5

4. Given I(x) =xz 4x +5. Find [rth-IS)...

Question

4. Given I(x) =xz 4x +5. Find [rth-IS)

4. Given I(x) =xz 4x +5. Find [rth-IS)



Answers

Solve. $$\frac{4 x}{x-4}+5=\frac{5 x}{x-4}$$

To solitary X plus four y equals six. Let's add the leper inside because they're like Tom's. Like can be added three X plus four X, which equal to seven. X equal to six. Now we can multiply by the reciprocal officer one, which is one way 77 x into one by seven equals six into one by seven. So this is multiplication multiplication Principal seven and symbol will cancel X equal to 67 using simplification. Simplifying. We'll get the answer. No, we need to check whether our answer is correct. So just substitute x record of success ever In the given question The given question is this stuff suit, this is three x less poor X equal six No, we need toe. Uh, substitute just three times six white, seven less four time six. Right. Seven. The school six. Normal to play a left inside 18 by a seven plus 24 by seven which will do six. No in particular prince size. This is 47 numeraries two and pork political 267 Success for Taito six equals six. So here are it is killer that X equal to six by seven is a correct answer for answer this X equal to six white. So? So this is our answer

Cross multiplying. We have five x princes. Expose five and we have nine parentheses for X plus four. Simple. Fine. We get AKs equals 20.

Let's solve this equation for X. Now, before we begin, we have to determine what values X cannot have. That is what values would make these denominators equal to zero. So we just have to set them equals zero in the solve for X and right here. By adding Ford, both sides we get well, X is going to be equal to positive four. Meaning X equals four is an unacceptable answer. The only unacceptable answer. And if we get X equals four, well, we can't allow that to be a solution now. Anyways, with that out of the way, let's begin solving. So we have to multiply by the lowest common denominator, which is X minus four. So we multiply both sides by X minus four and then on the left, the denominators cancel, leaving us with X on the right and the first term that denominators cancel, leaving us with four and then in the second term. Well, there's nothing to cancel with, so we distribute the four to get four X minus four times four is 16 then combining like terms gives X equals four X minus 12. We can subtract a four x from both sides to get negative. Three X equals negative 12 and finally solve for X by dividing both sides by negative three, which gives X equals four. So that's our answer, right? Well, not really, because we said that's an unacceptable answer. That's the only number which X is never allowed to be, because it would make us divide by zero. Therefore, since that's the only solution we got, but it's also not allowed as a solution, there is no solution. Our solution set is just the empty set.

We need to solve the following. So we're going to take the absolute value sign and have X -4 equals X -5. And then we have X -4 is equal to negative times the quantity X -5. So our first one when we subtract X that gets resolved are variable and we have negative four is equal to negative five. So that doesn't give us anything. So the next one we distribute our negative sign, we get negative X plus five, so we add X to both sides, We get two, X -4 is equal to five, we add forward to both sides and we get two, X is equal to nine, We divide by two And we get X is equal to 9/2. But if we take nine haves and plug it back in nine House -4. So nine half minus four comes out to be one half and the absolute value of one half is one half. And then nine halves -5 is negative one half. So this doesn't work. So this has no solution.


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