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Discussion 1 Tries Fino [ne Minimum and maximnun 1 1 8 11 ALnonuAnNAX38...

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Discussion 1 Tries Fino [ne Minimum and maximnun 1 1 8 11 ALnonuAnNAX38

discussion 1 Tries Fino [ne Minimum and maximnun 1 1 8 1 1 ALnonuAnNAX 3 8



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Exercises $1-8:$ Let $a \neq 0$ $$ \text { Solve }|x| \leq 3 $$

This problem we were told that a is a matrix given by -3012. The matrix B I'm sorry, that was negative one over here and three was positive 30 negative 12 And then B is three negative four 11 first. We want to find the matrix A plus B. Right, okay. Now, in order to add two matrices together we just add the corresponding component. That means we're gonna take top left plus top. Let three Plus 3, Jesus six. Mhm Zero plus 92. 4 is negative four. They have one post, 10 and two plus one is three. And so that's our matrix A plus B. Now for the matrix A minus B we should just subtract correspondent components. 3 -3 is zero, zero minus negative four is four -1 -1 is negative two into minus one is one. So that is the matrix A minus B. We also want the matrix to A to A. Just means take every component of A. And multiply it all by two. So when we do that three times to six, zero times 20, You have one times two is negative two And two times two gives us four. And so that's our matrix to a. And then for negative three B, we just take every component of being multiplied by negative three. and so three times a day of three is named nine and four times 93 is 12, And then on the bottom of 93 And then you have three.

The problem we're told the matrix A. Is equal The 3 -22 zero on negative four. And negative three to negative form. And the Matrix B is a matrix 40 two negative one negative 13 Now first we want to find A plus B. Now in order to add two matrices they must have the exact same dimensions. Well a is a three x 3 makers But B is a three x 2. And so that means that this is not possible because they don't have the same dimensions. Yeah. We also want to find A minus B. Yeah this is something else that we can't do because these don't have the same dimensions. And so this is still not possible. Yeah. Now we can find to A to A. Just means take everything in A. And multiply it by two. So that top probably six. And then get a 44 Than 0 to -8. The -6 4 -2. Yeah. And then lastly we want negative three B. And so it just means to take everything and be And multiply it by -3. That's 1912 0. Then you have 63 3 -9. So that's our matrix -3 B.

The given question we have to solve the absolute value inequality And the absolute value inequalities. Model of experts than three. Okay, so to solve this absolute value inequality, I have a formula and the formula says that if you have any linear expression X plus B and it's more or less is better than K. Okay then the solution must say that he or he expressed me either less than minus K or X plus B is better than Okay. Okay. Both the conditions may happen here. So by this formula, I can say that if I am removing here models and then the solution, I must say that Your ex should be either less than -1 Or X should be either 33. It means that This solution consists of minus and finite to -3 small records And this solution consists of 3 to infinity. No. Finally my answer is that minus and final two minus three. Union 32 In finance. Okay. This is the final answer of the given question. We're delay. This is the final answer of the given question here. Okay, thank

And this problem we are given that Matrix A. is the three x 2. Matrix six I get 1- zero. Now you have 34. Mhm. And Matrix B is the Matrix Uh huh. 31 And yet 1560. And we want to find first A plus B. Now to add to major cities, you just add the corresponding components together. So top left close, Top left Is what goes on. The top left search plus three is 9. Top ride was top ride, It was in the top right now give one postponement 0. And then we proceed in this matter. Two plus negative one is one, zero Plus 5 is five. They have three plus six is three Than 4.0. As for And so that is our Matrix A plus B. Now for the Matrix A minus B. Take our correspondent components again and subtract the light terms 6 -3 is three -1 -1 is -2. Two minus negative one is three, 0 -5 is -5. Then you have 3 -6 is -9. 4 0 is four. Now for two a. We take everything and a and multiply it by two. six times 2 is 12 in one times two is that you have to We have 40 -6 and eight. And then lastly we want the matrix negative three C. I'm sorry, 93 B. Three B. That means take everything and be and multiply it by negative three 789 Now you have three. Three may have 15 negative 18 zero.


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