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What is the IUPAC name of the following substance?Submit Answer...

Question

What is the IUPAC name of the following substance?Submit Answer

What is the IUPAC name of the following substance? Submit Answer



Answers

What is the IUPAC name of each of the following compounds?

Yes, sir. Problem nine. We are on our you pack naming. Okay, so we have this molecular model in here, and we're supposed to name it. So the first up is still find the longest Jane we could find. Okay, so just by looking at it, all right, I think this should be the longest jane in this in the structure, right? And then we'll have those. We'll have those two branch points right here, okay? And so we're gonna have to count our carbons. And we are gonna come from where the closest branch point is. So say, um, so versus left or right. It looks like the branch point the first branch point is closer to the left. So we are gonna count, starting from the left kick. So let me raise everything we have so far and count from the left. So we have one two, three for 56 Okay, so we're only counting the carbons an hour main chain. Okay, Since we have six carbons, that's gonna have the the prefix hex right hooks. And since they're old single bonds, that's gonna be a vaccine. Okay. And then on carbon, too. We have the ch regroup. So we have two metal, right? That's a method group. And then we have another method group on carbon three. Right, So that's three metal. Okay, so now that we have all the information we need, you could go ahead and combine all of these information. Okay, so we're going to start with the numbers. We have two. Three. And since we have two metal groups, that's gonna give us a dime, Ethel. Okay, Dime Ethel. So 23 dime. Ethel Hexi. Okay, so that s the name for this molecule.

Let's solve the problem from the chapter. Organic chemistry. This problem is based on the U. P C naming of the organic compounds. Here we are given structure of an organic molecules for which we have to write the OPC name. So let's start numbering the carbon atoms. The numbering will be started from the left hand side as it contains the side groups. So this is the carbon number one, two, three, 456 and seven. There are seven carbon atoms in the parent chain, and at carbon number two, there are two methyl groups and there is a triple bond at carbon number three, so the compound can be named as to two diameter trial. Three have nine.

Let's work on the problem from the chapter. Organic chemistry This problem is based on the U P C names of organic compounds. Here we are given the structure of foreign compound, for which we have to write the U. P. C. Name. So let's start counting the number of carbon attempts in the parent chain. The numbering will be started from the side where triple bond is present between carbon atoms. So this is carbon number one, then two. This is 345 and six. In this molecule, there are six carbon atoms and the parents scene with a triple bond between carbon number one and two. And the lethal group is present at carbon number three. So now you piece the name of this compound will be three eat tile, one exit sign.

Let's work on the problem from organic chemistry. This problem discusses the ups the naming of the organic compounds. Some of the structures of organic components are given. We have to provide there are UPS he needs. If we start with the first compound first, we will provide numbering to the carbon. Attempts to find out the parent train, followed by writing the names in this compound. There are three carbon atoms. This is carbon number 12 and three at carbon number one hydroxy group is present. So the compound is named as one, dropping all and moving on to the next compound. Given we can start counting numbering from any side. This is carbon number 12 34 and five. This compound having 55 carbon atoms with our dogs Children at carbon number three is named as three pending on then we have the next compound we're there are seven carbon atoms presenting the parent chain and some of the positions are substituted. Carbon Number three substitute by Hi doctrine groups and carbon number 456 are substituted by metal group each So we can name this compound as four five six try me tile three have been all. Yeah. Then we have the last compound where the ring is present, numbering is done from the carbon. We're always group is present, considering with what group is known as final. So this compound can be named as metal derivative of final, and the compound is named as three me tile final.


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