H C two h three po to, and we're tight, treating it with any Ohh! Every asset. Base reaction gives us water and assault as the products. So in this case and a C two h 302 we can see that this equation is already balanced. So now let's determine the polarity of our acetic acid. The equation tells us that we had 0.5062 Moeller of N A. O. H. And that we needed 16.58 mills to complete the tight rations. From here we can determine the number of moles. Remember that moles equals polarity. Times leaders. So for N a o. H. We have 0.5062 moles time 0.1658 Leaders. That gives us 0.839 malts From our chemical equation, we see that the moles of any O. H is equivalent to the molds of acetic acid. Therefore, this is also the number of molds of acetic acid. We have the number of moles, and we're also told that we had a 10 mill sample. Therefore, we could do moles divided by leaders to get malaria T that tells us that the polarity of acetic acid 0.839 divided by 0.1 leaders or 0.839 Moeller. That's the solution to part a. Next for Part B, we need to determine the mass percent. We're given the density of the vinegar solution, and we already have the moles of acetic acid. Using these, we can calculate the weight of the entire solution and the wage of just the acetic acid. So let's start with the acetic acid. We had 0.839 moles. So if we multiply by the molar mass, which in this case is 60 we find that we have 0.504 grams of acetic acid. Next, let's use the density to calculate the mass of the whole solution. The density is 1.6 grams per mil and we had 10 mils of solution. Therefore, we have a mass of 10.6 grams finally to get the mass percent will do 100 times the mass of acetic acid over in the mass of the solution, which gives US 5.1%.

In this problem were asked to determine what mass of sodium acetate can be created from mixing 15 grams of sodium bicarbonate with 125 milliliters of a 1250.15 Moeller acetic acid solution. Our first step in this problem is going to be determining the limiting reactant because the number of moles of the limiting react it will be used to calculate the mass off the product later on in the problem. So we can start with our sodium bicarbonate. We can take the grams that we were given in the problem statement, and we can divide by the molar mass of sodium bicarbonate to get ourselves into millions. So we have 0.179 those of sodium bicarbonate, and we can repeat this with acetic acid and I'm gonna abbreviate. This is a A for the rest of the problem. So we were given a Moeller concentration of arsenic acid and we were given a volume of that solution in milliliters. So weaken doing unit conversion on our volume, then multiply by the volume of our solution and we find that we have 0.188 moles of acetic acid so we can take the morals of our sodium bicarbonate that we determined and see how many moles of acetic acid are needed to fully react that sodium bicarbonate and that will help us determine which is the limiting react. So if we're using our sticky a metric coefficients here, we know that for every one mole of sodium bicarbonate that one mole of acetic acid is required. So to fully react to the entire amount of moles of sodium bicarbonate that we have, we need an equivalent amount of moles of acetic acid. And because we don't have this amount of moles of acetic acid, this makes acetic acid or limiting reactant. So in order to find the mass of sodium acetate, we're going to use theme out of moles of acetic acid and perform dimensional analysis. And we're using the moles of acetic acid because we determined that that was the limiting reactant so we can start with the amount of moves that we calculated above, and we know that for every one mole of acetic acid, we require one mole of our sodium acetate. Then to get our units into grams instead of moles, we can multiply by the molar mass of sodium acid e. And if we perform that map we get, our final answer is 1.54 grams of sodium acid e.

And this problem. We're given a lot of information about a base in an acid and asked to calculate the polarity of the asset. To this end, we're gonna use the equation for malaria and a peaceful to number of moles divided by volume and leaders. I noticed that this equation can be written in three different ways. We can solve for polarity, consult for moles, and Ripe says, and the times, um, is equal number of moles. Or we can call for volume and find the volume A sequel to number of Moles by mole Aridity. These will serve you well as you move through these. Now, I'm gonna go to this thing a lot of detail if you're just here for the solution and you want to see the one step shortcut way of Stoke Yama tree pill tree. Um, but I will take the time to explain each step conceptually. So if you want to skip ahead to the end, you can go ahead and do that. So we have, uh, a lot of information about the space over here knows we have volume and the polarity. So we're gonna use that information to find the missing piece that's the number of mulch to our first step is going to be to find the number of malls of anyway. H the reason why we want more than a wage. Because in this reaction, we're told by nature of the reaction that one more of any U. H reacts with one roll of acetic acid so that I can use the multi more ratio to find malls of the feet of Katherine. So notice that would that does is it gives us more of this substance, and with the volume we can then find the polarity that we're after. So that will be. Our final step is to find similarity up the acid history seal, too. So let's start with that. First, I need my volume in leaders. So this is 0.947 leaders. Polarity it serves us to remember, can be written as you're appointing 00 molds for every one leader. I noticed that when I multiply these together, the leaders cancel out nicely and their product is you're a point. You're a point hero who want each night four well, sodium hydroxide. Okay, now recall that we said that for every one more sodium hydroxide. We have one more of acetic acid, so I don't really need to do any math here. I just know that because of this want to one ratio that I have just as many moves of acetic acid as I did sodium hydroxide. No math involved. I just already know the next step. And then now what? I have multi story of acetic acid volume of the Vedic acid. I confined the polarity by the fighting, given the definition, Willard. So I have 0.1894 more divided by the volume, which in leaders his Euro point Nero to 50 leaders motive units of molds divided by leaders. This is equal to 0.7576 mold over leaders, which is the same thing. Moeller and I'm going to round three significant figures, given that I had three significant for years and all of my initial givens with 0.758 look okay, now let's talk about the shortcut. You have a good grip on all of these things. You can kind of conceptual work your way through it all in one go. So let's start with the volume of acid, just as we did at the top. I have this many leaders of nitric acid, so I need to multiply by the polarity of nitric acid you can treat this polarity is a conversion factor. She could write it either with moles in the numerator, leaders in the numerator and the unit that comes before is gonna guide you. I mean, those us to cancel Next. Remember, we had to change substances. We do that using multiple ratio. One more of acetic acid reacts with warm bowl. Sure, I am. Keep writing H in the three. My God. And the problem back there should be any Uhh you don't really know when will the new age. And finally, I can't divide this results by the volume. Remember, that's for what I have, leader. So your small small This whole product gives me multiple acetic acid and I'm gonna divide mulled by leaders Europe with 0 to 50 beaters, acetic acid solution And what that will give me Smalls, former leaders or polarity. All of that is equal to the same 0.758 Moeller. I don't know, it's the same. I basically did the exact same process the whole way down. This is it in one


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