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10 pointsSuve AnswerTwo identical charges (Q1 = 92 ) repel each other with a force magnitude of F = 10 N, when they are 2 cm apart How big are the charges? [ &0...

Question

10 pointsSuve AnswerTwo identical charges (Q1 = 92 ) repel each other with a force magnitude of F = 10 N, when they are 2 cm apart How big are the charges? [ &0 = 8.85 x 10-12 c2I(Nm2) ]6.7 mC045 . 10-12 €06.7. 10-13 €0.67 uCType here t0 search

10 points Suve Answer Two identical charges (Q1 = 92 ) repel each other with a force magnitude of F = 10 N, when they are 2 cm apart How big are the charges? [ &0 = 8.85 x 10-12 c2I(Nm2) ] 6.7 mC 045 . 10-12 € 06.7. 10-13 € 0.67 uC Type here t0 search



Answers

The repulsive force between two identical negative charges is $0.750 \mathrm{N}$ when they are $0.100 \mathrm{m}$ apart. Find the amount of each charge.

So we are given the data that Q one plus Que Tu is equal to 20 my local room. So let's write and write that down for part A. We are given that force is 0.75 mutants. Let's substitute it in terms off electrostatic force off attraction or repulsion, which is when divided by four pipes that are not here. Times Q. One Q two Divided by our square, which is equal to 0.75 Now distance are is three. So three square is nine, which is here, and this is one by four pipes that are not so In this way. You find the product Cuban que tu as 75 times 10 power negative 12. Let's simplify that. If you simplify that you get, he want you to product at 75 Micro cool. I'm square by simply for that. I mean, just write 10 power negative 12 as micro Coolum Square so that our calculations will be easier since we are given that Cuban place cute who is 20 micro column here. We can use this equation to write cute, too, in terms of Cuban, as we have done here, 20 minus Cuban and substitute this in this equation appear. So if you do that, it's 20 to 1 square 20 Q one minus Q. One square. Is it well to 75? This is a quadratic equation. Q E. Okay, so let's write it down in a standard form human square minus 21 plus 75 now on a side. Note. If you have If you are given a quadratic equation as X squared plus B effortless, see the Solution X is equal to negative B plus minus square root B squared, minus full, A C divided by twice a day. So let's use that here. So Q one is equal to positive 20 because of this negative sign here. And this negative sign here makes it positive plus minus square old 400 minus 400 of the square of 20. So here, which is be square square on dhe for a sea. Since value off A is one here it is four times 75. Now, if you solve it four times 400 minus. This is 300 makes it 100 square root off under the strain, so 20 plus 10 is 30 or 20 minus 10 is 10. So you get Cuban is either 15 micro Coolum or find my curriculum as shown here and see that both values are complimentary. How do we say that is because if Cuban is 15 micro Coolum Que tu is fine, My curriculum and if you want is fine. Michael Coolum Que Tu is 15 micro Coolum so that their addition is 20 now in the part B were given their forces 1525 Newton, but with additional condition that the charge attract each other. That means the falls off its force off attraction, which must be negative. So that will give us the product. If you want you to as negative 5 25 Cuban square on a similar lines now to solve it, we will do the same things that would date for the party, eh? So we will get same quadratic equation, except for the factor off negative 5 25 here, which was positive 75 before Now it's negative. 25. Even the factor of 20 won't change because edition of Q and Q two is still 20. So if you saw this quadratic equation here, you get the solution here, which is 20 plus square root of 2500 which is either 70 by two or 30 by two. In this case, this will be negative. Implies Q one is either 35 micro Coolum. Oh, or negative 15 micro cooler as before, both by loser complimentary. That is, if Kyu won is 35 Micro Colon, you too. We'll have to be negative. 15 micro puller. And if Cuban is negative 15 miles of blue ink you two will have to be 35 Marco Polo. Thank you for listening.

Hi the to charge particles given in the problem are Cuban is equal to eight into 10 dish par -6 column, And Q two is equal to six into 10 dish par -6 colon. The force experienced by these two charged particles is given as 2.7 into 10, par -2 newton. So using Ghoulam's lock for electrostatic force acting between two charged particles which has given us F. Is equal to one x 4 by absolute note into Cuban, into Q two by our square. So plugging in all non values here for force, this is 2.7 into 10 hr minus two. Newton is equal to nine in 2, 10 days 100.9. Newton meters square per column square. Multiplied by the charge is the product of the charges, which is eight into 10 days, par -6. Coolum Into six into tended bar -6 colon, divided by the distance between them, which is missing here. So canceling the similar units. This is newton by newton and column into column, which will come out to be equal um square by this column. Square. Hence finally, the expression for this unknown distance. The square of distance will come out to be nine Into eight, into 6 into 10 dish par minus street, divided by 2.7 into 10 dish par -2, which will come out to be 160 into 10 dish par minus one. Or we can say this is 16. So finally, the distance between them will be given by square root of 16 m. Or we can say this is 4.0 m, which is the answer for the given problem. Hands here, we can see our option B is correct here. Thank you.

So in this problem, we have two charges. Uh, que wise. Ah, Eight times turned to the neck of six qualms. Thank you to is, uh, six times into the *** six columns. And according to the columns law, we see that the force between them is ethic. Whoa, Well over four pi absolutes, Kinds Q one Q two deal by r squared right, and this equal the 2.7 times 10 to the next *** to Newton's according to the problem. So if you plug in the video of the Q one Q tuned into this expression and you go so far to our Pentagon tin that are equal full meters, all right?

We have two identical charged particles. It means both have equal charge Cuban equals to kill two equals two Q. And they are separated by a distance, small equals to one point double zero m. And both are repelling with repelling each other with force F equals to one point double zero neutral. Okay, so now we have to determine the charge on each spear. That is cute. So from the cool. Um So we know that the force F equals two KQ square by the square. So from here we get after rearranging Q equals two F. D. Square. They were by K. And hold under the sun of substituting values. We get Q equals two under root of F, which is one point double zero newton and D. Which is one point a double zero m. So holy square divided by K. Which is 9 to 10 to the power nine newton meter square park cooling the square. Okay, so from here after solving we get charged Q. On the boat particles equals to 10.54 micro color. Okay, so this is the answer for that question, and this is the charge on each particle, which will experience a force of one newton after placing at a separation one m. Okay?


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