5

LAAMPLLpolice car mth 600 Hz siren traveling 'long the same street motorcycle Tne velocities of the two vehicles and the distance between them are given each ...

Question

LAAMPLLpolice car mth 600 Hz siren traveling 'long the same street motorcycle Tne velocities of the two vehicles and the distance between them are given each figure.Iu nu' 052 1S mIQItC€C4xDEU Mu0107Rank the frequency of the siren Js measured by the motorcycle rider 8 >A>D>€ C>0>a> D >8 >A>€ BeC>aed Allhear the same frequency:

LAAMPLL police car mth 600 Hz siren traveling 'long the same street motorcycle Tne velocities of the two vehicles and the distance between them are given each figure. Iu nu' 052 1S m IQIt C€ C4xD EU Mu 0107 Rank the frequency of the siren Js measured by the motorcycle rider 8 >A>D>€ C>0>a> D >8 >A>€ BeC>aed Allhear the same frequency:



Answers

A police car sounding a siren with a frequency of 1580 Hz is traveling at 120.0 km$/$h. ($a$) What frequencies does an observer standing next to the road hear as the car approaches and as it recedes? ($b$) What frequencies are heard in a car traveling at 90.0 km$/$h in the opposite direction before and after passing the police car? ($c$) The police car passes a car traveling in the same direction at 80.0 km$?$h. What two frequencies are heard in this car?

Everyone. This is a problem based on Dr Effect, A source and Islam both are approaching towards each other. The frequency of the sound received by the national is B s Be not over B minus base, no substitute. Develop frequency is 5 23 hertz. Frequency of sun in air 3 43 that is speed by which listener is approaching is 14.8 m per second and the sorts by which it is approaching to our service Neris 32.2. So it is to me 602.1 Hertz that so Thanks for watching it.

Here. We have a kiss in the first case in part A Ah, the observer is especially. So Observer is especially, uh, stationery, stationery. And, um, a source is approaching. So we have a source. Right? So our source is approaching. Um, So I approaching approaching before approaching our right shortcut. Then we can write a frequency. So sorry. I already wrote a frequency of four source moving tours. Source moving toward MT. Eye right. Can be written as a frequency. Oh, we're, um one minus speed off the source S O s. Alright. Right here for the speed of source. Or, um, this speed off the sound, which is yes. Then frequency we have here is a 12. 80. If he's a 12 80 or one minus force is having a speed 1 20 kilometers per hour, which, if we can work into a meter per second, then it becomes 33.33 33 Um, as usual, their speed off a sound is a three 43 3 43 meter per second. So, um, by dividing these two numbers than the frequency off the source moving towards we get here is 14. 20 14 20 Hertz, um, frequency for a source which is moving and approaching, so approaching. Hey, I'm right here. Well, Britain is f or one plus the speed of the source source or the speed off the sound that is equal to buy the plugging the value off 12. 80 and 33.3 tree for the speed off the force or ah, the sound speed. Then the answer you get here is 11 Ah, 70 hearts. This is a frequency for source moving approaching, um, in part b for the case when both observer and source are moving So observer and source of moving and we can write the frequency, uh, for approaching is equal to frequency times. Um, speed of the sound, yes, the speed of the observer or or the speed of the sound minus the speed off the source. And this gives us, um, we can put the value, um, by converting a 90 kilometers per hour into um meter per second, which is 25 meters per second. Replied the values here, which is so f is a 12 80 as we rode previously. Speed off the sound is 3 43 pass. Ah, they were lost. He or the speed off observer is a 25 meter per second and working from kill me to put our and for a second Oh, we're, um the speed off the sound 3 43 Subtracting the source speed, which is 33 going to three. Three tree meter per second. And by doing your mats, the non. So we get here is a 15 20 hertz, 20 hertz. This is for a frequency approaching now. Frequency for receding. Um, let me write it here. Frequency for receiving weaken Right here. So right, R e for a sitting, we can write. This formula is f into of yes, minus the speed off observer or mmm, speed off the sound plus the speed off the source. So as our c I would like for source and, um as we did previously by putting the values for ah, speed of the sound and speed of the observer and speed of the source. The answer we get here for receding frequency is 1080 hurts A de hurts. So this was a part B in part C. Both source and observer are moving. So we have a situation in which source An observer I'm in. Then we can write the frequency off. Police car Police car approaching Fortune will be equal to our frequency times. Um, speed off the sound minus speed of the observer will be divided by the speed off the sound The minus speed of the source. We can, uh, pluck the values as we did previously. Um, for the speed off observer only here we have is frequency, as usual, is a 12 12 80 12 80 a zoo jewel. The speed of sound is a 3 43 minus the speed off observer which is a 22 point to tool to to hear, or the speed of the sound, which is again three for three minus the speed off the source 33 point 33 33 Then doing a simple mats deriding these numbers than the police car Frequency approaching will be 13 30 herds, herds the inn next case where we have a police car which is receding. The police car receding ari leased car receding can be written as f into, uh, speed off the sont plus the speed off observer or the speed of the sound. Plus the speed off the source. We can substitute the values as we did above. Then the answer we get for the police car receding frequency is 12 40 hurts 12 40 hurts hearts end off the problem. Thank you for watching.

In problem 48. There's a motorcycle in a police car that are approaching each other. We have the speed of each of them. And the police car has a siren with the frequency of 523. And we want to know what frequency the motorcycle guy hears some using the general equation for Doppler effect. Because both my observer and my source are moving, So I'm just going to plug things in my equation. I'm looking for the perceived frequency. Um, here. I know if they're approaching each other, these summaries air getting bunched up. So my frequency is definitely getting higher, so I choose the signs that are gonna make it higher. I'm either choose the top ones or the bottom ones. That's why these air flipped on the bottom. Um, if I'm gonna make this frequency higher, I know I need a big number here, so I need my top to get big. I need my bottom to get small, so I'm going to use the adding on top. I'm going to use the subtracting on the bottom. Um, so one waas the velocity of of the observer, which is the motorcycle V is the speed of the wave, which is sound 3 43 That will be one minus the speed of the source, which is the police car over the speed of the waves, Which is sound times the original frequency, which is 5 23 When I put this in the calculator, I'm just gonna nest a bunch of parentheses. So one plus, we're two parentheses, e owned. It equals divided by I'll use the parentheses. He here. But then I also have a nested parentheses inside here. When I get on the calculator, I get a perceived frequency of 602 hertz.

For this problem. On the topic of sound waves, we are told that a stationary observer, here's a frequency of 560 Hz coming from the siren, often approaching police car As the police car passes, the frequency is observed to now be 480 Hz. And we want to find the speed of the car from these observations. Now, for the approaching car, using the Doppler effect equation, we have the observed frequency of prime is equal to the source frequency F divided by one minus the speed of the source, via is divided by the speed of sound and air V. For the police car. Moving away, the observed frequency F double prime is equal to F over one minus -3 over v. Now F prime, We are given to be 560 Hz, And f double prime is given to be 480 Hz. And so therefore, Mhm. Mhm. 560 into one minus V. S. Over V. Is equal to 480 Into one plus v. S. Over V, which means that 1000 And 40 times v. s. of v. Music bo 2 80. So rearranging we get the speed of the source, which is the speed of the police car to be 80 into v, which is 343 m/s, Divided by 1040. This gives the speed of the police car To be 26.4 meters per second.


Similar Solved Questions

5 answers
Question 1 (5 points) Determine %hethor cach statement 15 somctumcs, always Or never trueIf thc Folumcs of tWo ttangulas prisms Jc thc samc , the prisms are congrueatsomctumcsnc!cIalays
Question 1 (5 points) Determine %hethor cach statement 15 somctumcs, always Or never true If thc Folumcs of tWo ttangulas prisms Jc thc samc , the prisms are congrueat somctumcs nc!cI alays...
5 answers
The following molecule hasasymmctric centers and maximum of _stereoisomers.2' =) yDraw the R and $ configurations of 3-chloro-I-butene.The following compound has only one asymmctric centcr: Why; then; does it have stereoisomers? CHCH-CHCHCH; Pls Li5 Itres OH
The following molecule has asymmctric centers and maximum of _ stereoisomers. 2' =) y Draw the R and $ configurations of 3-chloro-I-butene. The following compound has only one asymmctric centcr: Why; then; does it have stereoisomers? CHCH-CHCHCH; Pls Li5 Itres OH...
5 answers
1 F 8 8 V IM 82h8 2 ! 8 8 4 1 1 1 '1 1 W 1 8 } I
1 F 8 8 V IM 82h8 2 ! 8 8 4 1 1 1 '1 1 W 1 8 } I...
5 answers
> WWi "22e2 7 L 8 2 8880& W Ma 5 2 8 1 li 5" 6 2 91 8 & 5 1 0 W 3 7 1 0 W 2 g 3 V Qi 7 88 1 lg 4 3 3 3
> WWi "22e2 7 L 8 2 8880& W Ma 5 2 8 1 li 5" 6 2 91 8 & 5 1 0 W 3 7 1 0 W 2 g 3 V Qi 7 88 1 lg 4 3 3 3...
5 answers
Solve 5x = 125 using the one-to-one property of exponentsA) x= In(125)B) x = 5C) x= 1D) x = 3
Solve 5x = 125 using the one-to-one property of exponents A) x= In(125) B) x = 5 C) x= 1 D) x = 3...
5 answers
22 2 2 55 3 * 2" iiiiiii 6 8 1 z 1 F E 5 2 7 2 [ 2 { [ 1 38 1 [ 1 2 6 1 L! L { | [ 1 23 1 { | [ L 1 3 1 1 #S L 7 3 2 3 L 1 F 1 2 : 01 E} 0 8 11 2
22 2 2 55 3 * 2" iiiiiii 6 8 1 z 1 F E 5 2 7 2 [ 2 { [ 1 38 1 [ 1 2 6 1 L! L { | [ 1 23 1 { | [ L 1 3 1 1 #S L 7 3 2 3 L 1 F 1 2 : 01 E} 0 8 1 1 2...
5 answers
Homework Question 8.26 Homework UnanswcredHow many mL ofa 1 M NaOH solution would be necessary to neutralilze 200 mL of0.5 M HCI? Give your answer in mLs Type your numcric answer and subrnit
Homework Question 8.26 Homework Unanswcred How many mL ofa 1 M NaOH solution would be necessary to neutralilze 200 mL of0.5 M HCI? Give your answer in mLs Type your numcric answer and subrnit...
4 answers
Your car broke down_ so vou tie rope to vour car and pull the car with constant force to the parking lot: How much work do you do on the car if the rope is horizontal to the ground 0 = 0Q (yellow Iine in image below) and you pull the car 5 meters? How much work do you do on the car if rope is at the angle 0 = 30"for the distance meters? What do vou conclude from (a) and (b)?
Your car broke down_ so vou tie rope to vour car and pull the car with constant force to the parking lot: How much work do you do on the car if the rope is horizontal to the ground 0 = 0Q (yellow Iine in image below) and you pull the car 5 meters? How much work do you do on the car if rope is at the...
5 answers
An AM radio station broadcasts isotropically (equally in all directions) with an average power of 4.00 kW. A receiving antenna 65.0 cm long is at a location 4.00 mi from the transmitter. Compute the amplitude of the emf that is induced by this signal between the ends of the receiving antenna.
An AM radio station broadcasts isotropically (equally in all directions) with an average power of 4.00 kW. A receiving antenna 65.0 cm long is at a location 4.00 mi from the transmitter. Compute the amplitude of the emf that is induced by this signal between the ends of the receiving antenna....
1 answers
Perform the matrix operation, or if it is impossible, explain why. $$ \left[\begin{array}{rr}{2} & {6} \\ {1} & {3} \\ {2} & {4}\end{array}\right]\left[\begin{array}{rr}{1} & {-2} \\ {3} & {6} \\ {-2} & {0}\end{array}\right] $$
Perform the matrix operation, or if it is impossible, explain why. $$ \left[\begin{array}{rr}{2} & {6} \\ {1} & {3} \\ {2} & {4}\end{array}\right]\left[\begin{array}{rr}{1} & {-2} \\ {3} & {6} \\ {-2} & {0}\end{array}\right] $$...
5 answers
Y = (4x2 x)(x - x2)16r' + 9r + 21
y = (4x2 x)(x - x2) 16r' + 9r + 21...
5 answers
Construct 9890 confidence intenval estimate Ihe population mean when x = 127 and a)n=40 b) n=70 c) n=100 Clickbere t0 view_page ollhe critical t-score_table Click here to view page 2 of he critical (~score table29 for the sample sizes below:a) The 98% confidence interval for the population mean when 40 is from lowor limit of (Round to two decimal places as needed )to an upper limit of
Construct 9890 confidence intenval estimate Ihe population mean when x = 127 and a)n=40 b) n=70 c) n=100 Clickbere t0 view_page ollhe critical t-score_table Click here to view page 2 of he critical (~score table 29 for the sample sizes below: a) The 98% confidence interval for the population mean wh...
5 answers
Pleedon 2Wataenn dumieuehenn]clecbic (lua Inl Eulca Wbtueleu ~lcli Iuica IenvtcunWuaceHleaHnmhddeEmmamVatuael naann+q
pleedon 2 Wataenn dumieuehenn] clecbic (lua Inl Eulca Wbtueleu ~lcli Iuica Ienvtcun Wuace Hlea Hnmhdde Emmam Vatuael naann +q...
4 answers
Let C an be a series such that an 0 for all n2 1. If Iim n3 an:thenSelect one:The series 2 an is divergent by Limit Comparison Test:Non of themThe series C an is divergent by nth-Term Test.The series C an is divergent by Direct Comparison Test:The series 2 an is convergent by Limit Comparison Test.
Let C an be a series such that an 0 for all n2 1. If Iim n3 an: then Select one: The series 2 an is divergent by Limit Comparison Test: Non of them The series C an is divergent by nth-Term Test. The series C an is divergent by Direct Comparison Test: The series 2 an is convergent by Limit Comparison...
5 answers
Find the simple interest eamed if the investments were made at RM 20 000 for 4 years 6 months at [1% per annum. Hence; calculate the simple amount.Mary invested RM 30 000 in two accounts. some at [2% per annum and the rest at 8% per annum: Her total interest for one year was RM32OO. How much was invested at each rate?RM 20 000 was invested on 23 March [994at 5% per annum. Find the interest carned on 27 November [994 using Banker' $ rule.
Find the simple interest eamed if the investments were made at RM 20 000 for 4 years 6 months at [1% per annum. Hence; calculate the simple amount. Mary invested RM 30 000 in two accounts. some at [2% per annum and the rest at 8% per annum: Her total interest for one year was RM32OO. How much was in...
5 answers
Twenty married couples were randomly selected Their weekly viewing times; hours_ are presented in the table below. At the 10% level of significance and using paired differences analysis, determine if married men watch less TV "On the average than married womenHusbandWifeHusbandWifeHusbandWife21 56 34 30 41 35 2624 55 55 34 32 38 3838 30 31 30 32 1545 29 41 37 35 48 1736 20 4335 34 32 1316 2123
Twenty married couples were randomly selected Their weekly viewing times; hours_ are presented in the table below. At the 10% level of significance and using paired differences analysis, determine if married men watch less TV "On the average than married women Husband Wife Husband Wife Husband...
5 answers
Calculate E-2)' 2) .ANSWER:Do the sets (0,1) and YOU answer8) have the same cardinality? Answer "YES" or "NO" and justifyANSWER:
Calculate E-2)' 2) . ANSWER: Do the sets (0,1) and YOU answer 8) have the same cardinality? Answer "YES" or "NO" and justify ANSWER:...

-- 0.019199--