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DIIIMdiT7tTro point charges 3 pC (left) and LC (right) separated by distance of 30 cm. third change = 4C is placed between them = show: force exerted by 91 on Jo i...

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DIIIMdiT7tTro point charges 3 pC (left) and LC (right) separated by distance of 30 cm. third change = 4C is placed between them = show: force exerted by 91 on Jo i 10.8 N,and the force exerted by Gz on Ja is 1.8 N What is the net electrostatic force acting on %o?H10an1 N10 cm -20 cm =A9Nto the right 8.10.8 N the right 21.8Nto the lelt D12-0 the rightQUESTION 11What Ihe electric field location 42.25 * 10 (to the left) 3,0* 10*N/ (to the left)the oter tto CharkeDretiou problemtc2,25 * 10'N;

DIIIMdiT7t Tro point charges 3 pC (left) and LC (right) separated by distance of 30 cm. third change = 4C is placed between them = show: force exerted by 91 on Jo i 10.8 N,and the force exerted by Gz on Ja is 1.8 N What is the net electrostatic force acting on %o? H10an 1 N 10 cm - 20 cm = A9Nto the right 8.10.8 N the right 21.8Nto the lelt D12-0 the right QUESTION 11 What Ihe electric field location 42.25 * 10 (to the left) 3,0* 10*N/ (to the left) the oter tto Charke Dretiou problemt c2,25 * 10'N; (to the right) 475*C XC (to the right} charke



Answers

Charge $q_{1}=1.4 \cdot 10^{-8} \mathrm{C}$ is placed at the origin. Charges $q_{2}=-1.8 \cdot 10^{-8} \mathrm{C}$ and $q_{3}=2.1 \cdot 10^{-8} \mathrm{C}$ are placed at points $(0.18 \mathrm{~m}, 0 \mathrm{~m})$ and $(0 \mathrm{~m}, 0.24 \mathrm{~m}),$ respec- tively, as shown in the figure. Determine the net electrostatic force (magnitude and direction) on charge $q_{3}$

Hi In this given problem there are three charged particles or linearly please. The first one positive charge particle having a charge. People on zero My Curriculum. Then at a distance of 20 cm there is another charge which is a negative charge -5.0 microbial. Um Then again At a distance of this, first distance was 20 cm and the second one is 30 centimeters and discharge here this is again a positive charge And it is having a magnitude of 810 Micro Cola. No, there are two forces experienced by this middle charge, both hard proactive. So first of all this is the force experienced by this middle charge. Due to this three Micro column starts we may represented by F E. Three electrostatic force due to the charge of three micro cola magnitude. Similarly here this is also electrostatic force F. E. But that is due to eight my curriculum charts which is symbolized by F. EA. So the net force experienced by five Micro Column Chart that is that will be given by F E mm minus F. E. Me. And using Ghulam slow this FE eight will be given by K into By Micro Cola means 5-10 for -6 column into eight In 2, 10 days par -6 column divided by distance between them. That is 30 centimetre means 0.3 sq and minus key. Again. This is 5 to 10 days par minus six colon, multiplied by three in 2, 10 for minus six column divided by the distance between them Which is 20 centim or 0.2 m. So here This game means nine in 2, can be taken out as a common along with why and and the par minus will leaving behind 850.09 -3 x 0.04. Well, finally, It will come out to be 45 into standish par -3 bracket 58.9 -75 newton. Finally, this force comes out to be 0.6 two five newton, which is the answer for this given problem. And this net force is words 810 Micropal. Um charge. Thank you.

Hi, friends. This is the problem. Baseball columns? No. In better form networks on Cuba. Good to be after. What? Unless f 23 plus I have to force it is to be back tradition. After what? Good week. Okay, Q Q d square. Jacob. Yeah, that is minus chicken. Force on to duty three repulsive force. So this could be Martin cape the chip Treat you is where? Minus I camp Force on cue to do to q four. Okay, good job. Food you upon rue de square direction If you see and community in this direction after 21 Just been weak if. Okay, 23 And that will be after four so it can be resolved in the two component minus cost. 45 I kept. Let's sign 45 j. Kevin. So you can write K. He was square by the square to be common. You will get minus two J cap minus six. I camp Mhm. My goodness. Eight by two. Yeah, One upon route, I kept notes. Eight right to one. Upon which Jacob So I'll simplifying it. This post could be recognized My next 4.2. Okay. +139 Jacob nutrition, you can give its magnitude as well as direction. So magnitude of net force on YouTube having the Meadows route off minus port while to square +139 square so it would be equal to four point to new trip. And it's the direction with me theater to return and worse off by component upon X component that is 10 and worse of while 39 divided by So you will get minus 5.4 degrees plus variety. Second is to me 1 74.60. That's all thanks for budging it.

Following arrangement of the charges. This is our X. Axis. And here is charged Cuban which is placed at the origin. And we have another charge Q two which is placed at a distance X equals to eight centimeters. Okay we build notice letter and we have to stay Place another charge Q three on the X. Axis so that it will have nature's net force on it equals to jail. So let us suppose this distance from the origin is X. Okay. No as for the question, the distance from the origin of charge Q two is eight centimeters. So 8.0 centimeter expert question. Okay and Cuban charge is equal to 6.0 micro column and Q two charges equals two minus 3.0 micro column. Okay now the electrostatic force due to Q two on this beauty will be in the let us suppose these charges positive. So it will be in this left direction. So call it F. One. And due to force uh due to charge Cuban. the force on Q three. This will be in the right side direction because this charges taken positive and this is also positive. So this is a force F two. Okay, so to have net force on charge Q three equals to zero. So we must have F one equals two. F. Okay, so substituting formula for them, the electrostatic force F one between charge Q three and Q two. It will be given by Q two. Q three divided by separation between them. And it will be this separation uh Total distance from here to here is X. So it will These regions will be D and they will be given by X -8cm. Okay, so X -8. Okay, so holy square we are taking it into centimeters. So can we can obtain this X in the centimeter also. Okay, but to convert it into meters so we can use here 10 to the power minus four m square. Okay, this is equals to have to the force between Q three and Cuban. So it will be equals two Cuban. Q three divided by separation. X square. Okay. Into 10 to the power minus four to convert it into meters. So now substituting values here. So we get cable counselor from each And the Q three will also cancel out. So Q two which is equal to three, multiplied by 10 to the power minus six divided by X minus eight. Holy square This is equal to Cuban which is six into 10 to the power minus six divided by X. Is where they stand to. The power minus four will also cancel out from each side. Okay, so from here, after solving we get X equals to 19 0.19 m. Or from here we can write that ax equals 2 19 cm. Okay, so from the given options option is the correct answer. Okay, so this is the answer for the question. Okay, X equals 2 19 centimeter uh, is the location where killed creatures should be placed so that net force on it will be zero.

Hello. So the question is from electrostatic given that charge Cuban is placed at a region. So if we draw a line So Q one is placed at origin. Okay. And it's coding it out 00 and other charge Q. Two and Q. Three hour placed it given it you to to all placed it You .1 Age. You intend to the power -8. No Q. To charge. Yes Please stay. And to your .1 and two. So that place is 0.1800. And the charges Q. two. Let me like the magnitude of you going to do to you also. And third charges placed it The U. n. Let us this is the point zero and your .24. And this is guilty. Now the values of Cuban to Cuban is 1.4 into 10. to the power -8. She was too -1.8 into 10. to the power minus eight column and 2 3 is equal to 2.1 into 10. to the power -8 column. Okay now we need to evaluate the value of electrostatic falls on charge. Beauty falls on this charge. So you two is negative so its forces inward and Cuban is positive. So it's false is outward. So this is false on three due to two and this value is false on three due to one. Okay, so let me evaluate the value of after even that is equal to one x 4 by absolute note into mhm. You went you three over All 1. 3 sq In two direction is J. Okay it means positive by access and after they do in the similar ways. Take me like this then I will substitute these values one by four by capsule. A note Q two Q three Over all, 2, 3 square. And the direction is along exits direction is 0.180. and Y it may like you need director you need to factor out to trees. 0.180 into I. Okay minus zero point to fall into. J. Mhm. Divided by squared 0.18 sq plus 0.24 square. Okay, so the value of our +23 unit vector is equal to. Yeah, let me evaluate the value of this unit vectors. Mhm Yeah Square with 0.18 sq 0.18 square plus 0.24 square. Okay, so uh that is taking the reciprocal of it? Multiply 0.18 So that is 0.6 into I Okay minus 0.8 & two. In the similar way we can evaluate the value of our two to you. Also Our 2 3 is equal to Do you .1 age square Plus 0.24 sq. So that will be zero 09 That is our 23 square 0.9 m script. Okay. And I won three. Let me evaluate the value of 13 So when three is okay This is a region and 0.24 sq 0.24 m2 square. Okay. These are the values of our penalty and now it is the time to substitute these falls. Sonett folks will be, let me value it. Victor F. That is victor F. 31 plus F 32 So after everyone is Taking one x 4 by actually not woman. And the country is also woman. They love to trees. 2.1 into 10. To the Power -8. and inside it. So one is 1.4 entertain to the power -8 divided by I want this you're going to fall square and in their direction, J plus you two minus that is already compensated in that direction. 1.18 to 10 to the power minus eight, Divided by 0.09 in two unit rectories. 0.6 I minus 0.8 G. 0.6 i -0.8 G. Okay so let me evaluate the value of this force. So they will be equal to mhm Firstly first x component is 99 into 2.1 E minus eight. X. component I it component multiply 1.80 -8. Do I did by 0.09. Multiply 0.6. So that will be 2.268 to 10 to the power minus five into I Newton. Now the jet component is let me check whether it would be positive will never do. Okay, So that will be 1.4 E minus a. Divided by zero point in your car. Scream minus 1.8. D minus eight. Yeah, divided by multiply biased. You appointed Do I did by 0.09. Multiply 99. 32.1 a minus eight. So that will be one plus 1.56975 into 10. To the power minus five G. This is basically in the vector from now, we need to evaluate the magnitude and direction on charge. Beauty. So magnitude. If we take it victor F magnitude is equal to that's right Plus 2.268 E -5 squared to the power. So magnitude is 2.7 six into tend to the Powerball -5 Newton. And direction is F. Y. Or what fx In general in the world is equal to In the vector from this is this, this is victor F and the magnitude is 2.7, 16 to £20 minus five, and direction is f Y. S 1.569. So do I did buy 2.268, So that will be 34 .7° with respect to the positive x axis. This is like this 34.7 Degree, and this is what this is F F X. This is their flight. So these are the required themselves. So hold this closure.


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