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The base protonation constant K of lidocaine (€,"zNONH) is L.IS* 10 Calculate the pH of a 088 M solution of lidocaine at 25 %€. Round your answer t...

Question

The base protonation constant K of lidocaine (€,"zNONH) is L.IS* 10 Calculate the pH of a 088 M solution of lidocaine at 25 %€. Round your answer to decimal place

The base protonation constant K of lidocaine (€,"zNONH) is L.IS* 10 Calculate the pH of a 088 M solution of lidocaine at 25 %€. Round your answer to decimal place



Answers

The $\mathrm{pH}$ of a $0.50$ -M solution of the weak base ethylamine, $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}(a q)$, is $12.17$ at $25^{\circ} \mathrm{C}$. Determine the value of $K_{\mathrm{b}}$ for ethylamine.

Here. Given page of 0.10 Mueller. A quick solution of formic acid is 2.38 at 25 C. We have to find out the as if the association constant kill a formic acid. Now ph given is 2.38 Peaches Negative Blog had two near my own concentration. That is 2.38. Therefore concentration of a still plus is Tend to depart negative 2.38. So the concentration of high do near my own is zero 0042 more. Like now let's write that dissociation reaction of formic acid, A C. W. Age less water H C double O. Minas. Yeah. Okay. Plus a studio plus let's make that concentration table Initial concentration 0.10 moller change concentration minus X. Yeah six and high dona most plastics. An equilibrium concentration 0.10 -6 eggs and hair, eggs. Let's ride the expression for that. K. A. S. E. Dissociation constant K. A. Is equal to concentration of IS C. W minus times concentration of is three plus divided by the equilibrium concentration of formic acid. There's X times X divided by 0.10 minus X. Here, X is the concentration of Haida Niermeyer which is equal to concentration of that. Form a tile. So this one will be 0.00 for two Square if I did by 0.10 -0.0042. So the value for K. A. is 1.8 times 10 to the power negative four morgan

To solve for the ph of this solution, We first need to make sure we can use the assumption or not. To determine whether we can use the assumption, we need to calculate what K. A. multiplied by 100 is it's .14. This is greater than the concentration of the weak acid we have, which is .02. Therefore we cannot make the assumption and we need to use the quadratic formula. So using the quadratic formula K. A. Which is provided is going to be equal to the hydro knee um concentration squared divided by the initial acid concentration minus the hydro knee um concentration. I'm not going to go through the algebra as you should be versed enough in algebra to be able to solve this. Using the quadratic formula. When solving it. Using the quadratic formula we get a positive and a negative number. The positive numbers 4.64 times 10 to the negative three. We can't have a negative concentration ph then is simply the negative log of this hydro knee um concentration or 233

Mhm. In this question, a 0.750 mol solution of a mono protic acid is known to be 1.7% ionized. We have to find out the ph of the solution also we have to calculate the value of K. For this asset. So that given as it is 0.0750 mon a protic acid, mono protic acid. Mhm. And it is 1.07% ionized. And let's start writing the reaction and let the mono protic acid B 80 so eight A plus water producers a minus and 83 or plus. Now let's draw the ice table division. Yeah. Mhm. Yeah. Mhm. Here the initial concentration Which is 0.0750 moller dear. Oh dear! Oh now things concentration less minus X plus X plus X. And here equilibrium concentration will be +0750 minus X. Here X. X. Now this solution is 1.7% ionized. So X will be 1.07% of 0.0750. So the fellow forex will be 0.0008025. Their stuff. Hello four eggs. Now excess concentration of high Dona Mayan. Therefore concentration of high Dona maya is 0.80 to five. So ph will be create means negative log hi dani. Um And concentration will be negative log 0.080- five. There are four p is 3.096. Now we have to figure out that K. E acid ionization constant. K. A. Will be concentration of a minus times concentration of high Dooney um iron divided by the concentration of the acid. Now a minuses X H. T. O. N. Plus and concentration also eggs. And this one is 0.0 point +0750 minus six. All the equilibrium constant that is K. A. Now we know that hello for X. Which is 0.8025 square x square. And here 0.750 minus the Hello affects which is very small. Still we are using since we know this one. Therefore K. A. Is this one? Now uh value for 0008025 square is 6.44 times 10 to the power negative seven. And if we subtract this one we get 0.742 Now we get eight 67 times 10 to the Power -6. That this is the value for. Okay. So we got A. A. And also that ph right and the ph was here That is three 096

In this question, we have to calculate the ph of a solution that contains 0.15am. Acetic acid and .25 a. m. a city dial and K a four as it take as it is given us 1.8 times 10 to the part. Negative five now. From Henderson. Yeah. Okay. Yes, right. Henderson has looked back. Equation, we can write pH, please speak a plus. Log concentration of the salt divided by concentration of that s e now pick a is minus log K. Here it is. 1.8 times 10 to the four negative five plus law. Concentration of sort is 0.25 divided by concentration of STD's 0.15 Now negative log. 1.8 times 10 to the poor, minus 574 point 745 Plus log of .25. divided by .15 is 0.22 and We get the P eight is 4.97


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