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Indicate whether the pair of structures shown represent stercoisomcrs; constitutional isomers; diffcrent conformations of the same compound_ or tne same conformatio...

Question

Indicate whether the pair of structures shown represent stercoisomcrs; constitutional isomers; diffcrent conformations of the same compound_ or tne same conformation of compound viewed from different perspective. Note that cis_ trans isomers are an example of stereoisomers _CHaH3C-H3CHyC OHOHCH3 HaCH3CCH3

Indicate whether the pair of structures shown represent stercoisomcrs; constitutional isomers; diffcrent conformations of the same compound_ or tne same conformation of compound viewed from different perspective. Note that cis_ trans isomers are an example of stereoisomers _ CHa H3C- H3C HyC OH OH CH3 HaC H3C CH3



Answers

Indicate whether the complexes in each pair are identical or isomers. If they are not identical, tell which kind of isomers they represent.

The question is asking whether these molecules are, um I suppose if they're up or if they are just the same molecules drawn in different ways. So a we have see each three group. Bryant was each to curb in double bond oxygen th three and this molecule below has Stage three s, A, C H and oxygen carbon each Aussie street very similar. The only difference is this position here is flipped. Therefore, they're considered a simmers and B. We see the same benzene green, the same bonds to eye. But this one is around 12 and this one has found 13 there for their position Ice Merced A different position. Now if we look at C C 1234 tarp carbon ring too carbons off of carbon two and three. And in the 2nd 1 we see the exact same thing. The only difference is the position in which this one is drawn. Going back instead of coming forward, their fourth, the same molecule form on the same structure. It is not a summer

Problem. We're determining whether the two molecules drawn are I summers or the same molecule drawn in a different way. And so, for a we have these two molecules and so this is going to be the same molecule as you can see. This carbon and this carbon are the same one with F or groups here, in here and on this top one Ethel groups here and here and then a method group here for each of the two. So these are the same molecule. Let her be. We have these two molecules and we can automatically right away tell that these are ice summers. Because if we just look at the number of carbons on each side of the oxygen this top one has to hear. And four here and the bottom one has three here and three here. And so we know automatically that these two are customers. Let her see. Looks like this. Yeah, and so these are the same molecule. And the way that we know that is, if we take this bottom one, move this carbon group here and flip this carbon group to the top. It will look exactly the same as this top one, and we haven't made or broken any bonds. Therefore, these two are the same molecule

This question has us whether these two compounds are the same compact on the eyes. So you wanted to do that? The easiest way would be named the compound. So this one is metal a prop annoy where this one is either last day. And so they are indeed eyes rumors. This one is also die Odo benzene. Whether this oneness measure Diadora benzene So their eyes Merce. So these compound, if we label it a name, it's will be 23 DiNozzo pretend similarly this comparison So 23 metal Buddha himself. This is the same. Calm down.

So now we will work on problem ninety four from chapter twenty one here were asked to determine whether each pair of structures are ice mers or the same molecules drawn to different weights. So let's go ahead and look at part A and draw the structures that were given its nucleus. They're drawn in the book. The same structure were given a CH three ch too. C h ch three with two carbons on tower. So the question is, are these the same work different So we can see here that we have our longest carbon chain as being five carbons long with a metal group at Position three. If we draw our largest carbon chain right here, we also get a carbon chain of five carbons with a method group at position three. So these molecules are the same. If we look at part B, we see two more pairs on her one more pair of molecules. So we haven't either. And then the second structure that were given is shown low here. C h three see it too. Ch too. Oh, ch So from these two marshals, we can see differences right away. We can see that The first one has two carbons on the right whereas this one has three carbons on both sides and this one has four. So this one is perfectly symmetrical. This one is not so. We can say that these are different molecules now moving on to part. See, we're given two more molecules. First is a key tone and then we also have another key tone has shown here. So from this molecule here, we can see Yeah, let's go and draw methyl group here we can see that the difference here is this Ma Ah methyl group is pointing down. This is pointing up, but it's in the same position. So everything left of the carbon eel is exactly the same, just shown in a different orientation. On the right side, it's the same thing. We haven't Ethel Group, which is just shown in a different orientation. So they are exactly the same. It's just the sum of groups are shown in a different orientation


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