Okay. Chapter seven, section problem forty eight. The question is considered the reaction I get to see a three Oh, age methanol plus three. Oxygen goes teo to carbon dioxide plus for water. Each of the molecular diagrams represents an initial mixture of the reactant CE. How many's coatue molecules would form from the reaction? Make sure that produces the greatest amount of products. Um, okay, so is asking us to to find the reaction mixture with the highest yield. Okay, so really, the best way to kind of do this would be teo Kind of make a table and solve it. So the I'm guessing the money, see the picture in the book that I was not able Teo put into my little cartoons here. So I need Thio. Remember which one's which this. Okay, So bluesy HR right a ch for or methane? And that would make in my little cartoons the black would be oxygen. Okay, So, um, saying what would produce more? So if we may like a table and we had, um Here's three oh, age. Um and we planted the amount of oxygen and then we could do and we need to split this in half. One more time to, say the amount of product produced limited by either the methanol or the or the oxygen. And then we'll see. Um, So again, this is so two from methanol. And we can compare that to actually with the CIA too calculated, um, from the hotel. Okay. And we got three. Got tested A b and C. Okay, so in a again, the methane or the methanol? What? Sorry. Okay, well, there's three. And and B there's one, and and see there's four, Right? Okay. And for the oxygen and a there's three. And be there six and and see, there's two. Okay, so the question is what's like the maximum yield that we would get from other or Okay, if we got for methanol. If we started with two, this would be equal. Tio. Um What? They're starting material three times the the coefficient of the product over the coefficient of the start of material. Right. So we need to go to for every three. Ah, methadone. So three times, three times two over three is equal to two. There's the end. All be all and the same will be true from the oxygen would be three moles of oxygen times to over three. So that would be too good to be the same. Impossible. Now. And I have that backwards because the story geometry is different. So let's try that again. Trying to write that one out. Okay. Three moles of two. And for every according to our data, for every three moles of two another two moles of corto I was wrong in a previous one. That's why I was is giving me problems. Yeah. Huh? Okay, I apologize. This is the wrong answer. This must be too right. According to the story, Gamma trees to OK, three times two, divided by two is equal to three. Nice. Okay. And then three times two divided by three. It's chemical too. Okay, Harry, go our work checks Now. Now what about the So for B is, maybe I should write this out. Um, you know, we should really for everyone. Mall of ch three o three o h. We multiply that by the story. Gamma tree considerations. Teo twos for every and two molecules bad and we can see that it's just going to remain the same. There's a pattern here and this is this is going to three over too frame so, too. And this will be a three point three, and that's a big one point three. Okay, so then the next part of the question is, um, which reaction produces the most are the highest yield. So we're going to get the greatest yield here. Um, the greatest yield would come with the one with the lowest number or the highest. Lowest number. Right. So this is going to give us the greatest yields or to bay. Um, how many molecules? Ok, we got to go all the way to molecules. So this is going to give us the highest yield and teacher. Okay, that's all we need to know. Okay, Great. Right. Because on B and N c um, the amount of you too formed is going to be the lowest possible amount on DH. That's kind of the definition bythe limiting re agent, but in a we are able to form tio. Okay, great. So then the next thing that we need to do is convert that, in fact, into molecules and the way to do that is there a little bit more dimensional analysis and just convert tio molecules arino. I guess how many so two molecules would form. I guess it's just the answer. It's just to the answers to two molecules from a anyway real exciting everyone.