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Question 2 of 10pitching machine programmed pitch baseballs horizontally at speed of 134 kmhh The machine ad aimed forward mounted on a truck As the truck drives lo...

Question

Question 2 of 10pitching machine programmed pitch baseballs horizontally at speed of 134 kmhh The machine ad aimed forward mounted on a truck As the truck drives loward you speed of 85 knvh; the machine shoots . ball toward you .For each of the object pairings listed, determine the correc= relalive speed:The speed of the pitching machine relative the truckThe speed of the pitched ball relative the tnuckThe speed of the pitching machine relative t0 youThe speed of the pitched ball relative t0 you

Question 2 of 10 pitching machine programmed pitch baseballs horizontally at speed of 134 kmhh The machine ad aimed forward mounted on a truck As the truck drives loward you speed of 85 knvh; the machine shoots . ball toward you . For each of the object pairings listed, determine the correc= relalive speed: The speed of the pitching machine relative the truck The speed of the pitched ball relative the tnuck The speed of the pitching machine relative t0 you The speed of the pitched ball relative t0 you Iwc bact nm Zoaknuit aikn 49kun



Answers

One kind of baseball pitching machine works by rotating a light and stiff rigid rod about a horizontal axis until the ball is moving toward the target. Suppose a 144 g baseball is held 85 $\mathrm{cm}$ from the axis of rotation and released at the major league pitching speed of 85 mph. a. What is the ball's centripetal acceleration just before it is released? b. What is the magnitude of the net force that is acting on the ball just before it is released?

In this question, the diameter is given D is equal toe 35 centimeters and the rotational frequencies asked the in revolutions per minute. Then they speared is given how much? 90 mil per hour. But I so so we can convert it into meter per second. So on converted into meeting per meter per second, we will get 40 point 23 meter per second and diameter. Also, we can convert it into meter. It will become 0.35 m so we can find the value off radius. It is deep by two which comes out to the zero point 352 It is zero point 175 who needed So we know Omega is equal to be by our now. Let us substitute the value 40.23 upon zero point 175 So on dividing it on solving it we are getting the value is 2 29 0.9 the Indian for a second now we need to convert it into revolutions per minute. So in order to convert it into revolutions per minute, we need to convert it. We need to divide it by Dubai, so it will become revolution. And second, we can write one by 60 minutes. So the 60 will go up and then we can light it to 29.9 into 60 over 25 So let us calculated the value of omega comes out to be 2196 point for you revolution. But I mean it. So this is the final answer. Thank you.

So in this problem we are looking at a baseball pitching machine that works by rotating a light and stiff rod about a horizontal axis until the ball moves towards the target and we want to know what the ball centripetal acceleration is just before it's released and be what the magnitude of the net force that's acting on the ball just before it's released. So we know that the speed of the ball is given us 85 MPH. But we want to put that in meters. So just during the conversions that will give us 38 meters per second, we're gonna not the radius. The ball's distance away from the access is 85 centimeters, but we want that in meters. So let's just 0.85 meters. We were given the mass of the ball in grams, which is one of 44 g. The 1000 kg. It's just 0.144 kg. Okay, so for part A, we know that the formula for centripetal acceleration it must be screwed over our We can just plug in our values that we were given we get. The acceleration is 1699 m per second squared mhm for Part B. We want to know the Net force. We're just going to use Newton's second law. Just force is equal to m A. And we can again just use the values that we have and the acceleration that we solved for in part a, which gives us the net force. It was 244.66 Newton's for 245 Newtons, Yeah.

Well late will be the speed of trust in positive X direction. So licked we be the speed of truck big dough, speed of drug right and this is in the positive x direction. So this is the quality X direction since ah, speed of bullies 40 meters per second. Ah, speed off bull equals 40 meter per second and this is in the truck's frame towards X direction. A speed of ball in ground frame is equal to we minus 40. So speed off ball in grounds frame speed. Most ball in, uh, ground frame ground frame is equal to re minus 40 and speed off bowl is 40 meters per second in, uh, trucks frame. So this is in trucks. Frame right crocs frame Well, we might is 40 is given, which is equal to 10 meters per second. We minus 40 is equal to 10 and solving. For we, we is equal to templates. 40 which is equal to 50 need to per second. Therefore, speed of truck is 50 meters per second, so speed of truck we equals 50 meter per second, so it's equal to 50 meters per second

Hello, friends. Here it is. Given adopters. Speedometer operating at frequency 1.2 and toe 10 to the power five. That means Doppler speedometer is the source on it omitting the sound off frequency. This the text the same way after their reflected from waste ball thrown by the picture. So frequency off Sander reflected sound received by the detector Toby 130 into 10 to the power five. We have to fight the spirit of top baseball. Speed off sound through the air is 3 40 m per seconds. Okay for consider received by the doctoral meter, which is the reflected Toby substitute The value this is given the speed of sound is 3. 40 on a spirit of all upon 3. 40 the on solving it the spirit of ball. We will get 44 m per second. That's all for it. Thanks for watching it


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