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Last year, nine employees of an electronics company retired. Their ages at retirement are listed below Find the mean retirement age_5856.1 yr 56.7 yr 58.0 yr 57.5yr...

Question

Last year, nine employees of an electronics company retired. Their ages at retirement are listed below Find the mean retirement age_5856.1 yr 56.7 yr 58.0 yr 57.5yr

Last year, nine employees of an electronics company retired. Their ages at retirement are listed below Find the mean retirement age_ 58 56.1 yr 56.7 yr 58.0 yr 57.5yr



Answers

A certain company offers a 5-year average retirement formula for their employees. The accountant uses a spreadsheet to keep track of employee benefits. The salaries from the last five years of employment are listed in cells B4, B5, B6, B7, B8, and B9. The percentage multiplier is listed in cell B10. The number of years of employment is listed in cell B11. Write the spreadsheet formula that will calculate the annual pension benefit for the employee.

Is given. Problem discusses The number of citizens aged 45- 64. So it's gonna be approximated by pFT Equals 1 97.9, Divided by one plus three point 274 E The negative 0.0 UG 631 or 3361 team. We have the model here. We want to know um What the expected population of citizens aged 45 to 64 years in 2010 is um so it's going to be when 1990 Is the tea go zero, so 2010 would be um p. of 20. and what we end up getting from that is 76. That would be the um number and millions.

So one thing that's excellent about mathematical models is the fact that it allows us to predict what will be the case in the future. So we have our population measured in millions. Um, and it is, Well, graph it's ffx just because graphing calculators prefer to use f of X. So we're going to do f of X, which is our pft. That's going to equal 1 97.9 over one plus 300 or 3.274 Okay, mhm e to the negative 0.361 t. Yeah. In this case, we'll call it acts. Now we have our graph, and we want to look at T from 0 to 25. So will narrow this down from 0 to 25. And what we're asked ultimately is, um, zero is the year 1990. And we want to know, um, the expected populations of citizens in this group in 2010. So that's going to be when t is 20 because that's 20 years after 1990. So if we look at t equals 20 we see that that's 76.396 So we expect for there to be about 76.4 million people

Ago. This was the bonus, and this was soon deviation. But 10 years from now, things have quint coupled or time to die 55 times more. So when you multiply any your Senate deviation and you're mean, you actually will change both. So the new, um bonus rate would be 10,000 so 2000 times five is $10,000 bonus, and then the nuclear deviation 3 25 times five would be equal to $1605.

So they asked to find the random variable. So X is the time in years after reaching aged 60 so is the time in years after reaching 60 b is ex continuous or discreet. Time is always continue. See, we want the distribution while we're told the mean was five. So the exponential distribution then would be one over five or point to the once the mean we're told to mean the beam was five. He wants the standard deviation, the standard deviation and the mean are always the same in these all so far f draw the graph. No point to 0.0.1 our 10 15. This will be the years past 60 that someone retired and then our graph looks something like that. G. Find the probability that the person retired after 70. So after 70 e to the negative 0.2, the mistake is people put 70 here. But remember, it is the time after 60. So this should be 10. And so that would give me 0.1353 age doom or people retire before 65 or after 65. So we just need to figure out one of these and we can answer this question. So I'm gonna figure out how many people are the percentage of people that retire after 65. So I know e to the negative point. Two times five. Remember, after 60 is the number for him that gives me a probability of 0.3679 So the probability someone retires at the age of 65 or more is 0.3679 says 65 plus so less than 65 years old would be just one minus that which is 0.6321 So more people retire before the age 65 then retire after the age of 65 and I in a room of 1000 people over 80. How many do you expect will not have retired yet, So we have to figure out the probability that they're still working at eight. So that would be e to the negative 0.2 times 20 once again, years past 60. And that is this 0.183 So that's the probability one person is still working at 80 years old. If we kinds that by 1000 that tells us 18.32 people will probably still be working at age 80


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