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You need capacitance 0f 50.0 pF but you dont happen to have 50.0 pF capacitor: You do have 90.0 pF capacitor:Part AWhat additional capacitor do you need to produce ...

Question

You need capacitance 0f 50.0 pF but you dont happen to have 50.0 pF capacitor: You do have 90.0 pF capacitor:Part AWhat additional capacitor do you need to produce total capacitance of 50.0 pF? Express your answer with the appropriate units:ValueUnitsHA

You need capacitance 0f 50.0 pF but you dont happen to have 50.0 pF capacitor: You do have 90.0 pF capacitor: Part A What additional capacitor do you need to produce total capacitance of 50.0 pF? Express your answer with the appropriate units: Value Units HA



Answers

You need a capacitance of $50 \mu \mathrm{F}$, but you don't happen to have a $50 \mu \mathrm{F}$ capacitor. You do have a $75 \mu \mathrm{F}$ capacitor. What additional capacitor do you need to produce a total capacitance of 50 \muF? Should you join the two capacitors in parallel or in series?

Hi. In the given problem, we need a capacity and solve 50 micro ferret. So equivalent capacitance should be 50 micro ferret. But we don't have any 50 micro for capacitors. We just have our 60 are 75 micro Fareed capacitor and we need tohave Ah, 50 micro for capacity means we need to reduce the value off capacitors. And we know the value off net capacitance is reduced Onley in our cities combination. So to convert 75 micro ferret into 50 micro ferret Suppose we join C two in Siris with 75 micro ferret capacitor. So using the rule off cities combination one by C equivalent is going toe one by C one plus one by C two. Hence the value of this C two will be given by one by sea to visible toe one by C equivalent to minus one by C one or we can save one by C two is able to one by 50 minus one by 70 Fight horse Even have this, Elsie, um will be 1 50. So this is three times and 75 will be two times only. So this is one by 1 50 or we can say a capacitor having a capacitance off 1 50 Micro ferret should be joined in Siris with 75 micro fared capacitor toe Get a net capacitance off 50 Micro ferret. Thank you.

Okay, so let's assume that a tool possibility here. Okay, So the first possibility here is let's connect the capacitor in parallel. So happy equivalent capacity is able to see one. Classy too. So therefore, C two is CQ CQ minus C one si two is the additional capacity we're looking for and see. Choose the recording capacity and see wise de capacity. We are already half so we know cuz. Go to 15 macro Ferre and see once you lose 30 Michael para so therefore see, too. Vehicle dio um 50 Micro Feraud minus 30. Michael Ferrat. This will give us 20 Michael Vera so you can find the additional capacity with a capacity in 20 Michael Cera and connect these capacitors in parallel. Okay, so this is, uh, first possibility and let's take a look. A the septum possibility. So that's trying to canal de ah capacitor in serious. So have one oversee who is equal to one over c one plus one or C two. So we have long was he too is a good one. Overseeing here might as well have a C C one. So therefore C two is even longer CQ minus one of us. You want to apartment one we know seeing he was 15. My prepare a C one story. My pop era. So therefore, see to shoot people too. 1/50. Michael Faraday, minus 1/30 Michael Farrell to the power of in everyone. And this is equal to next year 75. Michael Farah. And we know the capacitance and never inactive. So therefore, this case is impossible. So the only possible case is the first case, which is, uh, connect additional confessor with the capacity 20 Michael Vera in parallel with the, uh, other capacitors. Okay. And these are the answers for these questions.

Hi. In the given problem, we need a capacity and saw 50 micro ferret overall. But we don't have 15 micro fatted capacitance. We just have a capacitance off 30 micro Farage. So we are having capacitor off just 30 micro ferret. But we need to make it 50 micro fair. It means we need to increase it. And as we know, the capacitors are increased only in parallel combination. As we know the value off net capacity tense is increased on Lee in parallel combination. So here we should join our 20 Micro Farid capacitor in parallel with 30 Micro Parrot the capacitor. Thank you.

So here we have three capacitors where one's gonna have capacitance of 3200 times into the minus 12 Farage's The Second is going to have a pass tins of 7500 times, somethin minus 12 Baird's, and the third is going to have capacitance of 120.1 time sent to the minus six ferrets. And so, if we want to combine these, the maximum capacitance weaken get is if all of these are in parallel and the capacitance, if they're all in parallel, is just the some C one plus C two plus C three, and the total capacitance is going to be 21 nano ferrets or 21 time sent to the minus nine ferrets that'll be our maximum capacitance now are minimum capacitance is going to come. If all of these capacitors are in Siris with each other, then we're going to have equivalent pastors one over C one plus one over seat to plus one oversee three all of that to the minus one that's going to equal to Nana Fareed's. That's a minimum. So again, the maximum happens when thrill in parallel and the minimum happens when they're all in Siris


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