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Write balanced net ionic equation for the reaction of AgNOalaq) with KBrlaqlAgNO_laq) KBrlaq)AgBr(aql) KNO3(s)Agt(aq) NOz (aq) Kt(aq) Br (aq)Ag (aq) Br (aq) KNO3(s)...

Question

Write balanced net ionic equation for the reaction of AgNOalaq) with KBrlaqlAgNO_laq) KBrlaq)AgBr(aql) KNO3(s)Agt(aq) NOz (aq) Kt(aq) Br (aq)Ag (aq) Br (aq) KNO3(s)AnsweredAg (aq) NOz (aq) + Ktlaq) Br (aq)AgBr(s) Kt(aq) NOz (aqlrrect AnswerAgt(aq) Br (aq)AgBr(s)There no reactionQuestion 91 / 1 ptsThe solubility of Pb(NO3lz is 55 grams per 100 g HzO at 20 %C Which term would properly describe solution where 44 grams of Pb(NO3lz is added to 100 grams of water at this temperature?insolubleCorrectlu

Write balanced net ionic equation for the reaction of AgNOalaq) with KBrlaql AgNO_laq) KBrlaq) AgBr(aql) KNO3(s) Agt(aq) NOz (aq) Kt(aq) Br (aq) Ag (aq) Br (aq) KNO3(s) Answered Ag (aq) NOz (aq) + Ktlaq) Br (aq) AgBr(s) Kt(aq) NOz (aql rrect Answer Agt(aq) Br (aq) AgBr(s) There no reaction Question 9 1 / 1 pts The solubility of Pb(NO3lz is 55 grams per 100 g HzO at 20 %C Which term would properly describe solution where 44 grams of Pb(NO3lz is added to 100 grams of water at this temperature? insoluble Correctl unsaturated saturated supersaturated



Answers

(a) Use the solubility rules to write the balanced net ionic equation for each of the following "molecular" reactions. If there is no net reaction, write "NR." (b) Which of these three reactions give clear visual evidence of the ion exchange process? 1. $\mathrm{NaCl}(a q)+\mathrm{AgNO}_{3}(a q) \rightarrow \mathrm{AgCl}(s)+\mathrm{NaNO}_{3}(a q)$ 2. $\mathrm{NaCl}(a q)+\mathrm{KNO}_{3}(a q) \rightarrow \mathrm{NaNO}_{3}(a q)+\mathrm{KCl}(a q)$ 3. $\operatorname{MgCl}_{2}(a q)+\mathrm{KOH}(a q) \rightarrow \mathrm{Mg}(\mathrm{OH})_{2}(s)+\mathrm{KCl}(a q)$

A similar problem. 89. We simply need to identify what the precipitate is. That precipitate, if there is one, will then allow us to identify what ions are required to form to form that precipitate it. And then we can write the Napoleonic equation. Barium carbonate forms a solid. Therefore it is the berry and two plus coming from the barium chloride in the carbonate coming from the sodium carbonate that produces the barium carbonate. This being the Net Ionic equation for the next one, all reactant and products are soluble. They're all spectator ions. No reaction occurs for the last one. Calcium phosphate formed as a precipitate. Therefore, the Net Ionic equation is three. Calcium two plus is reacting with two phosphates form. Are calcium phosphate solid? Because precipitates forum in the first and the third reaction, these examples of I in exchange

In this question we have been asked to look into the cell ability of the products that are going to be formed from the given income culture. So for the first election we've been given H. Two S. Or four last Calcium c. l. 0. 4. Sure so the product that are going to perform here this is going to be a double replacement reaction. So we're going to be forming calcium self had plus hcl or form this is an actual solution. This is also an actual solution but from the soul ability rules calcium self that is insoluble. So this is going to be our solid but this is also solid. So remember when we want to write the energy have to look only at those species that are in archaea solution. Those are the ones that form ions in solid. So for the net ionic equation we have to split those accursed compounds into their corresponding iron for example H two S. 04 is made of room malls of H plus ions plus and more of Yes or for the sulfate irons Plus see a two plus irons from the calcium back loaded. This is going to be a plus more models of pig ignorant. All right moving on this is going to be performing cuts himself had this is going to be a solid. It is a precipitated it is in solid book so it won't from ions in solution plus H plus irons plus C. L. O. Mm minus items. So looking at this if we now want to write the net ionic equation we have to remove the spectator islands. Those are the islands that appear in both the reactions and the final product this time around this is going to be our hydrogen iron and we have our hydrogen ion also here our remember looking at this this is not a balanced reaction. So we have yeah balance this out. This is going to be to malls and two moles of No. So in terms of the spectator irons are spectator ions are those that appear in the reactions and the product and these are our hydrogen iron and also pig nor it. I am. So once you have removed our spectator items we have been going to have the innate of our creation where we have S 44 to minus ions in aqueous solution. The action with calcium to blast ions in aqueous solution to from air calcium sulfite precipitate. So this is the net ionic equation. So this is the approach that we're going to be applying. That is we look at what is an aqueous solution and then we split those into the corresponding irons, remove the spectacular irons and then have a final I am the equation. And then moving on to the next one, we've been given a G. N. Or three. This is an actual solution plus N A C. L. Or four also in actual solution from our what is going to happen here. This is w replacement. So this is going to be a G. C. L. Or four plus an A. Uh huh. Three. Now from the general, from the general rules of scalability, what is going to happen is what silver pick Loretta. Uh So LeBeau and also sodium hatred. Both of these are solid. So looking at this products that are formed, it means if these both both of these are actually solvable, it means that there is no reaction that is going to be occurring because at the end of the day, if these are also solved, it means irons that we have in solution as the product. Also the irons that we're going to be having in solution because all these are just going to dissolve in solution. They are performing the same ions. So in general or in essence there is no reaction that actually Okay And then moving on to the next one, Well we've been given HG two and or three. So this is an actual solution blast NAC seven H five or 2. This is also in our case solution. What is going to happen is product that we're going to perform the ears. H G H G two, H G two. And the iron part of this is C seven H five or two. And then this is we add this who will also add sodium nitrate. This is W replacement. So from the general guidelines of scalability, make your results are insoluble. So this is going to be solid. But how can they get The metals are generally soluble. So this is going to be in our care solution. So again, if we split these into the individual irons and we remove the spectator as the overall reaction is going to be H G two plus irons and Archaea solution. Last two moles. We have two miles of C7 H five or two minus ions in aqueous solution. Reform HG to C seven H 5. Well, and this is going to be our sunday and then moving on to the next reaction or next system that we've been given. The last one. Actually, what we've been given is PP CH three C 4 or this isn't asserted. This is going to be in aqueous solution plus K P R. And our culling metal sold which is also in solution. This is going to form PB be attitude blast C H three. See or or Okay, so looking at this information, this LED LED Souls are generally in solid. So this is going to be a solid while this is an actor. So if we do the reaction or split peas, outcast compounds into their individual items the next and the equation is going to be PP to blood irons in solution, blast bromide ions in solution. This is going to be for me E B R two is a solid

Here we have see a three p of four to precipitate on. We're looking for the percentage CEO by Mass, where we have three times 40 point nor 7 8/3 10.18 multiplied by 100 together into percentage while we generate 38.763%. Our equation here is three C A two plus our two h p 04 to minus generate C a P o full add to H. So we do have CEO to bubbles present. We have C 02 at H 12 generates H two c 03 Well, we have see a two plus at H two co three, where we have see a CO three at H two where we have a precipitate formed on. Then we have C A C 03 at h two c 03 generates see a two plus on to H 03 minus, which in fact we dissolves

In this question, we're going to be looking into the scalability of the given combat. That is we've been given incomplete game with our elections and we've been asked to look into the scalability and then we have to look into net. So before we answer this question, let's just look at this in terms of this variability in H2. So as a general guideline, Alcalay alcohol, um Eater of souls and I'm money, I'm sold. These are solid wood in water. Then the next guideline is most. Matrix also have asserted. We also have right. These are also sorry, book in H two. Then again we have silver let and Make your results. These are insoluble and H 20. And then we also have Gloria from my and I a rights that we know to be Soluble in H two. And then moving on, we know that most upon it. We're looking at a cup on it satisfied oxide, hydroxide, It is a these are generally insoluble in water except for maybe body. Um and calcium might look science that are slightly solid. And then finally we look at soffits. These are generally soluble in H. two or except for barium and calcium solve it that are not solely so looking at this information, this is what we are going to be using to predict the suitability of given compounds and the product. So for the first one we look at the first one, we can notice that those two reactions are in our curious form. So what is going to happen is the net the reaction that is going to be happening. It's more like a double replacement reaction. We were going to have ceo C. L toe plus into is from C E O. S Last two miles off so to employ. So looking at the products that we have been that has been formed. We have seen you as and certain employees. So here what we have is we have copper sulfide. This is a self right? So this one is in solid form. So this is going to be there solid. But looking at such time curate, this is an alcohol, a meter salt so this is soluble so it will be in solution. So the net ionic equation here this is going to be Let's just look at this. We have See you two plus we have two moles of chlorate. Irons. Remember ions are only formed by the species that are in our class form. They're looking at sodium we have two and a blast last we have the song for. And the products this is going to be copper sulfide which is a solid Plus two moles of sodium irons plus two moles off chloride iron. So to write the late ionic equation, we have to remove the spectator I am. And in this case these are the sodium irons and the Glory and they are Spectator islands because they are common. All found in both the reactions and the product. So the net ionic equation is going to be suffered. Irons in aqueous solution reacting with cooper two plus irons in anger solution to form air copper sulfide press a bit. So this is the general approach that we're going to be used. So if we look at the next one in the next one we've been given museum from my end potassium up on it. So if we do this, if we look at this, yeah MGB are two plus okay to see or three all of these are in our class form. What is going to perform here is museum cup on it plus two malls of K. P. up. So if we are to look at this information, this is a cup on it. Looking at the general guidelines that we had here completed to say in general components are in solid. So this is not going to be in our classroom, this is actually going to be a solid. And they're looking at K. P. R. This is an al curly metal soul, this is soluble so this is also going to be in solution so to form ions. These are the compounds that are we are going to be splitting and if we follow the same procedure that we followed above. First of all, break down these into irons and then remove the spectator irons we'll find that what is actually happening is we have mechanism irons reacting with upon it. Irons to form our magnesium upon it as a president And then moving on to the next one where we've been given BACL two plus a tool is all well. So if we look at this, the reaction this one, it forms B A S 04 plus K C. Yeah. So if we look at the scalability rules, remember these are in fact this form. So they do form irons. But if we look at the scalability holes we completed to say barium sulfate is not soluble, but this is an alkali metal sort. So this is so liberal, going to be an Arkia solution and this is going to be a solid. So again, if we split these compounds that are in Accra solution and remove the spectator ions, what is actually happening is barium to blast plus S +44 to minus ions in aqueous solution. These were performing but I am so fit precipitation. And then finally, if we look at the one the last one This time around, we've been given HG two or 3 that is in our class blast K C. L. That is also in actual solution. These are going to performing SG two Cl 2 blasts, KN 03. Again, this is an alcoholic meters or alcohol. E meters hold so this is soluble. But then looking at this, make everyone this is not going to be soluble. So this is going to pay our salt. So if we split these irons down all these compounds to form irons and then to move the spectator irons, what we're going to have is H G two plus plus to blow right irons desire Marcus for our HG two Cl 2 solid.


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