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1462The table belon show Tumbo Caneio their numt Ars Galeepenencmontncven emnpleye Corcord MotorHpenenceSncswould Ilke t0 use simple mgression analysis t0 estimate ...

Question

1462The table belon show Tumbo Caneio their numt Ars Galeepenencmontncven emnpleye Corcord MotorHpenenceSncswould Ilke t0 use simple mgression analysis t0 estimate monthly car sales using the Mamagemen ot sales experience: The total sum of square s for this sample numnIr Or Eam C)70.83 D153.71 B) 63.33 A) 53.50

1462 The table belon show Tumbo Caneio their numt Ars Galeepenenc montn cven emnpleye Corcord Motor Hpenence Sncs would Ilke t0 use simple mgression analysis t0 estimate monthly car sales using the Mamagemen ot sales experience: The total sum of square s for this sample numnIr Or Eam C)70.83 D153.71 B) 63.33 A) 53.50



Answers

An auto dealer offers discounts averaging $$\$ 2450$$ with a standard deviation of $$\$ 575 .$$ If 50 autos are sold during one month, what is the expected value and standard deviation for the total discounts given? (A) $E($ Total $)=\$ 17,324 \quad \mathrm{SD}($ Total $)=\$ 170$ (B) $E($ Total $)=\$ 17,324 \quad \mathrm{SD}($ Total $)=\$ 4066$ (C) $E($ Total $)=\$ 122,500 \quad \mathrm{SD}($ Total $)=\$ 170$ (E) $E($ Total $)=\$ 122,500 \quad \mathrm{SD}($ Total $)=\$ 28,750$

Really given problem, we have the retail market. Um The model for the data is going to be F of X Equals a zero 0 to 06 X squared plus zero point 548 X Plus 16.9. Um and ax equals zero is going to correspond to 1980. So in this case, um we have that 2015 is going to be FF 35, And then f of 2020 is going to be f of 40, and we see that at 40, that's gonna be 5.86 as the resulting market share.

This is problem. # 10, We are given the following instagram for the number of cars sold per week and their frequency. So our first step For part a is to find the most frequent number of cars. This will be our tallest bar in the graph, which we can see is here at 12 And the number of corresponds to is four For part B. We will get how many weeks two cars were sold. So we have our number of cars hold here at two and looking at his frequency, we can see that it meets the bar at nine. So it happened nine times for part C. You look at the percentage of time that two cars were sold. Given that the yeah, Total number of weeks in a year is 52. We can. Mhm. Yes. Given that we have 52 weeks in a year, We will take our number of times. So we have nine Out of 52, converting this into a percentage, we get 17.31%. Finally, we describe the shape of the distribution. As we can see. We have very low data points to the right of our data, and the high data points move over towards the left. So we have a part D right skew.

Okay, so we have three models sub compact, compact and standard. And this here is our numbers sold. So, actually, should this should be an M or an s. And in here we have the Prophet Purcell, and we want to know the monthly profit. So we're gonna multiply 38 by 528 sit ups. 20064 We're gonna do that for every rose to 33 times 6.7. That's a 21351 And in 19 times 912 which is a 173 to 8. And now we want to find a monthly total profit. So that's the song of all of these terms. So it some that any yards 58743

Brotman. Number 10 question. Aim. Most frequent number is for it, which should be on the answer is nine, which in C 9/52 times 100%. Because the number of weeks in the year is 52 and the number off the week toe course were sold. Our our nine. So 9/52 times 100 5% question be by classical probability, we can we have next distribution off. The note is equal to 4/52. B one is equal to 1/52 Be over two is equal to 9/52 so be three is equal to AIDS. Over 52 before is equal toe well over 52 be five is equal toe aid over 52. B six is equal to 5/52. B seven is equal to to over 52. B eight is equal toe 1/52 and being I is equal to 0/52 and beaten is equal to 1/15. Yeah,


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