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Question

TABLE 2230 ? ? %€0439328986 20 < € € { = & & & & E & E 5 # ? 0;8 8 2 : 2 3 : 3 ? & s82 0 : € ] ] / ] > U#0 00 0 *Tlie Genetic Code 3 3 : ? : : : : :>3] Triplets in Messender 2 { : * * :3 ? ? # #]]2 e/g g ? ? : 8 % € ! $ 3 8 8 2 3 ? 9 4 < 0 $ < < < < 3 } ? ?

TABLE 223 0 ? ? %€0439328986 20 < € € { = & & & & E & E 5 # ? 0;8 8 2 : 2 3 : 3 ? & s82 0 : € ] ] / ] > U#0 00 0 * Tlie Genetic Code 3 3 : ? : : : : :>3] Triplets in Messender 2 { : * * :3 ? ? # #]]2 e/g g ? ? : 8 % € ! $ 3 8 8 2 3 ? 9 4 < 0 $ < < < < 3 } ? ?



Answers

Based on Table $17-1,$ how would you categorize the following genomes? (Letters H through J stand for four different chromosomes. HH II J KK HH II JJ KKK HHHH IIII JJJJ KKKK

Here we have a pedigree and we have an X. Chromosome links and excellent disorder was by little tree. So there's going to be thanks gee ex cheats and a possible Y. Chrome zone. Yeah. Can we using an extra e. Okay so let's look at the answers. It. Hey looking at these First Generation # two Service is an effective female. So an affected female has to be um Hamas august recessive with its recessive condition. So she will have X. G. X. She Because she's affected v. 2nd generation number two this is an unaffected female. So she's going to have two X chromosomes from her father. She's going to get this from her mother. She is going to get one of her affected ones. So she will be a carrier. See So this is generation to # five. This is an affected male. So he has one X. Chromosome and it is the responsible and then here's a white crimson D. So okay D. Is generation three. Number two. So this is an affected male. So again effective male has to be this regardless. So he must have picked up the recessive X chromosome from his carrier mother. I'm finally eat Generation three. # six is an unaffected female. So she has two x chromosomes. One is from the effective milk, one is from the unaffected mother. So most likely she is going to, well she's a carrier so we know that she has to have this regardless of her mother's. We're gonna come over as a carrier. We know she got the recessive one from her affected father which is going to be this one because she doesn't have herself, she must have got this one from her mother.

Okay, so this question gives us a table comprised of values of X and values of the functions F of X and G fx. And what we want to do is create a new table of values of F of G of X and G of F of X. Two. New functions are made up of fx and G fx compositions of those two functions is what we would formally say. Our function is just a rule that takes values of X as inputs and then outputs different values In the case, when X is equal to -3, note that G fx Outputs The Value three. Now this first new function F of G of X. What this means is is that we first apply G fx to our value of X and then our output we put into F of X as our input um and return the value from ffx. So in the case when X is equal to -3, we get three and then plug in three back into F effects. We can see from the table that when X is equal to three F of X returns zero. Hence we know That when X is equal to -3, this new function f of G of X returns zero. So we've got the first entry in our table there and now we can fill in the rest of our table or at least this first bit F of G of X by simply looking at the value of X going down to G of X and then using that as our input again to get to f of G fx. Okay, so when X is equal to minus two G of X is to f of two is one Ff too by the way is just the same way as saying what the input X is to what do we output F of two gives us one -1 goes to 2, 2 goals to one zero goes to 000. When X equals zero fx gives us three uh annexes one, Uh get -2 -2 goals to one. When X is equal to 2G of X is equal to -2. And then using -2 of the input of FX, we get one stand, see a little bit of a pan. When X is equal to three G of x gives us -3 And then f of -3, return zero. Okay, so we've completely the first row of our new table and now we have to look at the next function G of F of X, which is exactly the same idea. Except now we reverse the order and perform F of X first. Okay, so when X is equal to minus three F of X produces zero G of zero gives us zero. When x is equal to minus two F of x produces one, Then using one as our input of G of X, we get -2 -1 goes to to to goes to -2, zero goes 2-3, three goes to -3. Want goes to to two, Goes to -2. two, goes to -2 -2 goes to I'm sorry I've done it in the wrong order that I performed G of X and then F of X so X is too F of X, produces warned And G of one gives us -2. When X is equal to three, G of X is equal to, sorry, F of X equals zero, And then GF zero return 0. There we have it. We've completed the table.

Okay, so we have three three genes that we're giving recombination frequencies for, and we are asked to determine the order of the genes. So what do we know about recombination Frequencies? Theory. Recombination frequency is going to tell us. Excuse me is going to tell us the distances between these genes. So we know just by looking here, the 35 is going to be the highest recombination frequency, which means R and L two are going to be further apart. Alright, so let's map these out. I like to map it out. So we're gonna have our here and l two here, and this is going to be 35 apart, okay? And we know that our and W to our 17 apart, And if you subtract 35 minus 17 is going to give you 18. So and we know W two and l to r 18 apart. So that means that are in W two must be at this location. Right? So this is going to be 17 and this is going to be 18. It's not quite drawn to scale, but that's kind of just how you how you solve these problems and 18 plus or 18 plus 17 is going to be 35. And this is the order. It was gonna be our w to l two or it could be l two w two are important thing is that W two is in the mid.

We are looking at an auto so more recessive sort of and we need to label the correction insult to compete in G. Depending on we'll camp. So looking at this pedigree first we're looking at the affected female so she's affected. So we already know she has to have the excessive disorders points definitely The Generation Student # one. So this is the affected woman's son and he is unaffected but he must have picked up one of her process of valuables. So he will be a carrier. See This is a generation to # two. So here we have an unaffected female, her parents are also unaffected. But if we look down the next generation we see that she has some affected Children. So if two unaffected individuals have affected Children they must both be carriers for this condition. So she too is a carrier. Mendy is a The affected female in Generation three. Again she's affected so she will have both recessive one from each of her carrier parents.


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