Hi in the human problem, the four parallel current carrying conductors are arranged such that the form are square means they are kept at the vortices of this is Squire, which is having aside a and these conductors, this is the conductor number four, which is carrying a current coming out of the plane of paper. This is conductor one which is also carrying the current coming out of the plane of paper. This is conductor number two, which is carrying a current getting into the plane of paper and finally, conductor number three. That is also carrying the current started into the plane of paper. Here, this is xx is and this is Y axis. So side of the square has given us or 18.5 centimetre, which can also be written as 0.135 need to. And the current carried by each conductor is same and that is having a magnitude of 7.50 And here. Now in this problem, we have to find net force experienced by this conductor for per unit of its land in unit. That notation. First of all this conductor for scanning the current in the same direction as in conductor number one. So it will be attracted by the conductor. One means the force acting on fall due to one is attractive in nature. So this is you will need it f at four due to one, but at the same time this four will be repealed by conductor three as the currents are in opposite direction and the force will be having same magnitude but a different direction. And it will be named as effort four due to three. No, if we mark its diagonal, also diagonal of the square between it's worth. This is two and four. To really be given ass the expression for diagonally Sayroo too, means here it will become 0.135 into rule two m. And as again the conductor for and conductor to are carrying currency in opposite direction. So the four conductor number four will be repelled by this conductor to also. So the force will be things like this. And this is named as Yeah at 4 to 2. And here this angle will be 45 degrees. So this effort to maybe resolved into two components. Yeah, this will be a 42 cause 45 degree. And here this will be a long negative by excess. This will be F. Or two. Sign 45 degrees. No to find total force experienced by this conductor. For first of all, we will find their different forces F 41 F 43 and F four to. So first of all we find F. For one. It is found using the expression new note upon four pi into two. I wanted to hear. Ivan means I fought current carried by conductor for Ivan. Current carried by conductor, one divided by our Mr gap between them. And that forces were unit length means newton for nita. So plugging in all known values here, this is standard for minus seven into two into my phone. And all the currents are same. So eye for an eye one will also be same. So this is 7.50 multiplied by 7.50 divided by our There are means eight. The gap between them and that is 0.135 m. And it will come out to be equal to 8.3 into 10 par minus five newton perimeter. Similarly, the force F at four due to three, that will also be having same magnitude. And it will be given as F 43 8.3 into 10 days for minus five newtons per meter as well. Now, F or two using the same expression you're not upon four by means standards for minus seven into Ivan into I two. Both 7.50 ampere invited by the gap between them which is diagonal. This time the inside room two mu 0.135 into route to. And this value comes out to be 5.9 into tendons, par minus five newtons per meter. So finally, net force along X axis will be given by if you look here along X axis along negative X axis, there are the two forces. So the net force will be F at four due to three plus the component of mm at four due to the horizontal component means F four to close 45 degree. So, plugging in all the known values here for F 43 This is 8.3 into 10 for minus five for effort. This is 5.9 into and each one minus five in two room two into one point of the value. Of course 45 degree. So finally it will come out to be the net force along X axis. And this is a long negative X axis. So in unit vector notation it will be minus 12.5 into tended to the power minus five. I kept newton four m. Similarly, F. Y. And that is equal to if you look at the figure again for Fy, this will be F 41 minus F four to sign 45 degrees. So here it will be F at four due to one minus vertical component of after it for you to it will be effort to sign or 85 degree. So, plugging in unknown values here also. This is 8.3 in 2, 10 inch par minus five and that was newton meter. Yes, of course, this is a 13 to 10. H one minus five newtons per meter minus 5.9 in 2 10 for minus five into sign 45 degree, which is one by two. So will come out to be 4.1 into and it's the power minus five newtons per meter. Or invent reform. It will be as it is a long positive Y axis, so it will be represented as 4.1 in 2, 10 for minus five Jacob. Newton per meter. So finally net force may be written has minus 125 multiplied by one more zero hair. Then it will become 10 days par minus six I kept plus here also, this is what even into standish par minus six Jacob and overall measured in newtons per meter. So finally we can write it like minus 125 I kept last 41 Jacob, and that is micro newton for meter 4, 10 1 minus six. This is the answer for this given problem here. Thank you.