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Use physics 2 wl algebra knowledgeWave Mean Trial| Frequency Wavelength velocity wave velocity 0.2 Hz 5.0 cm 1.0 cmls 0.62 cm/s 2 0.4 Hz 0.5 cm 0.2 cmls 0.6 Hz 1.0 ...

Question

Use physics 2 wl algebra knowledgeWave Mean Trial| Frequency Wavelength velocity wave velocity 0.2 Hz 5.0 cm 1.0 cmls 0.62 cm/s 2 0.4 Hz 0.5 cm 0.2 cmls 0.6 Hz 1.0 cm 0.6 cm/s 0.8 Hz 1.0 cm 0.8 cmls 1.0 Hz 05 cm 0.5 cms Suppose the mass of the string in the simulation is 400g, estimate the tension force for both settings from the data you have collected above,

Use physics 2 wl algebra knowledge Wave Mean Trial| Frequency Wavelength velocity wave velocity 0.2 Hz 5.0 cm 1.0 cmls 0.62 cm/s 2 0.4 Hz 0.5 cm 0.2 cmls 0.6 Hz 1.0 cm 0.6 cm/s 0.8 Hz 1.0 cm 0.8 cmls 1.0 Hz 05 cm 0.5 cms Suppose the mass of the string in the simulation is 400g, estimate the tension force for both settings from the data you have collected above,



Answers

A transverse wave described by $$ y=(0 \cdot 02 \mathrm{~m}) \sin \left[\left(1 \cdot 0 \mathrm{~m}^{-1}\right) x+\left(30 \mathrm{~s}^{-1}\right) t\right] $$ propagates on a stretched string having a linear mass density of $1 \cdot 2 \times 10^{-4} \mathrm{~kg} \mathrm{~m}^{-1}$. Find the tension in the string.

Okay is given by to buy over Lambda. It was two pi over four meter with 1.57 major in yours. Omega can be indirectly, which is to buy over four meter times. V W, which is to 23.6. Made up for a second on that comes out to be 351.2 seconds indoors. From here, we can find that velocity or the speed comes out to be omega over. K equals 3 51.2 divided by 1.57 it was to 23.6, meeting for a second.

Everybody. So I drew a little image for everybody here and for a um it's asking us determined attention in this strange And so what is gonna be doing some simple trade here? And so let's find the sign data, and that's gonna be wide over 1.5. OK, And that's because here we have worn and one okay, we need to find out what data is equal to and to do that we need. So what we're doing is we need to find the sine function here, okay? And because of that, we do this side and this side is simple tray. Okay. And so we have to over three. Technically, if we will NYSE, you don't have to do that. You can use Internet into calculator. That is totally fine. OK? And so data equals sign um, to me of one, 23 or a member put or 1/1 0.5. Whatever one you want putting calculator, it doesn't matter, and it's gonna evil. Teoh, 41.8 degrees. Okay, so he found the data so now will weaken. Dio is we need to find the tension in the string and the tension that drink is mass times gravity, which is this mass here. And it's gonna be two times. And the co signer dig it up. Um, that's just because we have 12 And here we have 1 20 for the mass, 9.81 meters per second. Squared times two times 41.8 groups I am was forgot. The coastline there they really right co sign at times 41.8. Okay. And you put it onto calculator and you get attention of 78.9 Newton's now, um B is asking us here. Um what at what pregnancy must string between the police, vibrate to form a steaming the wave. Okay, so we have abrasions or the velocity as t equals new in the new Israeli mass densities, we have 78.9 linear Mastin. See, the string is 0.1 square root and we get to 81 meters. Suck it. And now we have our d as me 3/2 terms. Lambda Lambda equals two D over three and R D is two which is given given to us, and that's been equal to 1.33 mirrors Time three and R. G is this guy right? And once cooled down. Now we do the frequency, which is the velocity times La Bamba. When we get to 81 um, area and we get to 80 one meters per second, divided by 1.33 meters and we get to 11 hurts. Right? That's it. Thank you, guys.

Belongs to the chapter wave. And in which we have a way of traveling on a string. Having equation Y equals to 0.0 to sign five X -80. Okay. Where X is in the meter and why is also in the meter? And he's in the second. So for the part of the question we have to calculate the wavelength and frequency of the wave. So by comparing the situation, so this five is equal to angular wave number, so it is equal to five I. Lambda and it is equal to five. So from here we get wavelength lambda equals 25 by five. From here. After solving we get wavelength lambda that is equal to 1.26 m. Okay. And similarly this aid is equal to this Aid is equal to uh frequency. So from here angular frequency, so omega is equal to two pi by two primary club. uh Two primary player by F. So from here we get frequency F. That is equal to omega divided by two pi. So omega is equal to eight here and divide by two pi. So from here we get frequency F equals to 1.2 seven hearts to seven hearts. OK so this is the answer for the lambda and this is the answer for the frequency. Now moving to the option part B. In which we have to calculate its velocity. So velocity V. It is equal to lambda, Multiplied by frequency. Celinda is 1.26 m and frequency is 1.27 hertz. So from here with velocity we comes out to be 1.60 m per second. Okay so this is the answer for the part. We next we have to calculate if the linear mass density of that string. New. It is equal to 0.1 double zero program per meter. We have to calculate the tension T. So we know that very speed. We It is equal to T by under to buy new and whole under oath. So from here attention T comes out to be new multiplayer by we square. So we have new equals to 0.1 and we Which is this value. So 1.60 m per second. Holy square. From here after solving tension T comes out to be 0.256 newton. Okay, so this is the answer for detention. Okay. Mhm.

Mhm This problem covers the concept of the wave on a string. And to solve this problem first, we need to find the length of the rope at as to the block. So the daughter length of the rope is five veto. And the length between the jubilee is two m. So you can see the length of the robot has to, The block on each side is 1.5 m. Now we have to calculate the angle theater. So if we draw a perpendicular on the string attached to the fully, then this land will be one m so we can see the angle theater equals signing was off one meter upon 1.5 m. Or the Angle Theatre comes out to be 41 eight degrees. Now let's show the free body diagram of torture, the forces acting on the objectives, the weight acting vertical downward. That tension force in the string addressed at an angle theater from the vertical. Since the blog is in a Librium, so we can write the summation of all external photos along the right direction is zero from Northern Second Love motion are two times Chico's Theatre equals MG. Are that ancient equals MG upon two goals theater. So for partly the tension in the string equals the moss. Uh there is 12 Kg And to 9.8 May just four seconds square upon two times the cause of forgiven .8 decrease of the tension in the strings comes out to the 79 note. Now party for a string fix at the both ends. The harmonic frequency of an equals and upon to well into square out of the tension in the string upon the linear mass density. Uh huh. And in the previous part we have give a symbol of T. To the ancient. So the tension is T. Okay, so from this we can say the third harmonic frequency have trees 3.2 and into the square root of the tension upon the linear mass density. Now substitute the values of the Total harmonic frequencies three into 2 into balance. two m into square out of 79 Milton upon 0.0010 kg go meet Are the frequency of trees, 2.1 in two and 3 Hotch. So 2.1 into it and there's two hutch. Our 210 Hotch. I think it was.


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