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COLLECTION QE GASES QVER WATERPROBLEMSA sample of hydrogen (Hz) gas is collected over water at 35"C and 725 mm: The volume of the ga5 collected is 72.0 ml, How...

Question

COLLECTION QE GASES QVER WATERPROBLEMSA sample of hydrogen (Hz) gas is collected over water at 35"C and 725 mm: The volume of the ga5 collected is 72.0 ml, How many moles of Hz gas has been collected? How many grams of Hz gas has been collected?

COLLECTION QE GASES QVER WATERPROBLEMS A sample of hydrogen (Hz) gas is collected over water at 35"C and 725 mm: The volume of the ga5 collected is 72.0 ml, How many moles of Hz gas has been collected? How many grams of Hz gas has been collected?



Answers

The hydrogen gas formed in a chemical reaction is collected over water at $30.0^{\circ} \mathrm{C}$ at a total pressure of 732 $\mathrm{mm} \mathrm{Hg.}$ . What is the partial pressure of the hydrogen gas collected in this way? If the total volume of gas collected is $722 \mathrm{mL},$ what mass of hydrogen gas is collected?

So in this question with what we have, um, I'm teaching gas that is collected over water. That decree says you're so to you one. It's your question, Teddy Degrees Celsius and the total pressure p torture his seven creature millimeter. Make Yuri on DA. We're told to calculates the partial pressure off hydrogen gas. So what we need to do is to know that people too east, uh, passion pressure off by reading us. Well, it's pressure pressure off water, since it is collected over water. So we need to know what a passion of pressure hold water. He's at 70 attentive degree socials. So Peter tie 72 Very metal. Make Yuri. Then be haste, you loss. Partial pressure of water had 30 degrees Celsius. Is, uh, see, is that too warm on page? Make your here for, uh, uh, the pasha of Brescia. Off hydrogen will be a cost. 2732 Mine instead to one point aids milling with make Yuri, That is, uh, 700 arms. Two minute me, Tom, make Yuri. That is the fascia pressure off hydrogen gas. Then the less question wants us to, uh it says that if the total volume of gas collected. Yes. Ah, 7 to 2. Maybe later. What is the mass off hydrogen gas there is collected. So for this, we need to use the I d. Gas equation. P B is the cost of an oxy. So, uh, we can find hand to be PB over hard. See, and therefore end will be a cost to pray. Or he's 700.2. An image on mercury, which would be, uh, watching that most fair. So we divide that by 7 16 seven under one, too, about myself. Testing LV zero when I 213 times the volume is several to two millimeters, which will be general 20.7 to 2 liters. Divided by the gas constant, which is 0.0 Hate to 06 litter Most fair oh, care being multiplied by temperature, which is step two degrees. So she is. And if you come back to that cabin with the trees, there are 3.15 Calvin. So this is a really fine 9 to 13 times. Find 7 to 2. You got it by several Quentin zero. They choose you under six. You got it. But it's a little early 0.15 So a number of hole he's 0.27 Don't 0.27 home and then to determine the mass of five agenda will be produced. We know number of home. He's must divided by Mormons, and we know the number off Mall of Hydrogen to present a 0.27 is your question and miles divided by Mollema. Smaller muscle fire. Edginess approximately two. So that's much apply and buy two we give us and this is to grass from all so that will give us Master be crossed. You 0.0 by 35 Gramps. So that's the answer.

In problem. Three. How many moles off hydrogen gas contained in a volume off to later add to 80 Calvin and 1.58 p. M. Pressure. So this question is taken from the topic Ideal Guest Commission. So we have given volume temperature and pressure values. So we find out the number off mold, and we know that our is gas constant, which its value is 0.821 liter, 80 m per Calvin Permal. So using all this information Ah, we can, uh, put in this formula that is previous sickle to NRT. That is peace. The pressure with the volume and is the number of small artist gas constant and T is the temperature so 1.5 into which is a call to end in 20.8 to 1 in 2 to 80. So on solving we get this is when you come out, Toby around 0.13 moles. So that means the hydrogen gas. The mall soft hydrogen gas is one point 0.13 moles. So the malls off higher Trojan guess so, um, also off hydrogen gas, which is equal to 0.13 morning. So this equation is also called it it as ideal gas equation. So this is the ideal gas equation that is PV sickle toe nrt.

In this problem. Healing helium is being collected over water at 25 degrees Celsius and won a t m total pressure. I'm trying to find what the total volume of the gas collected will be in order to get 0.586 grams of helium. We're also told that the vapor pressure of water is at 25 degrees Celsius. 23.8 tour. Um, first, I want to convert by 23.8. Tour to a T. M. So, um, one a t. M. Is 760 tour, so we get that. The vapor pressure is 0.31 a. T. M. Um, next, I need to figure out how many mole of helium it is that I'm trying to collect. So 0.586 grams of helium. One more helium is gonna be 4.3 grams, which gives a 0.1 for six mole of helium being corrupt. Collected using my PV equals energy equation, we can substitute into solver volume. So rearranging the equation for volume volume equals moles. Times are ratio. Our times are constant times the temperature divided by our pressure um Now we have to take into account that there is vapor pressure here. So we know that we have 0.146 moles. We have our constant and we have our temperature of 298 Calvin. Now for our pressure, the total pressure is one. However, some of that is the vapor pressures. We have to subtract the 0.31 from that, and we get that the we need a volume of 3.68 leaders in order to collect 0.586 grams of helium.

And this question, you're asked to determine how many leaders of hydrogen gas are collected over water At 18.18°C uh 7 25 millimeters of mercury, 1.84 g of lithium reacts. So we need to balance chemical reaction lithium reacts with water producing lithium hydroxide and hydrogen gas. As described in the problem, we have one lithium one lithium, one oxygen, one oxygen to hydrogen, 123 hydrogen. So if we put a one half right here, it would be balanced. But to get that, let's see to get rid of that one half, we need to multiply everything through by two. So this would be a more appropriate balanced chemical reaction. Starting with 0.8 g lithium, we can go to moles lithium by divided by the molar mass lithium and then from moles lithium two moles hydrogen gas. Once we know moles hydrogen gas, we can use the ideal gas law in order to calculate the leaders of hydrogen gas. They tell us that the leaders of hydrogen gas are being collected over water, but it's asking just for the leaders of hydrogen gas. So I will assume that the pressure associated with water vapor is negligible in comparison to the total pressure that is provided. Or I will assume that the pressure provided is just the pressure of hydrogen. Because the question does not stipulate this, I will make this assumption. Then when using the ideal gas law, I can use the anti calculated up here with the R value the temperature and the pressure, assuming this is just the pressure of hydrogen gas in order to get the volume of just hydrogen gas. However, when using this equation, the pressure needs to be in units of atmospheres. So we'll convert the millimeters of mercury into atmospheres by dividing by 7 60 And we get a volume of hydrogen being 152 leaders.


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