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PROBLIMA (Puuto extral Resolver el siguiente problem [ArR obstener plnto Gxtin Sobre In Dos burras de longituc culificacion clel primer preinl estan colocnclas dce ...

Question

PROBLIMA (Puuto extral Resolver el siguiente problem [ArR obstener plnto Gxtin Sobre In Dos burras de longituc culificacion clel primer preinl estan colocnclas dce tul nuera qut formau HOStCIL " Agulo de Gu" figura. Cadu bnrra colticne tal y €OITIO SC CHKU Q distribuidn uniformemente A lo Inrgo dc longit uc. Cnlculnr CAmp>o eechico Q PHI O colo ncloe distuucin dle unA dc Ins bartns (vcr figura) por CucimaFurn Oborpunto extra dleluriu uolett e pobsleun ecplcto co IuiiCT Cuita

PROBLIMA (Puuto extral Resolver el siguiente problem [ArR obstener plnto Gxtin Sobre In Dos burras de longituc culificacion clel primer preinl estan colocnclas dce tul nuera qut formau HOStCIL " Agulo de Gu" figura. Cadu bnrra colticne tal y €OITIO SC CHKU Q distribuidn uniformemente A lo Inrgo dc longit uc. Cnlculnr CAmp>o eechico Q PHI O colo ncloe distuucin dle unA dc Ins bartns (vcr figura) por Cucima Furn Obor punto extra dleluriu uolett e pobsleun ecplcto co IuiiCT Cuita



Answers

A 7.nSO $_{4}$ solurion is boilcd wirh an NallCO $_{3}$ solution ro producc (a) $7 . n] 1 C O_{3} .7 . n 0$ (b) $7 n(011)_{2}$ (c) $7 \mathrm{nCO}_{3}$ (d) $\angle \mathrm{L} C O_{3} \cdot \mathrm{Na}_{2} \mathrm{SO}_{4}$

In this problem, just look at it carefully. BB I too, will react in pageants of BSE here, too. ECU was to give compound Are we change which aid 80 cl here, which it A d c L. Here? So this is white PPT. They said white PPT. Therefore, according to the option option, age, correct and said for this problem, A d c l a will be the white PPT in this problem.

Is this reaction commentator or district? Later? And what does it stay? A chemistry off the product of it, each in turtles involved into this reaction, it responds toe that enter our image transition stick. To make it on a magic will need to introduce another Lord to Homer, which is achieved by the color tater process. So those two parts the erupted in the same direction. It will bring this Mitchell job up and business or group down. So that's trance relationship. Same reaction under photochemical conditions in this case, it electrons to respond to the on a magic transition state toe. Keep the number off notes. We need to rotate those professions in the upper the directions, which is just prepared to refresher. It will bring Mr Woodroof one up and missile group. Then up it responds to the cysts stood a chemical relationship

In this question we are to simplify the expression that is I can say that W is equals to one of one square root of L. C. And square root of one minus artists were C opponent. Okay, so first of all we're going to take here I'll see him in the square root. So I got here L minus or it's square C divided by L. Okay, now there is a property which says that if we have a square root of em by and then it can give it an f square root of him divided by square root of them. Okay, so I apply this property here so I get here where do l minus R? Square see divided by the square root of L. C into spiral propel. Okay, now that is again property which says that if we have square root of them and then we can write it as square out of them square off in. Okay, So you see we get your square root of l minus. Sorry, square C divided by square. Hotel square would see square root And again. Okay, I can see that we can make product of the square mile square earlier. So they should provide us little l minus. Artists were C divided by square root L It's a square and square root C. No, we have to multiply here with the numerator and denominator. That is where about 60 years. Okay, so you can see that we get here Finally square group of l minus R. E. Square see into Well, I don't see and divided by you know, we have here square of square root. Okay. Means we have here empt and power and truth of a. This provides us a year. So due to this reason we get here L into square assi square off against where you see Police Square. Okay. And then apply this formula year and make product of the terms of enumerated. Because nobody says that if no, they would face death, we can write it as a good baby. Okay, so we see here we got here L minus artist. Percy in to see here and divide by L. C. Okay. Now, further we make product of the terms of enumerators who get Elsie minus artists. Where's his where and divided by L. C. Okay, This is the final simplified expression for the given question here. Thank you.

Yeah, okay. We are going to find the derivative of the dot product between these two vectors and the derivative of the cross product. So first of all, for our dot product we can go ahead and multiply our two tee times t squared, then our t squared times to T. And then our negative five times one to take the derivative. Now we will have a six t squared plus six t squared and then the minus five goes away. So it ends up being a 12 t squared. Okay, so now for our cross product, I like to write out my A I. Js and Ks of course we have to write are you first and then R V Since we're doing the cross product of U. And V. So to do that, remember um for I we're taking that um and we're going criss crossing right? So we have our t squared times one and then that's going to be Multiplied by the -20 T. Now, for RJ we subtract and we have our two tee times one minus R. T square times negative five. So that was also becomes a plus. And then lastly, we hired kind of that cake column and again we look at our two tee times to T. So that's our fourty squared and then we subtract R. T to the fourth. So now we're ready for our derivative and so are derivative of our cross product is going to be two T plus 10 in the I direction And then subtract two plus 10 T in the J direction, and finally A T minus 42 the third in the K direction.


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