5

The drawing below shows mixture of molecules KcycarbonhydrogennitrogensulfuroxygenchlorineSuppose the following chemical reaction can take place in this mixture: CH...

Question

The drawing below shows mixture of molecules KcycarbonhydrogennitrogensulfuroxygenchlorineSuppose the following chemical reaction can take place in this mixture: CH,(9)+2 0_(g) 3 CO,(9)+2 H,O(g)Of wnich reactant are there the most initia moles? Enter its chemical formula:Of which reactant are there the least initial moles Enter its chemical formula:Which reactant is the limiting reactant? Enter its chemical formula

The drawing below shows mixture of molecules Kcy carbon hydrogen nitrogen sulfur oxygen chlorine Suppose the following chemical reaction can take place in this mixture: CH,(9)+2 0_(g) 3 CO,(9)+2 H,O(g) Of wnich reactant are there the most initia moles? Enter its chemical formula: Of which reactant are there the least initial moles Enter its chemical formula: Which reactant is the limiting reactant? Enter its chemical formula



Answers

Consider the reaction:
$$2 \mathrm{CH}_{3} \mathrm{OH}(8)+3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{CO}_{2}(g)+4 \mathrm{H}_{2} \mathrm{O}(g)$$
Each of the molecular diagrams represents an initial mixture of the reactants. Which reaction mixture produces the greatest amount of products? How many CO $_{2}$ molecules form from
the reaction mixture that produces the greatest amount of products?

Okay. Chapter seven, section problem forty eight. The question is considered the reaction I get to see a three Oh, age methanol plus three. Oxygen goes teo to carbon dioxide plus for water. Each of the molecular diagrams represents an initial mixture of the reactant CE. How many's coatue molecules would form from the reaction? Make sure that produces the greatest amount of products. Um, okay, so is asking us to to find the reaction mixture with the highest yield. Okay, so really, the best way to kind of do this would be teo Kind of make a table and solve it. So the I'm guessing the money, see the picture in the book that I was not able Teo put into my little cartoons here. So I need Thio. Remember which one's which this. Okay, So bluesy HR right a ch for or methane? And that would make in my little cartoons the black would be oxygen. Okay, So, um, saying what would produce more? So if we may like a table and we had, um Here's three oh, age. Um and we planted the amount of oxygen and then we could do and we need to split this in half. One more time to, say the amount of product produced limited by either the methanol or the or the oxygen. And then we'll see. Um, So again, this is so two from methanol. And we can compare that to actually with the CIA too calculated, um, from the hotel. Okay. And we got three. Got tested A b and C. Okay, so in a again, the methane or the methanol? What? Sorry. Okay, well, there's three. And and B there's one, and and see there's four, Right? Okay. And for the oxygen and a there's three. And be there six and and see, there's two. Okay, so the question is what's like the maximum yield that we would get from other or Okay, if we got for methanol. If we started with two, this would be equal. Tio. Um What? They're starting material three times the the coefficient of the product over the coefficient of the start of material. Right. So we need to go to for every three. Ah, methadone. So three times, three times two over three is equal to two. There's the end. All be all and the same will be true from the oxygen would be three moles of oxygen times to over three. So that would be too good to be the same. Impossible. Now. And I have that backwards because the story geometry is different. So let's try that again. Trying to write that one out. Okay. Three moles of two. And for every according to our data, for every three moles of two another two moles of corto I was wrong in a previous one. That's why I was is giving me problems. Yeah. Huh? Okay, I apologize. This is the wrong answer. This must be too right. According to the story, Gamma trees to OK, three times two, divided by two is equal to three. Nice. Okay. And then three times two divided by three. It's chemical too. Okay, Harry, go our work checks Now. Now what about the So for B is, maybe I should write this out. Um, you know, we should really for everyone. Mall of ch three o three o h. We multiply that by the story. Gamma tree considerations. Teo twos for every and two molecules bad and we can see that it's just going to remain the same. There's a pattern here and this is this is going to three over too frame so, too. And this will be a three point three, and that's a big one point three. Okay, so then the next part of the question is, um, which reaction produces the most are the highest yield. So we're going to get the greatest yield here. Um, the greatest yield would come with the one with the lowest number or the highest. Lowest number. Right. So this is going to give us the greatest yields or to bay. Um, how many molecules? Ok, we got to go all the way to molecules. So this is going to give us the highest yield and teacher. Okay, that's all we need to know. Okay, Great. Right. Because on B and N c um, the amount of you too formed is going to be the lowest possible amount on DH. That's kind of the definition bythe limiting re agent, but in a we are able to form tio. Okay, great. So then the next thing that we need to do is convert that, in fact, into molecules and the way to do that is there a little bit more dimensional analysis and just convert tio molecules arino. I guess how many so two molecules would form. I guess it's just the answer. It's just to the answers to two molecules from a anyway real exciting everyone.

In this exercise, we are given three little windows and I've tried to draw these windows for you and were given the reaction you see right here. So we have methanol reacting with oxygen to yield carbon dioxide and water and we are asked to do two things. Were asked to pick which window. Let's call them A, B and C produces the most products, most products. And after we have that figured out, we're also going to use that window to tell how many CO two molecules will form. Okay, so the black particles represent carbons so we can cross out be right away because there's only one carbon here and one carbon and four hydrogen doesn't give me very much. It would let me do a half a particle of hydrogen. Let's look at I just know the answer here. So I'm gonna do it this way in reaction window. See We have four carbons. We have four times 4 16 hydrogen, And we have 2468 oxygen's Looking at our products. And I'm just going to write our products right here. We have to co two Plus four H 20. And we can see that in this I have four plus 48 oxygen's. So I could make to Particles of Co two. Now let's take a look at I don't know if I can move down here or not. I don't think I can now, that's okay. So I'm just going to write this up here that we can produce two C. 02 s in this window And in this window we can produce one co 2 when a race a little bit. And we're going to look at Window A in Windows A. We have three carbons. We have 246789 oxygen's. And we have four times 3 12 hydrogen. So let's see what we can make. Again, we have to co two Plus four H 20. So if I can make three co 2 s that would take up these three and it would take up six of my oxygen's leaving me three H 2 Os. So I could make three of these. That would give me 6789. I'd have plenty of hydrogen is left over. So this window would be the window that allowed me to make the greatest amount of product. And how many co two molecules would this make? It would allow me to make three co 2 molecules.

Hi there and welcome to answering a question we're doing question 47. Consider the reaction for hcl gas plus O two gas is going to go to two H +20 gas plus two cl two gas. Each molecular diagram represents an initial mixture of the reactant. How many molecules of cl two would form from the reaction mixture that produces the greatest amount of products. Okay, so let's think about this. First of all, we want to know that the problem is asking us to consider how many molecules of cl two are produced. So we need to make sure that we remember it's asking for molecules. Love that. Keep that in mind when you're reading a question like this that you're going to give it in the right format. Great, how do I deal with molecules? You might be wondering what just important? Remember that? This means that we need to know um avocados number molecules is what is being asked for. So how do I get to molecules? I need a big address number which is of course the number of molecules that are in a mole. And here it is written for you. 6.22 times 10 to the 23rd molecules. When we figure out how many moles are produced, we'll just do a quick conversion to end our and her answer awesome. Okay, so let's go back to this reaction. So four hcl and one oxygen is enough material for this reaction to go one time and then that will create two H 20 And what we really care about is two cl two. And let's remember, we're trying to figure out which of these reaction mixtures produces the greatest amount of products. So now we need to start considering which of these is going to make the greatest amount of products. Let's color code a little bit so we can think about it. The hcl, I'm underlining green because that's these green molecules hint for you. White ball usually means hydrogen and then I cl chlorine is much larger than hydrogen and then oh two is going to be the red. And there's a sign for you there, even if you're not sure is that because it's two of the same atoms making up an oxygen molecule. These two red balls together representing that. Great. Okay, so let's look at the first one. First one, we have seven of these green molecules. So seven hcl. Nice. And accompanying that one. Oh two. How much? How much does this allow us to run this reaction? How many times? How many turns? How many, how many, how much of this reaction can we do? Well, it looks like we have enough oxygen to do the reaction one time. So I'm putting one time. There is a note for myself. Okay, what about the next one? How many molecules of our reactions do we have? Okay, so it looks like we have six of the H. C. O. 123456 Great. Okay, we have six H. C. O. Hey, that's enough to run the reaction one time. How much option do we have? We have 3123 oxygen molecules. So we have plenty of oxygen. But again, after we do this reaction, one time we're going to run out of enough hcl do the reaction again because you need four. We only have six. So once we do that, once will be out. So again we're going to do the reaction one turn of the reaction. One time 11111111 reaction is going to happen when one, one turn, one time one of these is going to go, okay, I like this so far. 11 Let's see what the next one is going to give us. You might be ahead of me now. 1234 Look at that, we have four H C O. Exactly enough to do the reaction once and five oxygen's if you're counting, lovely. Now what I love about this is the person who wrote this question is not trying to trick you, whichever of these you picked. You would find that the reaction can go one time one turn once we're doing reaction one time. Great. So now that I know that I probably have a good idea about how many moles of Cl two are going to be produced because I know it's only gonna go once. I'm gonna make too moles of Cl two. But now I need to remember what the question is asked me for asking me for molecules and if it's asking me for molecules, I need to do a little math. So two moles of cl two are being produced. Let's convert that to molecules. So two moles of CO two times. And here let me make this, see, look, it's moderately better times, avocados number, he's going to get us our answer. That's gonna be our answer. That's going to be the number of molecules of CO two. Okay, and that should be super helpful for you. So let's just do the math. I think I'll go ahead and just body put a nice little box over here for where we finish our answer. So let's do this two times six point open two times 10 to the 23rd. At this point, if you'd like to get out your calculator way to go you, which is multiplying this number avocados number times two and the answer is one 0.2044 times 10 to the 24th. Now you're not done yet because you need to write molecules right? Always right what it is, molecules ma'lik, cures of cl two. Love it. This is our final answer. Double boxed, Happy Face, smiley Look at that and I'm just going to write it out right over here just in case that's helpful for you. Sometimes it's helpful. Now I'm going to review the question again but at this point I am hoping you feel pretty good about this and that's awesome. Let's review. Okay, good. Now I can type having a little technical problem here. Oh boy. So there it is, there it is written out for you, help and yeah, anyhow. So what do we do? We made sure to remember we were working in molecules, made a note about how to do that to ourselves. Then we considered which of these reaction mixtures would produce the greatest number of products. Some fun analysis and colour coding told us that they will all turn this reaction one time we have enough material to this reaction once, which means we will be creating two moles of cl two. And then we just had to figure out how many molecules two moles is right then. Okay.

All right. Hey, welcome to question 47. It's nice to see the pictures here because they're really important. So, we're considering this reaction for hcl plus one oxygen gas. It's gonna become two H +20 and two Cl two. I want to just reference for those of us that might find this helpful. This is avocados number. This is the number of molecules of a God rose number in a mall. There's my beautiful number sign. Look how pretty that is. Okay, anyhow. So each molecular diagram A B and C represents an initial mixture of the reactant. Okay, so we have initial, How many moles of CL two would form from the reaction mixture that produces the greatest amount of products. It sounds like a great question. So, let's just do a little color coding. I care about CL two and I want to know how many molecules art would form. All right. And let's do a little color coding here. So, if I have four H C. L. So this this one right here, these are the hcls. These these green is chlorine. Little white ball is always hydrogen. So we have 1234 We have seven hcls and we have we have one oxygen molecule and there's two red balls together is an oxygen molecule. So we can go over here, we have three oxygen and we have 123456 Is that right? That I count that? Right? Six hcls. Oh my goodness, Okay. And lastly we have 12345 five. Oxygen's a lot of oxygen. And how much hcl do you have your prior ahead of me for HDL. Great. So then we need to wonder we're going to create the greatest amount of product. So how many times are going to do this reaction? So which of these give the most? So in this first one, this first one we're gonna run out of 02 So once this reaction uses one unit of 02 it'll use up four of its units of hcl and then it will run out. Okay, so this reaction will go 11 will create one mole. In this case we have four hcl so I'll just circle. This is our limiting. In this case we have four hcl. We need for hcl do the reaction one time. So we will use all four Hcl and will only use one of the 02 S. In this case we're going to run out of Hcl. Okay, so that is making me think that oh maybe this is it. So for this reaction after we use for Hc for Hcl and one oxygen will be left with some extra material. So be is clearly our winner here. Let's do a little math here. So for every more of material, we will be able to run this reaction. Say we have this this action, make sure you know, it's a big big old container containing all this gas. Make this reaction run for every mold material. We have we have 123456 We have enough material. We have six HDL 32 We're going to be able to do the reaction fully once. We'll do four Hcl and one oh 21 time. And then we'll be able to do the reaction a little bit more. Because we're gonna have after one run, we'll be left with, I'll do a little color coding. We have four Hcl. It's gonna get used and we're gonna have left over when the left left over of two hcl. Okay. Okay. So this is a reaction being run once in full and then here's our leftovers and we're going to have 102 and we have leftover of 202 Okay, so I hope you're with me here and you're noticing we're going to be able to run the reaction completely one time and then we have enough material. Two hcl is enough is not enough to do the reaction of full time. We can do the reaction and then and in part some as well because remember, it's not that we have to hcl molecules, we actually have a lot of material because this is the mixture. So you can do this as a ratio we have enough material to do this reaction again. So if we do this reaction some more, let's say we do for every four hcl we need one oxygen in this case since we have to we're gonna need half an oxygen. So that means in order for us to totally run out of hcl we're going to use up another half oxygen. So then and in part now how much apart? Half of them all. Whoa. So we're going to run the reaction to the reaction work over here. Now the reaction is run, they're actually gonna be run one and one half times 1.5 times. Okay, what does that mean? The reactions 1.5 times? Well, it means that we have enough material to create two cl two times the amount that this reaction is going to run, times 1.5. Which is going to equal two times 1.5 is gonna equal three moles cl two, wow. We're gonna make three moles of CO two. Well, what's three times avocados number? Yeah. What is three times avocados number? Okay, this is where you get out your calculator and you have a really nice time with your calculator and I'm going to give you some time to do that. Well I actually go ahead and do it to another tab and I really recommend that you're doing math like this. You use a calculator you're allowed to and your answer should be somewhere around. We're probably gonna do a little bit of fast math and go 3 18 point times 10 to the 23rd but that's not correct. Scientific notation. We're gonna need to move this decimal point over and we'll get to 1.8066 times 10 to the 24th. Right on. Okay. Well I hope this was helpful and let's be sure we say 1.8 oh 6 64. We want to be clear. We're talking about molecules of cl two. Yeah. Isn't that so great way to go us. All right, so how do we do this question? Let's just review for fun. Okay, so we remembered that it was asking us for molecules of Cl two. So we thought about our cadres number. Then we went through each of the different molecular diagrams, imagining uh some sort of container that has these gases that are gonna interact. And we thought about, okay, well which of these is gonna be able to make the most stuff. We noticed that in a we had enough oxygen to run the reaction one time and then we'll be left with some hcl and the reaction would stop and we noticed with C we had enough hcl to run the reaction one time. But then it would be left with a bunch of options left over but it would be able to react to anything. So then we came to B and B. We noticed that we had enough Hcl and oxygen for the reaction to go once and then we would have some leftover materials. We had to figure out how those leftover materials would interact. And so two moles of Hcl interacting with, two moles of oxygen would allow us to run this reaction in part, so half of um half of a mole of material would still react. And so we did the math on half a mould material adding into one more material. So fun to add one and one half, we get 1.5 times and then we got to do our math with alligators number. So too well to being produced times, 1.5 times that it's happening. Three moles of CO two, three times out of God. Rose number is 18 oh 66 times in 23rd. Then we made sure to correct our notation and to write out that its molecules of CL two. I hope this was helpful and I hope you're having a nice day.


Similar Solved Questions

5 answers
40f 6Par ADraw the product of the reaction CH;CH; CHCHzC_CCH; 2Br? -? Draw the molecule 0n the canvas by choosing buttons from the Tools (for bondsh, Atoms; and Advanced Template toolbars_ The single bond is active by default Include all hydrogen atoms:View Available Hints)0 H: + 0 0 /04
40f 6 Par A Draw the product of the reaction CH;CH; CHCHzC_CCH; 2Br? -? Draw the molecule 0n the canvas by choosing buttons from the Tools (for bondsh, Atoms; and Advanced Template toolbars_ The single bond is active by default Include all hydrogen atoms: View Available Hints) 0 H: + 0 0 / 04...
5 answers
Suppose that f(€,y) = 9x + 6y and the region D is given by {(T,y) | -1 < r < 5, - 1 < y < 5}-Then the double integral of f(€, y) over D isfJ fk, y)drdy 216 Preview
Suppose that f(€,y) = 9x + 6y and the region D is given by {(T,y) | -1 < r < 5, - 1 < y < 5}- Then the double integral of f(€, y) over D is fJ fk, y)drdy 216 Preview...
5 answers
0(0) = 0.6, 0(0) FI = 0x9 = 0.6, 0r9 = 0192 = 0.4 _P(B = 1)Hidden variableFlavorWrapperBag P(F = cherry B) 1 051 2 02Bag P(W = red B) 1 Ov1 2 012W =redW = greenF= cherry F= lime28181638Bag
0(0) = 0.6, 0(0) FI = 0x9 = 0.6, 0r9 = 0192 = 0.4 _ P(B = 1) Hidden variable Flavor Wrapper Bag P(F = cherry B) 1 051 2 02 Bag P(W = red B) 1 Ov1 2 012 W =red W = green F= cherry F= lime 28 18 16 38 Bag...
5 answers
Ib. Give the correct reagents and conditions for the following reactions There may be more than one step_OH
Ib. Give the correct reagents and conditions for the following reactions There may be more than one step_ OH...
5 answers
Dry air at STP has a density of $1.2929 mathrm{~g} / mathrm{L}$. Calculate the average molecular weight of air from the density.
Dry air at STP has a density of $1.2929 mathrm{~g} / mathrm{L}$. Calculate the average molecular weight of air from the density....
3 answers
Hto Points]DETAILSofIt In ocld veL0 Cf nhili nas COnirg broker sugrerted that ] inYest ha: 510,000 lorct Kncings, murni Aesunuing thar these rates ms Eon chalt0 TAnch were yiolding 548 Der Year; Ccoounded and tho otrer nalf in cortif Letee deposi (Cu= Anan? (Rolmt [ Fnc #earast Cari nettt= Guun /7 Fiaaned hor nun
Hto Points] DETAILS ofIt In ocld veL0 Cf nhili nas COnirg broker sugrerted that ] inYest ha: 510,000 lorct Kncings, murni Aesunuing thar these rates ms Eon chalt0 TAnch were yiolding 548 Der Year; Ccoounded and tho otrer nalf in cortif Letee deposi (Cu= Anan? (Rolmt [ Fnc #earast Cari nettt= Guun /7...
5 answers
2) Given the 4th Differences are equal to -48a) State the degree of the polynomial b) State the sign of the leading coefficient c) Determine the value of the leading coefficient d) Draw an approximate sketch based on the above properties
2) Given the 4th Differences are equal to -48 a) State the degree of the polynomial b) State the sign of the leading coefficient c) Determine the value of the leading coefficient d) Draw an approximate sketch based on the above properties...
5 answers
Question2 Find the missing value of the table given belowAN[6 marks]b) Justify vour reason for using the proposed mathematical method? EV[4 marks]Year1917 4431918 38419191920 1921 397 467Export (in tonsWhat assumption have vou made in finding the missing value?
Question2 Find the missing value of the table given below AN[6 marks] b) Justify vour reason for using the proposed mathematical method? EV[4 marks] Year 1917 443 1918 384 1919 1920 1921 397 467 Export (in tons What assumption have vou made in finding the missing value?...
1 answers
Use the double-angle identities to answer the following questions: If $\sin x=\frac{1}{\sqrt{5}}$ and $\cos x<0,$ find $\sin (2 x)$
Use the double-angle identities to answer the following questions: If $\sin x=\frac{1}{\sqrt{5}}$ and $\cos x<0,$ find $\sin (2 x)$...
5 answers
A standard deck of cards has 52 cards divided into four suits: clubs, diamonds, hearts, and spades. Each suit has 13 cards consisting of an ace, a king, a queen, a jack, and cards numbered from 2 to $10 .$ Assume that one card is selected from a standard deck. For Exercises $37-48$, find the probability of selecting the indicated card.A heart
A standard deck of cards has 52 cards divided into four suits: clubs, diamonds, hearts, and spades. Each suit has 13 cards consisting of an ace, a king, a queen, a jack, and cards numbered from 2 to $10 .$ Assume that one card is selected from a standard deck. For Exercises $37-48$, find the probabi...
1 answers
Determine whether the function is a linear transformation. $$\begin{aligned}&T: M_{2,2} \rightarrow R, T(A)=a+b+c+d, \text { where }\\&A=\left[\begin{array}{ll}a & b \\c & d\end{array}\right]\end{aligned}$$
Determine whether the function is a linear transformation. $$\begin{aligned}&T: M_{2,2} \rightarrow R, T(A)=a+b+c+d, \text { where }\\&A=\left[\begin{array}{ll}a & b \\c & d\end{array}\right]\end{aligned}$$...
1 answers
Approximate $f(x)$ to four decimal places. $$ f(x)=-2.1 e^{-0.71 x}, \quad x=1.9 $$
Approximate $f(x)$ to four decimal places. $$ f(x)=-2.1 e^{-0.71 x}, \quad x=1.9 $$...
1 answers
For each function, find the specified function value, if it exists. If it does not exist, state this. $$ g(x)=\sqrt{x^{2}-25} ; g(-6), g(3), g(6), g(13) $$
For each function, find the specified function value, if it exists. If it does not exist, state this. $$ g(x)=\sqrt{x^{2}-25} ; g(-6), g(3), g(6), g(13) $$...
5 answers
Find vector equation for the line through the given points_ (Use for the parameter) (1, 2, 1), (5, 3, -2)(x, Y, 2)
Find vector equation for the line through the given points_ (Use for the parameter) (1, 2, 1), (5, 3, -2) (x, Y, 2)...
5 answers
1 1 H 6 5 49 " "28 8%& 1 | 8 7 8 474 [ 4347 [ 1 8y: 633 { #> 2 82 ~2 1 1 3 F
1 1 H 6 5 49 " "28 8%& 1 | 8 7 8 474 [ 4347 [ 1 8y: 633 { #> 2 82 ~2 1 1 3 F...

-- 0.020264--