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If a 1.00 M solution of an unknown monoprotic acid has pH of 2.75_ calculate the K for the acid_...

Question

If a 1.00 M solution of an unknown monoprotic acid has pH of 2.75_ calculate the K for the acid_

If a 1.00 M solution of an unknown monoprotic acid has pH of 2.75_ calculate the K for the acid_



Answers

The $\mathrm{pH}$ of a $1.00 \times 10^{-2} \mathrm{M}$ solution of an unknown acid is $4.79$ at $25^{\circ} \mathrm{C}$. Calculate the value of $K_{a}$ for the acid at $25^{\circ} \mathrm{C}$.

Mhm. In this question, a 0.750 mol solution of a mono protic acid is known to be 1.7% ionized. We have to find out the ph of the solution also we have to calculate the value of K. For this asset. So that given as it is 0.0750 mon a protic acid, mono protic acid. Mhm. And it is 1.07% ionized. And let's start writing the reaction and let the mono protic acid B 80 so eight A plus water producers a minus and 83 or plus. Now let's draw the ice table division. Yeah. Mhm. Yeah. Mhm. Here the initial concentration Which is 0.0750 moller dear. Oh dear! Oh now things concentration less minus X plus X plus X. And here equilibrium concentration will be +0750 minus X. Here X. X. Now this solution is 1.7% ionized. So X will be 1.07% of 0.0750. So the fellow forex will be 0.0008025. Their stuff. Hello four eggs. Now excess concentration of high Dona Mayan. Therefore concentration of high Dona maya is 0.80 to five. So ph will be create means negative log hi dani. Um And concentration will be negative log 0.080- five. There are four p is 3.096. Now we have to figure out that K. E acid ionization constant. K. A. Will be concentration of a minus times concentration of high Dooney um iron divided by the concentration of the acid. Now a minuses X H. T. O. N. Plus and concentration also eggs. And this one is 0.0 point +0750 minus six. All the equilibrium constant that is K. A. Now we know that hello for X. Which is 0.8025 square x square. And here 0.750 minus the Hello affects which is very small. Still we are using since we know this one. Therefore K. A. Is this one? Now uh value for 0008025 square is 6.44 times 10 to the power negative seven. And if we subtract this one we get 0.742 Now we get eight 67 times 10 to the Power -6. That this is the value for. Okay. So we got A. A. And also that ph right and the ph was here That is three 096

So for an acid h a. The reaction that decay of this would describe is H A reacts with water to form age 30 plus. And then the car, Your base a minus. In other words, this version went over here most bad arrows apartment. And so our mass action expression is going to be the concentration of age trio, plus times a conscious in a minus over the conservation. Ahh, that's just coming directly from my heart equilibrium unit, where mass action expressions. And so now if we could figure out what this amount is at equilibrium, that be great because then we could plug it in, figure out what K is. And so we have an idea. Now, first of all, we turn note that the conscious of H 20 plus and a minus here are going to be equal every time h a forms one of these, it forms the other. It can't avoid that. So these are the same value. Also, we're told the concentration of H 20 plus not directly but indirectly. Remember, the concentration of H 20 plus is equal to tens the negative pH And so in this case, that is negative. 2.95 and so we can get I'll just hold, like that tense and it's 2.95 Moeller is our Constitution basically a plus. And so we'll plug that in here and here cause those are gonna be equal. Were given an initial concentration of H A, which is 0.185 Moeller. But we're also losing this same amount that becomes HBO plus, and so at equilibrium, what we have is we have tense the negative 2.95 squared one from each of these right here and right here and then, Denominator, we have our initial amount 0.185 minus tends the negative 2.95 the amount that went and became a spear plus months. If you did a nice table, you would get the same result. And either way, somehow you gotta plug this into a calculator and you'll find a k A equals 6.84 times 10 to the negative six

Over one morning. We all know that the concentration off each posted for a week as it is calculated using these relation k eight times by the concentration off the week as it so. Now the value off key A will be equal. The concentration off each postive Bauer two divided by the concentration off the week I said So the concentration off each postive is equal timber negative value off B H, which is 4.52 So it will be timber or negative. The value off pH power to dividing by the concentration off the week as which is open toe one night. So the result will be 4.8 times Boynton bore negative nine. Andy Lees is a simplest way to calculate the the value off Key A I think.

In this question will calculate the acid ionization constant for a weak acid. Give him P. eight is 2.95. And concentration of the acid. Yes. 0.185. What now ph minus law. Hydro near my own concentration. Therefore. Hi dani. Um concentration will be 10 to the power negative P. H. Which is 10 to the power negative 2.95 Which is 1.1-2 Times 10 to the power negative three mona. So now we have the concentration of high Dona mile. Now we'll set up the ice table and still that. Oh plus needs to yeah. In my nurse blast is to your class. Of course. Yeah. Yeah. Yeah. Yeah. Yeah. All right mm. Mhm. Okay. Hair. I initial concentration change concentration and E. For equilibrium concentration Concentration of the sed s. Mullah and Will ignore this one. No concentration. Hair. No concentration here then minus six blah six plus eggs. Now equilibrium concentration will be 0.185 minus X. And here it will be X. And concentration of high Dona man. We just calculated that is 1.1 to 2 Times, tend to depart -3. Now we have the concentration of high Dona Mayan. Now concentration of a minus a minus also equals to the X. Value or fix. So concentration of a minus will be 1.1 to 2 times 10 to the power negative three molar. And concentration of the acid H. A .185 minus X. So .185. My not 0.001122 which will come 0.18 388 more. Like. Okay so we have all the concentration now we have to calculate the ionization, acid ionization constant. K. A. E concentration of a minus times concentration of high Dona Mayan divided by concentration of the acid. Mhm. Mhm. No concentration of a my nest is 1.1 to 2 times 10 to the power minus three Hatoyama ion, also same value 12 to 10 to the power negative three, And concentration of the acid 0.183, 8, 8. And it will come 6.8 Times 10 to the Power -6. Therefore, acid ionization constant that is K A. Is 6.8 times 10 to the bar -6. Yeah.


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