5

Review Homework: Homework 5 Normal Distribution Close Score: 0.25 of 3 of 9 HW Score: 13.89% , 25 of 9 pts5.3.32Question HelpSuppose x is normally distributed rando...

Question

Review Homework: Homework 5 Normal Distribution Close Score: 0.25 of 3 of 9 HW Score: 13.89% , 25 of 9 pts5.3.32Question HelpSuppose x is normally distributed random variable with = 33 and 0 = 4. Find value Xo of the random variable X P(x 2Xo) =.5 b. P(x < Xo) =.025 P(x > Xo) =.10 d. P(x > Xo) =.95 Click here t0 view table of areas under the standardized normal curvea. Xo 33 (Round to the nearest hundredth as needed )For This Project: Create Game With At Lcast Ou:_ Cnegg comb. Xo(Round

Review Homework: Homework 5 Normal Distribution Close Score: 0.25 of 3 of 9 HW Score: 13.89% , 25 of 9 pts 5.3.32 Question Help Suppose x is normally distributed random variable with = 33 and 0 = 4. Find value Xo of the random variable X P(x 2Xo) =.5 b. P(x < Xo) =.025 P(x > Xo) =.10 d. P(x > Xo) =.95 Click here t0 view table of areas under the standardized normal curve a. Xo 33 (Round to the nearest hundredth as needed ) For This Project: Create Game With At Lcast Ou:_ Cnegg com b. Xo (Round to the nearest hundredth as needed:)



Answers

In Exercises $11-14$ , the probability density function of a random variable is defined.
(a) Find the expected value to the nearest hundredth.
(b) Find the variance to the nearest hundredth.
(c) Find the standard deviation. Round to the nearest hundredth.
(d) Find the probability that the random variable has a value
greater than the mean.
(e) Find the probability that the value of the random variable
is within 1 standard deviation of the mean. Use the value of
the standard deviation to the accuracy of your calculator.

$$f(x)=\frac{4 x^{3}}{609} ;[2,5]$$

Number 13. We have our rubber leading to the city function, nickel effects and given internalise to go fine. Your bar days was we need to find expected value for me, will you? I mean, really Just doing my integration all next time to wear for next e x. Don't interrupt. I want to be a ninja. Really stupid fire. And therefore taxis want excuse Your big day takes, you know name You are forgetting basics. 09 this constant. So to get outside of integrity and Xing to excuse next this to four. No, indeed. Additional picks is two forties Nexus will fly you right back. Fly now! I think you'd probably make minus Lord limit. So here, use acquittal upon six year old nine. Finest. Oh, my dear. Verify 6 25 minus. Do this to my eyes. Started to divided by five. So or mu alles 4.6 That is expected of you. No, The second thing is you need to find radiance. No. Radiance is my musical traditional. Next year, the full facts Marina's new spear limited that to be in this question limit is 25 and left offices for X cubed. You're headed right? Six year old nine. And there were meal. These 4.6 Where we're in here for my 69 is constant and experience to excuse His next was to fight miners. What? 26 square? No, indeed. This one off. Mixed misto flies excess with six divided right six No executive Pollux it, Linus. Lower than you. So Proclivities fight. Limit is two Now what it is to fight 15,625. You got it. Seeks and to list the sixties. We simply by these forget our millions is I see your point. Don't fire. No standard solution is given by squared off radiance. So you various c'est it'll bring the butterfly. So standard Deviation e's CEO won't 74. Okay, No, the party is on the probability that the random variable has a value better than the mean so here. I mean, really Release for six. Andi given intern authorities. Cool. What? So your limits should be 106 Cool. Right. So now find the probability Wondering toe for 0.6 to 5. Careful. Fix D x no, therefore exceeds. Well, excuse You ready for a 60 year old name Ni Exe I've been here for four years. Basic see loneliness must int in traditional excuse bees Next list to four divided by four No execute upper limit Marino's Lord Bye. Well simplified disaggregated improbabilities serial point 58 No lost bodies find a probably that the value off the random variables within one stand in division I mean so your new minus sigma palestina or two ext left me plus sigma, your news for Syrian six Sigma Cyril wants 74. So being here Meurice for from 06 plus the points 74. Well, 106 minus here over 74. He's three. I want you to let Donna go to extra lesson. Only do 1.8. You be easy. We're doing traditional youthful mix dukes So you're a Z would keep on 32 be easy going for part eight year 3.22 for more great in their four taxis. What excuse you have date Night takes your length DX We're going here for my six year old minus one stone so they get outside of the integral indignation off ex cuties. Next, Mr. Before you ready? But more now I see you topple. Limit minus lower limit. So he probably limit is 4.8 minus lower. Limited to 1 32 was simplified. These things we get a couple of beauties syrup 60 70 three. Thank you.

All right. So you have this probably distribution country you can buy at the Becks is X to the negative, one third over six from your eight. And we want to do a few things that first we want to find the average, which will calm you. I'm just going to be the integral from zero to eight of X times distribution function, a children's. This's going to be X to the two thirds over six. All right, And so what we get, we get policy. So we add So that's going to be five thirds of three fifths. Divided by six is going to be wanted. And then we have eight to the five shirts, which is going to p thirty two thirty to ten. Sixteen over thighs. Twitch is three months already. The next we want to find them. Variants to the variance is the same integral. Under seizing B for variance. That's extreme people times distribution function minus the average queen. You square. So this is here to hate. This is going to be X to the five thirds six minus near which wass I'LL see sixteen over five squared. All right, so this is going to be now seven errands. Those are painters, X t eight thirds diarrhea from zero to eight. And then we have a one six. We're going tow. Multiply by their cyclical three eights. So that's going to give us one over sixteen. Front minus sixteen. Five squared. All right, now. Okay. So we need to evaluate, huh? Eight to the third since too naive, which is to pity. Six. So this is two fifty six over sixteen. That's sixteen minus sixteen squared. That's it. Oberg twenty five, sixteen squares to fifty six on, then This is about actually, it's exactly equal to you. Yeah, five point seven six. Right now, the standard deviation. It's just the square root of the variance Sigma square root of the variance, which in this case is just two point four and for being says, find the probability that the variable given by this distribution function it was bigger than you. So this is going to be the integral from new all the way up to eight of X to the minus one third over six necks. Remember that mu is three point two. And if you compute the center girl, you get about zero point four by seven one Um, this is di Sorry D and then for E We want the probability that excess within one standard deviation so mu minus sigma Hand me a plus England. So just take away an ad one standard deviation from the average. This is going to be the integral from you, my Sigma Tim, you plus sigma uh, next to the minus one third over six d x. And when you compute the center girl, take just anti derivative here Evaluated these two numbers you get approximately zero point five seven to nine.

This question asked you to take 100 samples of size five from the uniform distribution of the digits. Now you can see I'm not on the white board. Instead, I'm using a computer to do this like the problems as I can. Andi, I have chosen to use the programming language are, which is a statistical program language. So I start by initializing a list, and then I will take 100 samples. I'll go. I'll just reiterate through 100 times. Every time it does this, it's going to do this sample function. The sample function takes the first argument, which is a vector of all the digits zero through nine, and it will sample five times. Also, it will take five elements of that population at a uniform probability. Like the problem says. And I've had this argument replace equals true s so that I can have duplicates so it will take samples of five and put them into this list. Um, the problem then asks you to find the mean of each sample. That's what this line does. Sample means is the list of all the means of every single sample. So there will be 100 sample means stored in this factor. Um, let me go ahead and run some of these. I'll start the list. I will create all of the samples. And so now you can see that I have over in the top right corner. I have a list of 100 samples of length five. Um Well, then find the mean of each one sample means on you can see again in the top, right where it says Samp means I have a list of 100 sample means and then finally asked you to create a hist. A gram of all these sample means. So this will be an estimation at the, uh, sample distribution for sample means. Oh, go ahead and run that. And you can see we get a hist. A gram of the sample means now the question once you describe this history, So what can we see about this? Well, we can see right away that it's unit motile. There's only one peak we also see it is pretty symmetrical. It's ah, looks pretty even around both sides. Um, it seems to be centered around five. That's where most of the data points are. So you know motile symmetrical with a center around five, and it also has arranged from a little bit less than two. So about about 1 to 8 has arranged from 1 to 8, and that's Ah, that's the hissed a gram of our sampling distribution.

Neary of this probability distribution function. F of X is three over sixteen times for Minds X squared on zero to and park A We just want to find the average. So don't know that I have you That's going to be the integral from here to two of x times its average our times this distribution function which in this case okay, begin factor out through sixteens Hey! And we just have girls here, too to for X minus execute Jax Mensch is very sixteen. Here we have X squared two linus for X squared over to sit to X squared minus X cubed. So that becomes Extend the fourth over four and evaluate from zero to two. This is three sixteenths times eight minus sixteen or force of four. So this ends up being Towler sixteen, which is three. Four or point seven five. Okay, for the variance, which all just know by being do something similar says here, too, to this time we put in X squared times the distribution function and then subtract the average squared. So three four squared okay, so can take out of three sixteenths. We have the integral of from here to two for X squared minus sixty fourth. The Ex minus three fourths square Ness's three sixteenths. It's gonna be for thirds X cubed minus X to the fifth over five. Evaluated from here to two minus. This is nine hundred sixteen. So people into it get eights. That's twenty for three me for E minus thirty two five minus nine over sixteen. And when we simplify that out, we get nineteen. Hoover eighty. Rich is about point two four. All right, so next we just want the standard deviation, which is the square root of the variance. And so what do we get about? I see your point for nine kit and then party. We want the probability that, uh, this variable given by this distribution function is bigger than me. So this is just the integral from the mean up to to the right important of three sixteenths times or minus X squared, the ex and women compute that player is again. We get about zero point for six, three, nine and then for Parky, we want the probability yes, that we're within one standard deviation. So, um, you plus sigma, you mind a sigma around? It's just the integral from you might of Sigma to you plus Sigma and I just have these bodies stored. Mom's compute the interval quick of three sixteenths for minus X squared. Jax, what do we get when we compute that out? We get zero point six one three.


Similar Solved Questions

5 answers
3.0) Ifyouadd 7.0 drops of6.0 M NaOH to 25.0 mL ofthe buffer sohtion You prepared would t resulting pPH be the same? higher? or bwer than the pH obtaned question 2?Explain your responseb) How will the conposition of your bufler change as result of adding the 7.0 drops 0f6.0 M NaOH to 25.0 mL of the buffer solution?
3.0) Ifyouadd 7.0 drops of6.0 M NaOH to 25.0 mL ofthe buffer sohtion You prepared would t resulting pPH be the same? higher? or bwer than the pH obtaned question 2? Explain your response b) How will the conposition of your bufler change as result of adding the 7.0 drops 0f6.0 M NaOH to 25.0 mL of th...
5 answers
1. Eva uate tne integral, or show that it is divergert: U = Rotx) du = X dx 4u =dx h I26 onl Ycu can- Jts4c 4 0 Tere$ 21 Xc 4 U= Rate) [email protected] 'plele Lye 42 Xa ( M = S &) Asympteles a€ L~Jlz wkl Knk 6 # S "s 5 UE3 [1-0]3
1. Eva uate tne integral, or show that it is divergert: U = Rotx) du = X dx 4u =dx h I26 onl Ycu can- Jts4c 4 0 Tere$ 21 Xc 4 U= Rate) [email protected] 'plele Lye 42 Xa ( M = S &) Asympteles a€ L~Jlz wkl Knk 6 # S "s 5 UE 3 [1-0] 3...
5 answers
Unis Is& MoiecuieDiavino22 Question (4 points) Draw the enantiomer of the following molecule.OHOHHOHollinIst attempt
Unis Is& MoiecuieDiavino 22 Question (4 points) Draw the enantiomer of the following molecule. OH OH HO Hollin Ist attempt...
5 answers
X=Cost Find the slope of the line tangent to at ( = y = 8sin t 23Find the length of y = 20<t<1
X=Cost Find the slope of the line tangent to at ( = y = 8sin t 2 3 Find the length of y = 2 0<t<1...
5 answers
The joint density function for a pair of random variables X and Y is given: Round your answers to four decimal places_ f(x,Y) = {cx(1 + y) if 0 < x < 5,0 < y < 4 Uo otherwise Find the value of the constant C. XFind P(X < 1, Y < 1) .Find P(X + Y < 1).
The joint density function for a pair of random variables X and Y is given: Round your answers to four decimal places_ f(x,Y) = {cx(1 + y) if 0 < x < 5,0 < y < 4 Uo otherwise Find the value of the constant C. X Find P(X < 1, Y < 1) . Find P(X + Y < 1)....
5 answers
Question 32 (1 point) college admissions officer takes simple random sample of 96 entering and computes their mean mathematics SAT score to be 42.?, Asunterhe pophlation population standard deviation is 123. What is the lower bound of the 99% confidence interval? Round your answer to the nearest integer: Write only number as your answer: Your Answer:Answer
Question 32 (1 point) college admissions officer takes simple random sample of 96 entering and computes their mean mathematics SAT score to be 42.?, Asunterhe pophlation population standard deviation is 123. What is the lower bound of the 99% confidence interval? Round your answer to the nearest int...
5 answers
Find the derivative implicitly with respect tox8x2 10zy + 3y2 = 268t -Jy 5.-3y31-4 = 5-3y8r - 2y 51+3y8r-3y = 3y-51
Find the derivative implicitly with respect tox 8x2 10zy + 3y2 = 26 8t -Jy 5.-3y 31-4 = 5-3y 8r - 2y 51+3y 8r-3y = 3y-51...
5 answers
Let G,H, K be groups and 0 : G = Hand $ : H= Kbe isomorphisms_ Prove 0 : G 77 K is an isomorphism.
Let G,H, K be groups and 0 : G = Hand $ : H= Kbe isomorphisms_ Prove 0 : G 77 K is an isomorphism....
5 answers
Consider the intial value problem: 49y" + 70y + 25y = 0, y(0) = a > 0, y (0) = -3.Find the solution in terms of a_Give your answer as y =.Use € as the independent variable:Answer:b. Find the critical value of a that separate solutions that become negative from those that are always positive.critical value of a
Consider the intial value problem: 49y" + 70y + 25y = 0, y(0) = a > 0, y (0) = -3. Find the solution in terms of a_ Give your answer as y =. Use € as the independent variable: Answer: b. Find the critical value of a that separate solutions that become negative from those that are alway...
1 answers
The switch in Figure $\mathrm{P} 21.60$ closes when $\Delta V_{c}>2 \Delta V / 3$ and opens when $\Delta V_{c}<\Delta V / 3 .$ The voltmeter reads a voltage as plotted in Figure $\mathrm{P} 21.60 \mathrm{b}$. What is the period $T$ of the waveform in terms of $R_{\mathrm{A}}, R_{\mathrm{B}},$ and $C ?$
The switch in Figure $\mathrm{P} 21.60$ closes when $\Delta V_{c}>2 \Delta V / 3$ and opens when $\Delta V_{c}<\Delta V / 3 .$ The voltmeter reads a voltage as plotted in Figure $\mathrm{P} 21.60 \mathrm{b}$. What is the period $T$ of the waveform in terms of $R_{\mathrm{A}}, R_{\mathrm{B}},$ ...
5 answers
Cunsider the function f (x,") 3r-+ 9y 24r _ I00. Determine the extreme values of the function the domain given below and the points at which the extreme values occur: The parabola has equation 1 and the slant line in the first quarter is given by 8r + y = 64. Approximate values with twso decimals, if YOu need64
Cunsider the function f (x,") 3r-+ 9y 24r _ I00. Determine the extreme values of the function the domain given below and the points at which the extreme values occur: The parabola has equation 1 and the slant line in the first quarter is given by 8r + y = 64. Approximate values with twso decima...
3 answers
[12 pts] Use MME with the following data1,1,0,0,0,2,1,2,2,1,0, 1to estimate the parameters 01 and 0z for the distribution of X whose moment generating function is given byMx(t) = (1 _ 01 ~ 02) + Bet + Oze2t.
[12 pts] Use MME with the following data 1,1,0,0,0,2,1,2,2,1,0, 1 to estimate the parameters 01 and 0z for the distribution of X whose moment generating function is given by Mx(t) = (1 _ 01 ~ 02) + Bet + Oze2t....
5 answers
Given =f(x)=x^ 2 +x, find the equation of the secantline passing through, (−5 f (−5)) and (1,f (1)). Write your answer in the form=y+mxb.
Given =f(x)=x^ 2 +x, find the equation of the secant line passing through, (−5 f (−5)) and (1,f ( 1)). Write your answer in the form =y+mxb ....
5 answers
Specify zer or nonzero molecular dipole moment for both of the following = compoundsCBr,(HC) CHCH,OH
Specify zer or nonzero molecular dipole moment for both of the following = compounds CBr, (HC) CHCH,OH...
5 answers
A shampoo company wants to test if the average amount of shampoo per bottle is 16g. The standard deviation is 0.20 grams. Assuming that the hypothesis test will be performed using a 0.10 significance level and a random sample of 64 bottles, what is the correct formulation of the null and alternative hypotheses?
A shampoo company wants to test if the average amount of shampoo per bottle is 16g. The standard deviation is 0.20 grams. Assuming that the hypothesis test will be performed using a 0.10 significance level and a random sample of 64 bottles, what is the correct formulation of the null and alternative...
5 answers
QuestionWhict exampte 0l @ nssense mulatlou? codan , chanod but Ifo amirio ack sunuerca ictwaints 5Ma Ancleol do chanood, but M i5 cmnetled by mr4 € Fnvima ^ sinqte point substitutiox) = channs Lcuo Pro Nw ^ trnma sh Il onds trarseul On Qailv dux EhhAM S cOdanQUESTIONWluch typas RNA nio dvarIly wwvavod Ir |rwt Wterstuon Datrt ol [Xotu s Hritlvisis? (aaleci Ihot Npln) IRNA MRNA IRNApANAClick Str md #utur t0Cic STHaeaenUnll
question Whict exampte 0l @ nssense mulatlou? codan , chanod but Ifo amirio ack sunuerca ictwaints 5Ma Ancleol do chanood, but M i5 cmnetled by mr4 € Fnvima ^ sinqte point substitutiox) = channs Lcuo Pro Nw ^ trnma sh Il onds trarseul On Qailv dux EhhAM S cOdan QUESTION Wluch typas RNA nio dva...
5 answers
In the following decomposition, the first fraction has an A in the numerator because the denominator is a linear factor The second and the third fraction have B and C respectively in the numerator because the denominator can be factorized into linear factors.28B (8+2)(8+1)(82+4)(8+1)(8-2)Is the statement true or false?Select one- TrueFalse
In the following decomposition, the first fraction has an A in the numerator because the denominator is a linear factor The second and the third fraction have B and C respectively in the numerator because the denominator can be factorized into linear factors. 28 B (8+2) (8+1)(82+4) (8+1) (8-2) Is th...

-- 0.022641--