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Finol Ike AIc lnjib of TCt) t/2 Aly +hz Foy 0 4 Cn 2 Wfille andejen In 9 naleal numbex...

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Finol Ike AIc lnjib of TCt) t/2 Aly +hz Foy 0 4 Cn 2 Wfille andejen In 9 naleal numbex

Finol Ike AIc lnjib of TCt) t/2 Aly +hz Foy 0 4 Cn 2 Wfille andejen In 9 naleal numbex



Answers

Ilcrc, whire precipirare $\{\mathbb{R})$ obraincd on rrcarment wirh aqucous solurion of $\mathrm{BaCl}_{2}$ is of (a) $\mathrm{AgC}$. (b) $\mathrm{CaCl}_{2}$ (c) $\mathrm{BaSO}_{4}$ (d) $\mathrm{PbC}^{\prime} \mathrm{I}_{2}$

K two Cr awful gives a yellow precipitated it's a yellow policy heated on reaction with on reaction with Be a two plus, as well as B B two plus, therefore, option C and option the uh, correct answer for this problem, Option C and option B. R. Correct answer for this problem.

In this problem I can write the reaction and CST CH two managed to in perchance of action or two 0-5° integrate will give this compound CS three CH 20 H. And this component to denso. PBL three will give CST CH two beyond and this compound in pageants of GCN we'll give CST CH two M. C. And this component presence of AL I am at full well finally give CST CH two NHCS three. This is compounded by this is component so according to the option, option C it correct here, option siege, correct answer.

In this problem, the yellow solution yellow solution, which age I need to see R 04 on reaction will give us yellow PPT and the yellow PPT here. Age B b CR 04. Therefore, according to the option option C. H, correct answer for this problem, Option C. Each correct answer for this problem, I hope you understand the the action of this problem.

So for this 63 9 cancel out to seven. And I just have to subtract the value of the powers if we have the same base. So six minus four is too. So I have r squared three minus two is one. So I've asked the first power, which just s 72 6 Cancel out to 12. The art. There's no Mars on the bottom. So I'm just gonna rewrite that as squared minus over s as times as over s cancel them out. We're left with one s. So then you can see that this and this are the same. So we just have to work with the coefficients. So seven minus 12 is negative five, and I just have to tack on that.


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